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时间:2020-03-10
《GMAT数学考试中余数精讲.doc》由会员上传分享,免费在线阅读,更多相关内容在工程资料-天天文库。
1、Introduction (赶时间的童鞋可以略过。。。只是一些概念帮助童鞋们回忆余数~~~)DefinitionIfxandyarepositiveintegers,thereexistuniqueintegersqandr,calledthequotientandremainder,respectively,suchthaty=divisor*quotient+remainder=xq+r;and0<=r2、ince15=6*2+3.Noticethat0<=r3、enasmallerintegerisdividedbyalargerinteger,thequotientis0andtheremainderisthesmallerinteger.Forexample,7dividedby11hasthequotient0andtheremainder7since7=11*0+7Thepossibleremainderswhenpositiveintegeryisdividedbypositiveintegerxcanrangefrom0tox-1.Forexample,possibleremaind4、erswhenpositiveintegeryisdividedby5canrangefrom0(whenyisamultipleof5)to4(whenyisonelessthanamultipleof5).Ifanumberisdividedby10,itsremainderisthelastdigitofthatnumber.Ifitisdividedby100thentheremainderisthelasttwodigitsandsoon.Forexample,123dividedby10hastheremainder3and15、23dividedby100hastheremainderof23.1. CollectionofMethodsMethod1:小数法(妹纸自己取的名字,包括后面的方法也都是妹纸取的~欢迎讨论)AwaythattheGMATwilltestremaindersiswhatyouwouldtypicallyjustdividebackintotheproblemtodeterminethedecimals:25/4=6remainder1Dividethat1backby4toget0.25,sotheansweris6.25.Anynu6、mberwitharemaindercouldbeexpressedasadecimal.Theremainderprovidesthedataafterthedecimalpoint,andthequotientgivesyouthenumbertotheleftofthedecimalpoint.Considerthisproblem(whichappearscourtesyofGMAC):Example: Whenpositiveintegerxisdividedbypositiveintegery,theremainderis9.7、Ifx/y=96.12,whatisthevalueofy?(A)96 (B)75 (C)48 (D)25 (E)12Sol:Goingbacktotheconceptoftheremainder,theremainderof9iswhatwillgiveusthat0.12afterthedecimalplace.Theanswertothedivisionproblemx/yiseither:96remainder9Or96.12Therefore,whentheremainderof9isdividedbackove8、ry,weget0.12.Mathematically,thismeansthat:9/y=0.120.12y=912y=900y=900/12y=300/4y= 75Thecorrectan
2、ince15=6*2+3.Noticethat0<=r3、enasmallerintegerisdividedbyalargerinteger,thequotientis0andtheremainderisthesmallerinteger.Forexample,7dividedby11hasthequotient0andtheremainder7since7=11*0+7Thepossibleremainderswhenpositiveintegeryisdividedbypositiveintegerxcanrangefrom0tox-1.Forexample,possibleremaind4、erswhenpositiveintegeryisdividedby5canrangefrom0(whenyisamultipleof5)to4(whenyisonelessthanamultipleof5).Ifanumberisdividedby10,itsremainderisthelastdigitofthatnumber.Ifitisdividedby100thentheremainderisthelasttwodigitsandsoon.Forexample,123dividedby10hastheremainder3and15、23dividedby100hastheremainderof23.1. CollectionofMethodsMethod1:小数法(妹纸自己取的名字,包括后面的方法也都是妹纸取的~欢迎讨论)AwaythattheGMATwilltestremaindersiswhatyouwouldtypicallyjustdividebackintotheproblemtodeterminethedecimals:25/4=6remainder1Dividethat1backby4toget0.25,sotheansweris6.25.Anynu6、mberwitharemaindercouldbeexpressedasadecimal.Theremainderprovidesthedataafterthedecimalpoint,andthequotientgivesyouthenumbertotheleftofthedecimalpoint.Considerthisproblem(whichappearscourtesyofGMAC):Example: Whenpositiveintegerxisdividedbypositiveintegery,theremainderis9.7、Ifx/y=96.12,whatisthevalueofy?(A)96 (B)75 (C)48 (D)25 (E)12Sol:Goingbacktotheconceptoftheremainder,theremainderof9iswhatwillgiveusthat0.12afterthedecimalplace.Theanswertothedivisionproblemx/yiseither:96remainder9Or96.12Therefore,whentheremainderof9isdividedbackove8、ry,weget0.12.Mathematically,thismeansthat:9/y=0.120.12y=912y=900y=900/12y=300/4y= 75Thecorrectan
3、enasmallerintegerisdividedbyalargerinteger,thequotientis0andtheremainderisthesmallerinteger.Forexample,7dividedby11hasthequotient0andtheremainder7since7=11*0+7Thepossibleremainderswhenpositiveintegeryisdividedbypositiveintegerxcanrangefrom0tox-1.Forexample,possibleremaind
4、erswhenpositiveintegeryisdividedby5canrangefrom0(whenyisamultipleof5)to4(whenyisonelessthanamultipleof5).Ifanumberisdividedby10,itsremainderisthelastdigitofthatnumber.Ifitisdividedby100thentheremainderisthelasttwodigitsandsoon.Forexample,123dividedby10hastheremainder3and1
5、23dividedby100hastheremainderof23.1. CollectionofMethodsMethod1:小数法(妹纸自己取的名字,包括后面的方法也都是妹纸取的~欢迎讨论)AwaythattheGMATwilltestremaindersiswhatyouwouldtypicallyjustdividebackintotheproblemtodeterminethedecimals:25/4=6remainder1Dividethat1backby4toget0.25,sotheansweris6.25.Anynu
6、mberwitharemaindercouldbeexpressedasadecimal.Theremainderprovidesthedataafterthedecimalpoint,andthequotientgivesyouthenumbertotheleftofthedecimalpoint.Considerthisproblem(whichappearscourtesyofGMAC):Example: Whenpositiveintegerxisdividedbypositiveintegery,theremainderis9.
7、Ifx/y=96.12,whatisthevalueofy?(A)96 (B)75 (C)48 (D)25 (E)12Sol:Goingbacktotheconceptoftheremainder,theremainderof9iswhatwillgiveusthat0.12afterthedecimalplace.Theanswertothedivisionproblemx/yiseither:96remainder9Or96.12Therefore,whentheremainderof9isdividedbackove
8、ry,weget0.12.Mathematically,thismeansthat:9/y=0.120.12y=912y=900y=900/12y=300/4y= 75Thecorrectan
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