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ID:41009943
大小:1.99 MB
页数:26页
时间:2019-08-13
《乙烷-Hyperchem程序应用》由会员上传分享,免费在线阅读,更多相关内容在工程资料-天天文库。
1、Hyperchem程序应用-乙烷1、画乙烷分子模型:build-defaultelement加氢:模型化:2、用半经验方法CNDO进行优化3、选用从头算计算方法进行单点计算:4、显示键长:5、显示原子电荷:6、显示键角、二面角:7、分子性质:8、乙烷分子2D、3D静电势图:9、等值面图:10、乙烷分子总电荷密度图(2D、3D):11、分子轨道图-最高占据轨道2D、3D图:12、分子轨道图-最低空轨道2D、3D图:13、分子结构模型表示:14、计算输出结果:HyperChemlogstart--SunDec1213:20:412010.Geom
2、etryoptimization,SemiEmpirical,molecule=(untitled).CNDOFletcherReevesoptimizerConvergencelimit=0.0001000Iterationlimit=50Accelerateconvergence=YESOptimizationalgorithm=Fletcher-ReevesCriterionofRMSgradient=0.1000kcal/(Amol)Maximumcycles=120RHFCalculation:Singletstatecalcula
3、tionNumberofelectrons=14NumberofDoubleOccupiedLevels=7ChargeontheSystem=0TotalOrbitals=14StartingCNDOcalculationwith14orbitalsE=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=1Diff=4413.54714]E=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=2Diff=2.12522]E=0.0000Grad=0.000Conv=
4、NO(0cycles0points)[Iter=3Diff=0.13330]E=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=4Diff=0.00917]E=0.0000Grad=0.000Conv=NO(0cycles0points)[Iter=5Diff=0.00002]E=-1659.8192Grad=64.946Conv=NO(0cycles1points)[Iter=1Diff=27.89455]E=-1659.8192Grad=64.946Conv=NO(0cycles1points)[
5、Iter=2Diff=2.23060]E=-1659.8192Grad=64.946Conv=NO(0cycles1points)[Iter=3Diff=0.18582]E=-1659.8192Grad=64.946Conv=NO(0cycles1points)[Iter=4Diff=0.01805]E=-1659.8192Grad=64.946Conv=NO(0cycles1points)[Iter=5Diff=0.00010]E=-1659.8192Grad=64.946Conv=NO(0cycles1points)[Iter=6Diff
6、=0.00000]E=-1634.7422Grad=146.122Conv=NO(0cycles2points)[Iter=1Diff=11.78436]E=-1634.7422Grad=146.122Conv=NO(0cycles2points)[Iter=2Diff=0.88985]E=-1634.7422Grad=146.122Conv=NO(0cycles2points)[Iter=3Diff=0.06927]E=-1634.7422Grad=146.122Conv=NO(0cycles2points)[Iter=4Diff=0.00
7、631]E=-1634.7422Grad=146.122Conv=NO(0cycles2points)[Iter=5Diff=0.00005]E=-1671.0494Grad=3.886Conv=NO(1cycles3points)[Iter=1Diff=0.00236]E=-1671.0494Grad=3.886Conv=NO(1cycles3points)[Iter=2Diff=0.00018]E=-1671.0494Grad=3.886Conv=NO(1cycles3points)[Iter=3Diff=0.00001]E=-1671.
8、1287Grad=2.282Conv=NO(1cycles4points)[Iter=1Diff=0.00235]E=-1671.1287Grad=2.282Con
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