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时间:2019-08-29
《高二数学(文科)参答》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、凉山州2018—2019学年度上期期末检测高二数学(文科)参考答案一、选择题1.C2.D3.A4.B5.D6.A7.B8.C9.C10.D11.B12.C二、填空题3n213."nÎN,n£314.3515.16.12三、解答题17.解(1)Q直线m:2x+y+1=0直线m的斜率k=-2Qm//n直线n的斜率k=-2............................................2分又Qn过点P(-1,2)y-2=-2(x+1)............................
2、.......................4分即y=-2x.................................................................5分(2)由题意得直线n的斜率k=-4,且n过点P(-1,2)y-2=-4(x+1).................................................................9分即4x+y+2=0............................................
3、.........................10分18.解(1)由题意可得:(a+0.03+0.04+0.02+a)´10=1解得:a=0.005...........................................................................................3分设中位数为m(704、.................................................8分(2)成绩达到优良的人数:(0.02+0.005)´10´60=15(人)............12分2219.解:Q圆C:x+y+4y+3=022(x+2)+y=1圆心C(-2,0),半径r=1.................................................................2分高二数学(文科)参答第1页共4页(1)弦长AB取得最大值时,AB为圆的直径则圆心5、C在直线上又因为P(2,3)在直线l上y-30-3=x-2-2-2直线l的方程为:3x-4y+6=0.........................................................6分(2)QCP=5MP=CP+r=6,MP=CP-r=4maxmin...........................................10分MPÎ[4,6]...........................................................6、..........................................12分20.解:(1)PA=(-2-x,-y),PB=(3-x,-y)222PA×PB=x-x-6+y=x-62即:y=x......................................................................5分点P的轨迹为焦点在x轴,开口向右的抛物线.........6分11(2)由题意可得:y=±带入方程求得x=MM24.........................7、..............8分p111MF=x+=+=M2442.....................................................................12分22xy21.(1)设双曲线C:-=1(a>0,b>0)22ab由题意可得:c=2,2b=2222b=1,a=c-b=32x2-y=13...................................................................................8、.....................6分(2)设直线l与曲线c与右只的两交点为A,B且A(x,y)B(x,y)1122ìy=kx+2ï联立íx22ï-y=1î3高二数学(文科)参答第2页共4页2消y:(1-3k)-62kx-9=0.....................................................................
4、.................................................8分(2)成绩达到优良的人数:(0.02+0.005)´10´60=15(人)............12分2219.解:Q圆C:x+y+4y+3=022(x+2)+y=1圆心C(-2,0),半径r=1.................................................................2分高二数学(文科)参答第1页共4页(1)弦长AB取得最大值时,AB为圆的直径则圆心
5、C在直线上又因为P(2,3)在直线l上y-30-3=x-2-2-2直线l的方程为:3x-4y+6=0.........................................................6分(2)QCP=5MP=CP+r=6,MP=CP-r=4maxmin...........................................10分MPÎ[4,6]...........................................................
6、..........................................12分20.解:(1)PA=(-2-x,-y),PB=(3-x,-y)222PA×PB=x-x-6+y=x-62即:y=x......................................................................5分点P的轨迹为焦点在x轴,开口向右的抛物线.........6分11(2)由题意可得:y=±带入方程求得x=MM24.........................
7、..............8分p111MF=x+=+=M2442.....................................................................12分22xy21.(1)设双曲线C:-=1(a>0,b>0)22ab由题意可得:c=2,2b=2222b=1,a=c-b=32x2-y=13...................................................................................
8、.....................6分(2)设直线l与曲线c与右只的两交点为A,B且A(x,y)B(x,y)1122ìy=kx+2ï联立íx22ï-y=1î3高二数学(文科)参答第2页共4页2消y:(1-3k)-62kx-9=0.....................................................................
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