欢迎来到天天文库
浏览记录
ID:38593342
大小:1.07 MB
页数:48页
时间:2019-06-15
《锅炉课程设计示例》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、《锅炉原理》课程设计示例说明47课程设计示例1.设计任务书2.原始资料锅炉型式:带有屏式过热器的汽包锅炉额定蒸发量:D=220t/h过热器温度:t=540℃过热器压力:pgr=100kgf/cm2(表压)给水温度:tgs=215℃热空气温度:trk=400℃排烟温度:θ=130℃冷空气温度:tlk=30℃设计煤种:某无烟煤,成分如下,Cy=63%,Hy=1.938%,Oy=2.16%,Ny=0.555%,Sy=0.62%,Ay=22.017%,Wy=9.71%,Qyd=22558kJ/kg制粉系统:本锅炉采
2、用钢球磨煤机中间贮仓式热风送粉系统锅炉给定参数:给水温度:tgs=215℃,锅炉负荷:D=220t/h,过热蒸汽压力:pgr=100kgf/cm2(表压),过热蒸汽温度:tgr=540℃汽包工作压力:p=112kgf/cm2(绝对)3.改烧煤种的元素分析数据校核和煤种判别3.1改烧煤种数据Cy=66.70%,Hy=3.20%,Oy=2.10%,Ny=1.25%,Sy=2.47%,Ay=17.97%,Wy=6.31%,Vr=9.41%,Qyd=25191kJ/kgt1=1190℃,t2=1340℃,t3=14
3、50℃,Kkm=1.63.2元素成分校核Cy+Hy+Oy+Ny+Sy+Ay+Wy=66.7+3.2+2.1+1.25+2.47+17.97+6.31=100.00%,元素分析正确。473.3发热量计算应用基低位发热量Qydw′=339Cy+1030Hy-109(Oy-Sy-25Wy3.4煤种判别Vr=?<10%,煤种为无烟煤Syzs=4187Sy/QydwAyzs=4187Ay/QydwWyzs=4187Wy/Qydw3.锅炉结构特性(见结构计算书)4.锅炉汽水系统(见任务书)(附)5.燃烧产物和锅炉热平衡
4、计算6.1理论空气量和理论烟气容积序号项目名称符号单位计算公式或数据来源结果1理论空气量V0Nm3/kg0.0889(Cy+0.375Sy)+0.265Hy-0.0333Oy=0.0889×(66.7+0.375×2.47)+0.265×3.2-0.0333×2.16.7902理论氮气容积VN20Nm3/kg0.79V0+0.8Ny/100=0.79×6.79+0.8×1.25/1005.3743RO2气体容积VRO2Nm3/kg1.866(Cy+0.375Sy)/100=1.866×(66.7+0.375
5、×2.47)/1001.2624理论水蒸汽容积V0H2ONm3/kg11.1Hy/100+1.24Wy/100+0.0161V0=11.1×3.2/100+1.24×6.31/100+0.0161×6.790.5436.2空气平衡表受热面名称炉膛、屏凝渣管高温过热器低温过热器高温省煤器高温空气预热器低温省煤器低温空气预热器α′1.151.201.231.261.281.311.33Δα0.050.030.030.020.030.020.03α″1.201.231.261.281.311.331.36476.
6、3烟气特性表名称符号单位受热面名称炉膛、屏凝渣管高温过热器低温过热器高温省煤器高温空气预热器低温省煤器低温空气预热器受热面进口过量空气系数α′/1.151.201.231.261.281.311.33受热面出口过量空气系数α″/1.201.231.261.281.311.331.36平均过量空气系数αpj/1.2151.2451.271.2951.321.345过量空气量ΔVNm3/kg1.3581.4601.6641.8332.0032.1732.343水蒸气容积VH2ONm3/kg0.5650.5670
7、.5700.5730.5750.5780.581RO2容积VRO2Nm3/kg1.2621.2621.2621.2621.2621.2621.262理论氮气容积V0N2Nm3/kg5.3745.3745.3745.3745.3745.3745.374烟气总容积VyNm3/kg8.5598.6628.8699.0429.2149.3879.559RO2份额rRO2/0.1470.1460.1420.1400.1370.1340.132水蒸气份额rH2O/0.0610.0650.0640.0630.0620.0
8、620.061三原子气体份额rn/0.2130.2110.2070.2030.1990.1960.193烟气质量Gykg/kg11.46211.59511.86112.08212.30412.52612.747飞灰浓度μhkg/kg0.01490.01470.01440.01410.01390.01360.0134ΔV=(αpj-1)V0对炉膛α用α″VH2O=V0H2O+0.0161(αpj-1)V0VRO2=
此文档下载收益归作者所有