第十四章β-二羰基化合物课后答案

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1、第十四章P—二拨基化合物命名下列化合物:1-CH卩COOHCOOH2-C^CDCHCOOC^2—甲基丙二酸l^^COOC^2—乙基一3—丁酮酸乙酯2—环C酮甲酸甲酯氯甲酰乙酸乙酯3—丁酮醛二、2*（XC^COOHdH2CH2CH2COOHCOOH3-c2h5ch(c(x)h)2C^C^COOH写出下列化合物加热后生成的主要产物:00ICC0H.0"ch3coc（ch3）cooc2h5三、试用化学方法区别下列各组化合物:CH3COCH(CH3)COOC2H5,不变解：加漠水：褪色解：分别加入饱和亚硫酸氢钠水溶液，1顶替酸生成晶体，而丙二酸不能。四、下列各组化合物，那些是互变异构体，那些是共振

2、杂化体？0

3、C1-厂、0曲0lCOQHsJklCOC.IL一-厂、r-互变异构体0-ch3_E090CH「t_0-共振杂化体2-互变异构五、完成下列缩合反应：1-2珂呼唱屯]・NaOq*2・ch3ch2cooc2h5cooq*CH^C^COCHCOOq^+qH5OHch31・NaOC^COCHCOCX^COOC^booc^1・NaOC2H54-C犷'、ch2ch2cooc2h5i・NaOC^C^C^COCHC^^ch3(M^CHCOOC2H5a*cSbooq^"ch30ICCOOC2H500IC+HCOOC^1・NaOC2HsIC厂、2LCHO六、完成下列反应式:1・。32・Zn,册CHO

4、ch2ch2choCHO2-CHsCOCHgCOOqtNa^COCHCOOC^ch3cichcooc2h55%NaOHch3coch2chcooc2h5ch3cochcooc2h5_chcooc2h5ch3収堺巒,出bbc^coc^cooq^c^cooq^「2C^MgBrCH3COCHJJC2H5rXIOHNaOC2HsNaCH(tOOC2H5)2ch2=chcoch3I—Roetett^NaBH4pNaOH^O2•出厶"rjXH^CHC^C^COC^CO(!)H七、写出下列反历程：0c6h5ch2icch2c6h5ch2=chcochNaOCH3CH3UH解：反应历程:0c6h5chjcc

5、h2c6h5NaOCH30C6H5CH2iCGHC6H50CH2=CHCOCH3c6H5CH2i€CHC6h5NaOCHAtH2CH2COCH300c6h5ch_iC_CHC6H5八、以甲醇，乙醇为原料，用丙二酸酯法合成下列化合物:1,2—甲基丁酸CH3OHpg3ch3cic2h5oocch2cooc2h5NaOC2H5NaOC2H5ch3ch2cic2h5oh比]CH3CH2C1ch3c2h5oochcooc2h5ch3HOOCCCOOHch2ch3△CH.C1ch3c2h5oocccooc2h5ch2ch3rH2O,-OH2也疔ch3ch3ch2chcooh2•正己酸ch3ch2oh[0

6、]5%NaOHaqch3choCHXH=CHCHO坞工吐ch3ch2ch2ch2ohPCI?ch3ch2ch2ch2cicooqH5CHNaC^C^C^C^Clcooc2h5CHCH2CH2CH2CH3Looc2h51芯°J°HCI^C^C^C^C^COOH3,3—甲基己二酸ch3ch2ci2CH3CHCH2Brch2oC^C^MgClh3oC^C^C^OHC^CH^2BrCH3CHCH2BraHOOCC^CHC^C^COOHch3rH2O,-OH(C2H5OOdCHCHCH2CH(COOC2H5)224,1,4—环己烷二甲酸H.?S04CHSCH?OH24?△ch2=ch2Br2BrCH2

7、CH2Br2NaOC?Hs2ch2(c()oc2h5)2-NaCH(COOC2H5)2BrCH2CH2BrNaCH(COOC2H5)2CH(COOC2H5)22b2一、ch(cooc2h5)2NaOC2Hc2H$(xrcooc2hsBrCH2CH2BrCOOHC2]•NaOH,H2O2也0*5.环内烷甲酸c2h5oocchcooc2h5+BrCH2CH2BrNaC2H5OOCCCOOC2H5CH2CH2Brc2h5cccooc2h5凶八ch2c2h5oocchcooc2h5CH2CH2Br].NaOH,H2ONaOC2H52・砂CDOH九、以甲醇，乙醇于以及无机试剂为原料,1,3-乙基—盒戊

8、酮PQ1CH?CH?OH3丁c^c^ciC^COC^COOC^Nag*经乙酰乙酸乙酯合成下列化合物:NaOC^CH3CH2C1CHCFLC19比CH3COCHCOOC2H53CH.COCHCOOq^CH2CH3%NaOHH3O盟隅C^CDCCXXT^53CH3COCHCH2CH(tH2CH3Na2.2—甲基丙酸PCI3CH3OHch3coch2cooc2h5ch3ciNaOC2H5NaOC2H5ch3ciNa