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1、环形变压器的设讨ThedesignoftheringtransformeriscalculatedBydesigningapowertransformerfora50Hzquartzlamp,ItsprimaryvoltageU1=220V,secondaryvoltageU2=11.8V,secondarycurrent12=16.7A,voltageregulationAU7%orless,toillustratethemethodsandstepsofcalculation.1)calculatethesecondarypowerofthetransformer.2
2、)computetransformerinputpowerPl(settransformerefficiencyeta=0.95)andinputcurrentIIIntheformula:K一thecoefficientrelatestothepowerofthetransformer・K二0.6%一0.8,andK二0.75.Accordingtotheexistingironcoresize,thesizeoftheironcoreis:highH=40mm,theinnerdiameterDno=55mm,andtheoutsidediameterDwo=110m
3、m・Formula:f-powerfrequency(Hz)・B一一fluxdensity(T),B-1.4T.N2二N20dotU2二3.23times11.8=38.1turns,andN2=38turns・6)selectthewirediameterwindingconductorwirediameterd(10)calculationtype:I-thecurrent(A)throughtheconductor・J一currentdensity,j=2.5~3A/mm2.Whentakingj=2.5A/mm2timesentry(10),twod=2.12mm
4、(consideringthemaximumsizeoftheinsulatedpaintis2.21mm)wireandwinding.Because①cross-sectionalareaofthewireSd2=6.78was2・94,andd=2.12mmwirecross-sectionalareawas3.53aftertwoparallelDEsectionalareafor:2*3.53=3.53was,andmarginisbiggerthataccordswitharequirementcompletely.6ringtransformerstruct
5、ureofringtransformerwindingsiscalculatedusingthewindingringrotationmovementinacoreandwinding,sothesizeofthecorediameterisveryimportantformachiningprocess,thepurposeofstructuralcalculationisroundalltheinspectionafterwinding,innerdiameterishowmuchspace・Iftheinnerdiameteristoosmalltomeetther
6、equirementofwinding,thesizeoftheironcorecanbemodified,soaslongasthecross-sectionalarearemainsthesame,theelectricalperformancewillbethesame・KnownironcoreinnerdiameterDno二55mm,theinsulationlayerthicknessinfigure7isto=1.5mm,tl=t2=1mm・1)afteraroundtheprimarywindingandtheinsulatedinnerDn2calcu
7、lationofprimarywindingineachlayeraroundthenumberofturnsofnltype:Dnlpackage-coreinsulationdiameter,Dnl二tODno-2二55-(2x1.5)二52mm;KP--thefoldingcoefficient,KP二1.15.ThelayerofprimarywindingisthethicknessoftheprimarywindingSecondarywindingsofthethicknessofthedelta22)tocal
