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1、CHAPTERTWOSOLUTIONS1.(a)12ms(d)3.5Gbits(g)39pA(b)750mJ(e)6.5nm(h)49kW(c)1.13kW(f)13.56MHz(i)11.73pAthEngineeringCircuitAnalysis,6EditionCopyright©2002McGraw-Hill,Inc.AllRightsReserved.CHAPTERTWOSOLUTIONS2.(a)1MW(e)33mJ(i)32mm(b)12.35mm(f)5.33nW(c)47.kW(g)1ns(d)5
2、.46mA(h)5.555MWthEngineeringCircuitAnalysis,6EditionCopyright©2002McGraw-Hill,Inc.AllRightsReserved.CHAPTERTWOSOLUTIONS3.Motorpower=175Hp(a)With100%efficientmechanicaltoelectricalpowerconversion,(175Hp)[1W/(1/745.7Hp)]=130.5kW(b)Runningfor3hours,3Energy=(130.5´1
3、0W)(3hr)(60min/hr)(60s/min)=1.409GJ(c)Asinglebatteryhas430kW-hrcapacity.Werequire(130.5kW)(3hr)=391.5kW-hrthereforeonebatteryissufficient.thEngineeringCircuitAnalysis,6EditionCopyright©2002McGraw-Hill,Inc.AllRightsReserved.CHAPTERTWOSOLUTIONS4.The400-mJpulselast
4、s20ns.(a)Tocomputethepeakpower,weassumethepulseshapeissquare:Energy(mJ)400t(ns)20-3-9ThenP=400´10/20´10=20MW.(b)At20pulsespersecond,theaveragepowerisPavg=(20pulses)(400mJ/pulse)/(1s)=8W.thEngineeringCircuitAnalysis,6EditionCopyright©2002McGraw-Hill,Inc.AllRights
5、Reserved.CHAPTERTWOSOLUTIONS5.The1-mJpulselasts75fs.(c)Tocomputethepeakpower,weassumethepulseshapeissquare:Energy(mJ)1t(fs)75-3-15ThenP=1´10/75´10=13.33GW.(d)At100pulsespersecond,theaveragepowerisPavg=(100pulses)(1mJ/pulse)/(1s)=100mW.thEngineeringCircuitAnalysi
6、s,6EditionCopyright©2002McGraw-Hill,Inc.AllRightsReserved.CHAPTERTWOSOLUTIONS6.Thepowerdrawnfromthebatteryis(notquitedrawntoscale):P(W)106t(min)571724(a)Totalenergy(inJ)expendedis[6(5)+0(2)+0.5(10)(10)+0.5(10)(7)]60=6.9kJ.(b)TheaveragepowerinBtu/hris(6900J/24min
7、)(60min/1hr)(1Btu/1055J)=16.35Btu/hr.thEngineeringCircuitAnalysis,6EditionCopyright©2002McGraw-Hill,Inc.AllRightsReserved.CHAPTERTWOSOLUTIONS247.Totalchargeq=18t–2tC.(a)q(2s)=40C.(b)Tofindthemaximumchargewithin0£t£3s,weneedtotakethefirstandsecondderivitives:3dq/
8、dt=36t–8t=0,leadingtorootsat0,±2.121s222dq/dt=36–24t22substitutingt=2.121sintotheexpressionfordq/dt,weobtainavalueof–14.9,sothatthisrootrepresentsamaximum.Thus,wefind
