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ID:41010006
大小:3.61 MB
页数:22页
时间:2019-08-13
《丙烷Hyperchem程序应用》由会员上传分享,免费在线阅读,更多相关内容在工程资料-天天文库。
1、Hyperchem程序应用——丙烷画分子图模型加氢应用半经验方法CNDO方法进行优化选用从头计算方法选用3-21G机组计算单点计算显示C-H键长显示原子电荷显示键角分子性质球棒模型丙烷分子三维静电势图丙烷分子等值面图丙烷分子总电荷密度图(二维)丙烷分子总电荷密度图(三维)分子轨道图-最高占据轨道二维图分子轨道图-最高占据轨道三维图分子轨道图-最低空轨道二维图分子轨道图-最低空轨道三维图计算输出结果:HyperChemlogstart--FriDec1022:08:072010.Geometryoptimization,SemiEmpirical,molecule=(unt
2、itled).CNDOFletcherReevesoptimizerConvergencelimit=0.0001000Iterationlimit=50Accelerateconvergence=YESOptimizationalgorithm=Fletcher-ReevesCriterionofRMSgradient=0.1000kcal/(Amol)Maximumcycles=165RHFCalculation:SingletstatecalculationNumberofelectrons=20NumberofDoubleOccupiedLevels=10Char
3、geontheSystem=0TotalOrbitals=20StartingCNDOcalculationwith20orbitalsE=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=1Diff=6390.11437]E=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=2Diff=3.56562]E=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=3Diff=0.20884]E=0.0000Grad=0.000Conv=NO(0cycles0p
4、oints)[Iter=4Diff=0.01454]E=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=5Diff=0.00011]E=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=6Diff=0.00001]E=-2442.5051Grad=68.601Conv=NO(0cycles1points)[Iter=1Diff=39.62238]E=-2442.5051Grad=68.601Conv=NO(0cycles1points)[Iter=2Diff=3.05992]E=-2442.
5、5051Grad=68.601Conv=NO(0cycles1points)[Iter=3Diff=0.26156]E=-2442.5051Grad=68.601Conv=NO(0cycles1points)[Iter=4Diff=0.02816]E=-2442.5051Grad=68.601Conv=NO(0cycles1points)[Iter=5Diff=0.00035]E=-2442.5051Grad=68.601Conv=NO(0cycles1points)[Iter=6Diff=0.00001]E=-2417.0471Grad=118.207Conv=NO(0
6、cycles2points)[Iter=1Diff=15.43150]E=-2417.0471Grad=118.207Conv=NO(0cycles2points)[Iter=2Diff=1.15472]E=-2417.0471Grad=118.207Conv=NO(0cycles2points)[Iter=3Diff=0.09506]E=-2417.0471Grad=118.207Conv=NO(0cycles2points)[Iter=4Diff=0.00984]E=-2417.0471Grad=118.207Conv=NO(0cycles2points)[Iter=
7、5Diff=0.00013]E=-2417.0471Grad=118.207Conv=NO(0cycles2points)[Iter=6Diff=0.00000]E=-2460.3787Grad=5.568Conv=NO(1cycles3points)[Iter=1Diff=0.02313]E=-2460.3787Grad=5.568Conv=NO(1cycles3points)[Iter=2Diff=0.00204]E=-2460.3787Grad=5.568Conv=NO(1cycles3points)[Iter=3Dif
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