3、INTOtestbVALUES(6,'f');1rowcreated.SQL>COMMIT;Commitcomplete.用左连接,结果testb表里TempColum的值为NULL:SQL>SELECTa.*,b.id"TempColum"FROMtestaaLEFTJOINtestbbONa.id=b.id; ID VALUE TempColum-------------------- ---------- 2 b 2 4 d 4
4、 6 f 6 5 e NULL 3 c NULL 1 a NULL 6rowsselected.将NULL值过滤出来就是最后需要的结果:SQL>SELECTc.id,c.valueFROM( SELECTa.*,b.id"TempColum"FROMtestaaLEFTJOINtestbbONa.id=b.id)cWHEREc."TempColum"ISN
5、ULLORDERBYc.idSQL> IDVALUE-------------------- 1a 3c 5e