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1、习题课电阻电路习题课(一)一个方向:参考方向;二个变换:电阻的Y–变换、电源的等效变换;三个定律:欧姆定律、KCL、KVL;四个元件:电阻、电压源、电流源、受控源;其它:电阻的串并联、分压、分流、功率的计算。U=______I=_______,Uab=______,Ucd=______Uab=_________Ia=______,Ib=______,Ic=_____2.1.3.U+-Is3A2I444140V12V8Vabcd222241一、课内练习题RRRUsbcaUsUs4.5V5V10
2、IaIbIc1010U3A2444I1.U=_____I=_____b1W2.1W2W2W4W40V12V2W2W8VacdIU4U3U2U1U7U6U5AI4.0104112222128-=-=+++++-=VUVUVUVUUVUU07,4.06,4.05,8.043,8.021==-=-====VUUUUab108.04.088.08462=+++=-++=30408.04.088.0408462-=-+++=--++=UUUUcdUab=____Ucd=____3.bcaSUSUSURRRIURUR
3、UISS==33SSURURIRU=×=×=0=-=-=SSSabUUUUUUab=_________bI10W4.5V5V10W10WcIaI3I2I1IAI5.010/51==AI5.010/52==AI110/)55(3=+=AIIIa5.131=+=AIIIb012=-=AIIIc5.132-=--=Ia=______,Ib=______,Ic=_____R=_______,Us=_______Pis发=______,Pus发=______Rab=________.I1=_______6.7.8.电路如下图所
4、示。当k=2时,求I1=?5.等效abRUs+_ab6A2A6V+_104V1+_2A2RRRRRRab23I2+__I13A6+U1kU1I22ba5.6A2A6V+_10Wab66V10Wab6V60V10WR=_______,Us=_______-2V4V6.1W2W2A2A4A2VPis发=______,Pus发=______RRRRRRabRabRab=R/67.RabRRRRRRab=________.2W2W3A6W1ku1u2i1i23i8.电路如下图所示。当K=2时,求二、课内讨论题:1
5、.1A0.5A2AR=3g1A4VI3I22V1322cdabefI1(1)求I1,I2,I3,Uab,Ueg;(2)若R变为5,问Ueg,I1,I2如何变化?3V+-1V+-Uab+-6V+-Uab=3-1=2VUeg+-Ueg=4-2-6=-4VI1=2+1-1=2AI2=2-0.5=1.5AI3=-2A1A0.5A2AR=3g1A4VI3I22V1322cdabefI110V+-Ueg+-R=5R=5Ueg=4-2-10=-8VI1,I2不变。2.(1)以f为参考点,求各点电压;(2)
6、以b为参考点,再求各点电压。1A422V8V2A1A10Veabfcd111012(1)Ua=Uaf=10VUb=Ubf=-8+2=-6VUc=Ucf=2VUd=Udf=-6+1=-5V1V+--5V-+(2)Ua=Uab=16VUf=Ufb=6VUc=Ucb=8VUd=Udb=1VUe=Ueb=2V3.(1)求Rab、Rac。2baca2344422baca2344424.(2)求Rab.21b2a244(a)开路:Rab=2//(4+2)//(2+1)=1(
7、b)短路:Rab=2//(4//2+2//1)=1a242142b5.电路如图,求图中电流I。444244444I-42V+42V2-42V1212124I+42V412121242-42V4I+42V46664解1:解2:444244444I-42V+42V444244444I-42V+42V22224442V42VI对称性:(等电位点)abcd每条支路电阻均为RRab2444442410V
8、10V10V24442410VIIII同极性对称:2444442410V10V反极性对称:222424422410V10VII2422410V