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ID:34547563
大小:296.57 KB
页数:20页
时间:2019-03-07
《高中化学方程式(总)70617》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、高中化学方程式一、非金属单质(F2,Cl2,O2,S,N2,P,C,Si,H)1、氧化性:F2+H2===2HF(阴暗处爆炸)F2+Xe(过量)==XeF22F2+–2(过量)+Xe==XeF4(XeF4是强氧化剂,能将Mn氧化为MnO4)nF2+2M===2MFn(M表示大部分金属)2F2+2H2O===4HF+O2(水是还原剂)2F2+2NaOH===2NaF+OF2+H2OF2+2NaCl===2NaF+Cl2F2+2NaBr===2NaF+Br2F2+2NaI===2NaF+I27F2(过量)+I2===2IF
2、7F2+Cl2(等体积)===2ClF(ClF属于类卤素:ClF+H2O==HF+HClO)3F2(过量)+Cl2===2ClF3(ClF3+3H2O==3HF+HClO3)Cl2+H22HCl(将H2在Cl2点燃;混合点燃、加热、光照发生爆炸)3Cl2+2P2PCl3Cl2+PCl3PCl5Cl2+2Na2NaCl3Cl2+2Fe2FeCl3Cl2+CuCuCl2Cl2+3+-2+2FeCl2===2FeCl3(在水溶液中:Cl2+2Fe===2Fe+3Cl)--Cl2+2NaBr===2NaCl+Br2Cl2+2B
3、r=2Cl+Br2--Cl2+2KI===2KCl+I2Cl2+2I=2Cl+I23Cl2(过量)+2KI+3H2O===6HCl+KIO33Cl2+I–+3H2O=6H++6Cl–+IO3–5Cl2+I2+6H2O===2HIO3+10HCl5Cl2+I2+6H2O=10Cl–+IO3–+12H+Cl2+Na2S===2NaCl+S↓Cl2+S2–=2Cl–+S↓++2Cl–+S↓Cl2+H2S===2HCl+S↓(水溶液中:Cl2+H2S=2HCl2+SO2+2H2O===H2SO4+2HCl++SO2––Cl2+
4、SO2+2H2O=4H4+2ClCl2+H2O2===2HCl+O2Cl2+H2O2=2H++Cl–+O22O2+3FeFe3O4O2+K===KO2S+H2H2S2S+CCS2S+ZnZnSS+FeFeS(既能由单质制取,又能由离子制取)S+2CuCu2S(只能由单质制取,不能由离子制取)3S+2AlAl2S3(只能由单质制取,不能由离子制取)1催化剂N2+3H22NH3N2+3MgMg3N2N2+3CaCa3N2高温高压N2+3BaBa3N2N2+6Na2Na3NN2+6K2K3NN2+6Rb2Rb3NN2+2Al
5、2AlNP4+6H24PH3P+3NaNa3P2P+3ZnZn3P2H2+2Li2LiH2、还原性S+O2SO2S+H2SO4(浓)3SO2↑+2H2OS+6HNO3(浓)H2SO4+6NO2↑+2H2O++6==6NO2-S+4H2↑+2H2O+SO43S+4HNO3(稀)3SO2+4NO↑+2H2O3S+4H++4-NO3SO2+4NO↑+2H2O3N2+O22NO4P+5O2P4O10(常写成P2O5)2P+3X22PX3(X表示F2,Cl2,Br2)PX3+X2PX5P4+20HNO3(浓)4H3PO4+20N
6、O2↑+4H2OC+2F2CF4C+2Cl2CCl4C+O2(足量)CO22C+O2(少量)2COC+CO22COC+H2OCO+H2(生成水煤气)2C+SiO2Si+2CO(制得粗硅)Si(粗)+2Cl2SiCl4(SiCl4+2H2===Si(纯)+4HCl)Si(粉)+O2SiO2Si+CSiC(金刚砂)-+H2-Si+2NaOH+H2O==Na2SiO3+2H2↑(Si+2OH2O=SiO3+2H2↑)3、歧化反应Cl2+H2O==HCl+HClO(加碱或光照促进歧化:(Cl2+H2OH++Cl–+HClO)–
7、=Cl–+ClO–+HCl2+2NaOH==NaCl+NaClO+H2O(Cl2+2OH2O)Cl2+2Ca(OH)2==CaCl2+Ca(ClO)2+2H2O(Cl2+2OH–=Cl–+ClO–+H2O)3Cl2+6KOH(浓)5KCl+KClO3+3H2O(3Cl2+6OH–5Cl–+ClO3–+3H2O)–2S2–+SO2–3S+6NaOH2Na2S+Na2SO3+3H2O(3S+6OH3+3H2O)24P+3KOH(浓)+3H2O==PH3↑+3KH2PO2(4P+3OH–+3H2O==PH3↑+3H2PO2–
8、)11P+15CuSO4+24H2O==5Cu3P+6H3PO4+15H2SO43C+CaOCaC2+CO↑3C+SiO2SiC+2CO↑二.金属单质(Na,Mg,Al,Fe,Cu)的还原性2Na+H22NaH4Na+O2==2Na2O2Na2O+O22Na2O22Na+O2Na2O22Na+S==Na2S(爆炸)2Na+2H+―
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