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时间:2019-06-17
《土力学与地基基础习题二》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、地基承载习题第八章第一节习题一 有一条形基础,如图所示,基础宽度b=3m,埋深d=2m,作用在基础底面的均布荷载P=190KPa。已知土的内摩擦角φ=15°,粘聚力C=15KPa,容重γ=18KN/m3。求此时地基中的塑性范围?步骤1:地基中塑性区边界线的表达式为步骤2:塑性区边界线计算α(°)15202530354045505510.52sin2α-5.45α-5.115.26-1.43-5.116.76-1.90-5.118.06-2.38-5.119.11-2.86-5.119.88-3.
2、33-5.1110.36-3.81-5.1110.52-4.28-5.1110.35-4.75-5.119.88-5.22-5.11Z(m)-1.28-0.250.571.141.441.441.130.49-0.45步骤3:第八章第一节习题二 已知地基土的容重γ=18.5KN/m3,粘聚力C=15KPa,内摩擦角φ=18°,条基宽度b=2.4m,埋深d=1.6m,试求该地基的Pcr?9 步骤1:步骤2:表8-1临塑荷载Pcr及临界荷载P1/4的承载力系数Nr、Nq、Nc值φ(度)NrNqNcφ
3、(度)NrNqNc001.003.14220.613.446.0420.031.123.32 240.723.876.4540.061.253.51 260.844.376.9060.101.393.71 280.984.937.4080.141.553.93 301.155.597.95100.181.734.17 321.346.358.55120.231.944.42 341.557.219.22140.292.174.69 361.818.259.97160.362.435.00 382
4、.119.4410.80180.432.725.31 402.4610.8411.73200.513.065.66 453.6615.6414.64第八章第一节习题三 已知有一条形基础,基础宽度b=3m,埋深d=2m,作用在基础底面的均布荷载P=190KPa。已知土的内摩擦角φ=15°,粘聚力C=15KPa,容重γ=18KN/m3。试求该地基的界限荷载P1/3,P1/4? 步骤1:表8-1临塑荷载Pcr及临界荷载P1/4的承载力系数Nr、Nq、Nc值φ(度)NrNqNcφ(度)NrNqNc00
5、1.003.14220.613.446.0420.031.123.32 240.723.876.45940.061.253.51 260.844.376.9060.101.393.71 280.984.937.4080.141.553.93 301.155.597.95100.181.734.17 321.346.358.55120.231.944.42 341.557.219.22140.292.174.69 361.818.259.97160.362.435.00 382.119.4410.
6、80180.432.725.31 402.4610.8411.73200.513.065.66 453.6615.6414.64步骤2:第八章第一节习题四 已知有一条形基础,基础宽度b=3m,埋深d=2m,作用在基础底面的均布荷载P=190KPa。已知土的内摩擦角φ=15°,粘聚力C=15KPa,容重γ=18KN/m3。试求条形基础的临塑荷载Pcr和界限荷载P1/4? 步骤1:查表得:表8-1临塑荷载Pcr及临界荷载P1/4的承载力系数Nr、Nq、Nc值φ(度)NrNqNcφ(度)NrNqNc0
7、01.003.14220.613.446.0420.031.123.32 240.723.876.4540.061.253.51 260.844.376.9060.101.393.71 280.984.937.4080.141.553.93 301.155.597.95100.181.734.17 321.346.358.55120.231.944.42 341.557.219.22140.292.174.69 361.818.259.97160.362.435.00 382.119.4410.
8、80180.432.725.31 402.4610.8411.73200.513.065.66 453.6615.6414.64第八章第一节习题五 某条形基础,基底宽b=1.5m,埋深d=2m,地基土的重度γ=19KN/m3,饱和土的重度γsat=21KN/m3,抗剪强度指标φ=20°,C=20KPa,地下水埋深为1.5m,试求该地基的界限荷载P1/4?步骤1:9表8-1临塑荷载Pcr及临界荷载P1/4的承载力系数Nr、Nq、Nc值φ(度)NrNqNcφ(度)NrNqNc001.003.1422
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