制图作业解答作业1解答

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1、第1页根据立体图中各点的空间位置，画出它们的投影图。a′aa″axayazEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.第1页二、已知A、B、C三点的两面投影，试求出第三投影，并作出立体图。a″aa′abcEvaluationonly.C

2、reatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.答案：Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.第2页三、已知点B在点A的左方25mm，下方10mm，前方18mm，求出B点的三面投影。并完成A点的第三投影。aa″Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5Cl

3、ientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.答案：(B在点A的左方25mm，下方10mm，前方18mm)Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.第2页四、画出直线的第三投影，判断各直线对投影面的相对位置，并标出各特殊位置直线对投影面倾角的真实大小。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2

4、.0.0.Copyright2004-2011AsposePtyLtd.答案：(见教材第43页表3-2)α=0°βγEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.答案：见教材第45页表3-3。α=0°β=0°γ=90°Evaluation

5、only.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.e′f′正平线β=0°αγ(见教材第43页表3-2)Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2

6、004-2011AsposePtyLtd.Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.答案：见教材第43页表3-2。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.第3页五、画出平面的第三投影，判断各平面对投影面的相对位置，并标出各特殊位置平面对投影面倾角的真实大小。abcEvalu

7、ationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.答案：见教材第58页表3-4。α=90°β=0°γ=90°Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-201