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1、洗衣粉去污功效研究的思路去污效能的综合函数指标F设人表示第i种主成分的特征向量，则有：A=[AM2^3；A4];Ai=[0.16,0.2,0.25,0.25,0.24,0.15,0.24,0.24,0.25,0.27,0.26,0.270.29,0.29,0.14,0」6,0.26,0.23]；A2=[0.37,-0.23,-0.23,0.24,0.3,0.37,-0.26,-0.26,0.25,0.17,0.19,0.19-0.12,-0.14,・0」4,01&・0.19,-0.24]；A3=(0.1,-0.36,-0.31,0」4,0.
2、04,・0」,-0.24,-0」5,0」4,016,018■0」,0.09,0.06,0.49,0.51,0.11,0.23J；幻=[0.25,0.33,0.15,0.12,0.06,0.35,0.15,0.12,0.02,・0.25,032-0.27,-0.1,-0.09,0.53,-0.2,-0.04,-0.26]o设w表示去污功效标准化矩阵(数据见附件)，W：(、Cl\…aW=:•.:,n=l,2,...,18；加二1,2,...,86厲]…amn>其屮如表示第rn种产品对第n种污渍的去污功效标准值。设尺表示第，种主成分的不同产
3、品的标准值矩阵，则有：斥,匸1,2,3,4设第i种主成分的贡献率为口，则有：7?=[53.885%,22.795%,6.511%,5.769%]，上1,2,3,4设第m种产品的去污效能的综合函数指标为£”令F为不同产品的去污效能的综合函数指标矩阵，则有：4F=^Fix77.,z=I,2,...,4z=i终上所述，可得去污效能的综合评定值一般模型为：F=WxArx?1产品溶液属性综合指标Q：设乩'表示第£种属性的特征向量，则有：B二力1；82；6；艮；跖；5=[0.23,009,009,0.14,0.1,0.15,0.18,0.21,0.22
4、,0.18,0.24,0.250.13,0.26,0.26,0.24,0.25,0.28,0.24,0.31,0.3];B2=[-O.l8,0.44,-0.18,0.51,0.53,0.1,0.03,0.23,0.020,-0.050.05,0.040.05,0.1,・0」7,01&・0.13,・0」8,0,-0.04];B3=[-0.09,0」3,0」,0.05,0.07,-0.25,-0.21,-0.26,-0.32,0.52,0.07,0.060.59,0.06,0.01,0」4,0.03,0,0.11,-0.08,-0.12];B4
5、=[-0.03,-0.26,0.65,0.2,0.26,0.32,0.25,-0.01,-0.02,0.01,-0.28,-0.230.11,-0.13,-0.1,0.18,-0.13,0.03,0.16,-0.02,0.04];B5=[-0.07,0.33,-035,-0.11,-0.13,0.38,-0.2,0.05,0.1,0.01,-0.3,0.040.08,-0.34,-0.23,0.38,-0.09,0.11,0.32,0.02,0.03]。设G表示产品溶液属性标准化矩阵（数据见附件），HU：/、a\…ajG=:•.:,j=
6、l;m=1,2,---,86宀川…為丿其中尙"表示第m种产品对第J种溶液属性的标准值。设0表示第k种主成分的不同产品的标准值矩阵，则有：Q严GxBj,&1,2,3,4,5设第£种主成分的贡献率为灯，则有：g=142.596%,11.784%,9.253%,6.673%,6.528%],k二1,2,...,5设第m种产品溶液属性的综合函数指标为Q”，令Q为不同产品的溶液属性的综合函数指标矩阵，则有：5Q=工Qkx即‘1,2,...,5k=l终上所述，可得溶液属性的综合评定值一般模型为：Q=GxBtx^运行程序：clc;clear;w=xlsr
7、ead('属性特征向量.xls'/sheetl7F2:Z87f);w1=w;notanumber=-isnan(w);uO=all(notanumbert),;w=w(uO,:);%特征向量Bl=[0.23-0.09-0.090.140.10」50」80.210.220.180.240.250.130.260.260.240.250.280.240.310.3];%特征向量B2=l-0.180.44-0.180.510.530.10.030.230.02-0.050.050.040.050.1-0.17018-0.13-0.180-0.04
8、];%特征向量B3=[-0.090.130.10.050.07■0.25-0.21-0.26-0.320.520.070.060.590.060.010.140.0300.11-
