电路分析课后习题第7章答案2010年整理.ppt

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1、求图题7-1所示电路中电流表A1,A2读数，已知：Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.2.已知两个串联元件上的电压分别为试用相量法求电压解：Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.3.已知某二端元件的电压、电流采用的是关联参考方向，若其电压、电流的

2、瞬时值表示式分别为(1)(2)(3)试判断每种情况下二端元件分别是什么元件？解：u3与i3同相,所以为电阻Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.5.图题所示电路，各电压表的读数分别为：V1表读数为20V，V2表读数为40V，V3表读数为100V，求V表读数；若维持V1表读数不变，而把电源频率提高一倍，V表读数又为多少？解：设：Evaluationonly.CreatedwithAspose.Slidesfor

3、.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.电源频率提高一倍时，端口电流不变，则V2表读数应变为20V；V3表读数应变为200V，所以5.图题所示电路，各电压表的读数分别为：V1表读数为20V，V2表读数为40V，V3表读数为100V，求V表读数；若维持V1表读数不变，而把电源频率提高一倍，V表读数又为多少？解：设：Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011Aspo

4、sePtyLtd.6.由R、L、C串联组成的单口网络，端口电压和电流为关联参考方向，已知端口电压和电流分别为V，A，XC=-20Ω，求R、L、C的值。解：Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.7.图题7-7所示电路，已知U=220V，，求I1、I2、I。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright

5、2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.8.图题7-8所示电路，已知Y1=（0.3–j0.4）S，Z2=（2–j5）Ω，Y3=（0.25–j0.25）S，Y4=（0.2–j0.2）S。求电路的等效阻抗Zab。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright20

6、04-2011AsposePtyLtd.10.求图示电路中各未知电压、电流的有效值。(a)(b)(c)(d)Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.11.已知I1=5A，I2=4A，XC=-12.5Ω,U=100

7、V，且与同相位，求R、RL、XL。R=16.7Ω、RL=6Ω、XL=8ΩEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.设端口电压Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.13.图题所示电路，用网孔分析法求电流。Evaluatio