资源描述:
《常用计算方法及描述统计量分析》由会员上传分享,免费在线阅读,更多相关内容在工程资料-天天文库。
1、实验一常用计算方法及描述统计量分析姓名:罗玉学号:3110343133习题2.10某海水养殖场进行贻贝与海带混养的对比实验,收获时各抽取50绳测其毛茧(kg)试从〒均数、极差、标准差、变异系数儿个指标评估单养和混养效果,并给出分析结论。单养50绳母数拋45,45,33,53,36,45,42,43,29,25,47,50,43,49,36,30,39,44,35,38,46,51,42,38,51,45,41,51,50,47,44,43,46,55,42,27,42,35,46,53,32,41,48,50,51,46,41,34,44,46混养50绳重量数据:51,48,
2、58,42,55,48,48,54,39,58,50,54,53,44,45,50,51,57,43,67,48,44,58,57,46,57,50,48,41,62,51,58,48,53,47,57,51,53,48,64,52,59,55,57,48,69,52,54,53,50解:经数据分析得参数单养混养平均42.752.1标准差7.07766.3350极差3()3()最小值2539最大值5569变异系数16.58%12.16%从极差上看,单养和浞养的重fi极差均为30,混养的重虽平均数高于单养,但是混养的标准差和变异系数均低于单养,说明混养的差异较小,混养的東量整齐
3、度优于单养的電量。习题2.对某种fff重复抽得100株,测量高资料如下(单位:cm):127,118,121,113,145,125,87,94,118,111,102,72,113,76,101,134,107,118,114,128,118,114,117,120,128,94,124,87,88,105,115,134,89,141,114,119,150,107,126,95,137,108,129,136,98,121,91,111,134,123,138,104,107,121,94,126,108,114,103,129,103,127,93,86,113,97
4、,122,86,94,118,109,84,117,112,125,94,79,93,112,94,102,108,158,89,127,115,112,94,118,114,88,111,111,104,101,129,144,128,131,142。将样本资料分组整理,列岀频率分布表,绘岀样本频率分布阁。解:经数据分析得敁大值为158,敁小值为72,对数椐进行分组得频率分布表接收频率接收频率7001202780313019909110161001310013110169091202714071301915051407803150516011601700其他0其他0样本频率
5、分布阁实验二假设检验4.7检查三化螟各IU:代每卵块的卵数,检查笫一代128个卵块,其平均数为47.3粒,标准差为25.4粒;检查第二代69个卵块,其平均数为74.9粒,标准差为46.8粒。试检验两代每卵块的卵数有无显著差异。解:⑴假设HO:P1=P2即两代卵块间无.U著差兄;HA:U1笑P2两代卵块间有差昇(2)选収W•著性水平a=0.05(3)检验计算:瓜,—X,=pi+-^-=6.0649U=xl-x2=—4.55Vnln2oxx—x2查表可知
6、(/
7、〉"0.05=1.96,P8、9.川屮草药青木乔治疗高血压,记录13个病例,测定的舒张压(mmHg)数据为治疗前110115133133126108110110140104160120120治疗f9011610110311088921041268611488112试检验该药足否其有降低血压的作用。解:⑴假设HO:Ul=P2即两代卵块间无显著差异;HA:U1其U2两代卵块间有差异(2)选取显著性水平(1=0.05;双尾检验(3)检验计算:由于木题Of和6722未知,故先进行F检验山于F=1.5348,FP0.05,即说明两样本是等方差则进行
9、t-检验的双样本等方差假设检验:治疗前治疗后乎均122.2308102.3077方差252.859164.7308合并方差208.7949假设平均差0df24tStat3.515225P(T<=t)单尾0.000887t单尾临界1.710882P(T<=t)双尾0.001774t双尾临界2.063899因为T=3.515225>Uft界=2.063899,所以否定H0,即治疗前P冇显著差异,该药物冇降低血糖值的效果习题4.10.为测定A、B两种病毒对烟草的致病力,取8株烟草,每一株皆半叶接种A病毒,:W