4、有多少余量:顶层空间距离-(A+0.035v2)-对重缓冲器行程①1.367-0.207-0.273=0.887(m)②1.827-1.107-0.273=0.447(m)③a 1.107-0.407-0.273=0.427(m) b 0.957-0.207-0.273=0.477(m) 上述4个数据取最小值0.427m(2)计算满足标准要求,对重导轨制导行程的有多少余量:底层平层时对重至导轨顶距离-(0.1+0.035v2)-轿厢缓冲器行程-轿厢撞板与缓冲器项面间距+对重撞板与缓冲器顶面间距④0.907-0.207-0.273-0.400+0.340=0.367(m)