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大小:2.28 MB
页数:63页
时间:2020-04-05
《世纪金榜2013高三复习答案.ppt》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、第一节集合Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.完全与教材同步,主干知识精心提炼。素质和能力源于基础,基础知识是耕作“半亩方塘”的工具。视角从【考纲点击】中切入,思维从【考点梳理】中拓展
2、,智慧从【即时应用】中升华。科学的训练式梳理峰回路转,别有洞天。去尽情畅游吧,它会带你走进不一样的精彩!Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.内容要求ABC集合及其表示√子集√交集、并集
3、、补集√…………三年4考高考指数:★★★★★Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.确定性互异性无序性∈Evaluationonly.CreatedwithAspose.Slidesfor
4、.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.(3)常见集合的符号NN*或N+ZQR自然数集正整数集整数集有理数集实数集Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright
5、2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.(4)集合的表示方法①__________②__________③____________列举法描述法Venn图法Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePt
6、yLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.【即时应用】(1)判断下列结论是否正确(在后面的括号内填“√”或“×”):①Z={全体整数}()②R={实数集}={R}()③{(1,2)}={1,2}()④{1,2}={2,1}()(2)若集合A={1,a2},则实数a不能取的值为________.Evaluationonly.CreatedwithAspose.Slidesfor.N
7、ET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.【解析】(1)①不正确,正确写法为Z={整数};②不正确,正确写法为R={实数};而{R}表示以实数集为元素的集合;③不正确,集合{(1,2)}表示元素为点(1,2)的点的集合,而{1,2}则表示元素为数1,2的数的集合,它们是不相等的
8、;④正确,根据集合中元素的无序性可知{1,2}={2,1}.(2)由a2≠1,得a≠±1.答案:(1)①×②×③×④√(2)±1Eval
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