路基路面设计201412

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1、路基路面设计201412长春建筑学院课程名称题冃院系专业班级姓名指导教师课程设计报告交通学院交通工程交1102班钱晋2014年12月1日1A重力式挡土墙设计1设计参数挡土墙墙高H=7.8m,取基础埋置深度D=1.5m,挡土墙纵向分段长度取L=10m;路基宽度13m,路肩宽度3.0m;墙面与墙背平行，墙背仰斜，俯斜坡度1:0.25,?=14.03°,墙底(基底)倾斜度tan?0=0.190，倾斜角?0=10.76°;墙顶填土高度a=2.0m，填土边坡坡度1:1.5,?=arctan(1.5)=33.69°，？1汽牢荷载边缘距路肩边缘d=0.5m墙后填夹石内摩擦

2、角?=45?，填土与墙背外摩擦角?=?/2=22.5?，填土容重?=22.5kN/m;风化软石地基与浆砌片石基底的摩擦系数f=0.50；3墙身采用5号块石，墙身砌体容重?k=22.5kN/m,砌体容许压应力3[?a]=2000kPa,砌体容许剪应力[?>450kPa,砌体容许拉应力[?wl]=160kPa；地基容许承载力[?0]=9601^3。2车辆荷载换算hO?q??12.75?0.67m193主动土压力计算3.1计算破裂角？2A?ab?2hO(b?d)?H(H?2a?2hO)tan?(H?a)(H?a?2hO)2?3?2?0.67?(3?0.5)?7.8

3、?(7.8?2?2?2?0.67)tan(14.03?)?(7.8?2)?(7?2?2?0.67)??0.14co???????45?14.O3??22.5??81.53?tan???tano)?(cot??tana))(tan(x)?A)??tan81.53??(cot45??tan81.53?)(tan81.53??0.14)?0.41??22.29?墙底到路肩的水平距离为3.75m,路肩宽3m,墙底至破裂面与路基交点距离为(7?2.5)?0.86?8.17m,3+3.75=6.75<8.17破裂谢交于荷载内进行计算直线形仰斜墙背，且墙背倾角?较小，不会

4、出现第二破裂面。3.2计算主动土压力Ea及其作用点位置3.2.1计算主动土压力Eah2?h3?d0.5??0.76mtan??tan?0..41?0.25b?atan?3?2?0.41??3.3mtan??tan?0.41?0.25Ka?cos(???)tan??tan?)sin(??o)cos(22.29??45?)?tan22.29??tanl4.03???sin(22.29??81.53?)?0.27hl?H?h2?h3?7.8?0.76?3.3?3.74m3Kl?l?h2hh2a(l?3)?021H2HH2?23.742?0.76?3.3?l?(l?

5、)?7.82?7.860.84?1.47Ea?ll?H2KaKl??22.5?60.84?0.27?1.4722?271.66mEx?Eacos(???)?271.66?cos(14.03??22.5?)?210.29mEy?Easin(???)?271.66?sin(14.03??22.5?)?161.7m3.2.2计算主动土压力的合力作用点位置Ha(H?h3)2?h0hl(3hl?2H)Zx??33H2Kl7.82?(7.8?3.74)2?0.76?3.3?(3?3.3?2?7.8)??33?60.84?1.47?2.67mB?bl?bltan?tan?

6、0?1.7?1.7?tan(14.03?)?0.190?1.78mZy?b?Zxtan??1.78?2.67?0.25?2.45m设bl=1.7(见“附录”的图)Zxl?Zx?bltan?0?2.67?1.7?0.190?2.35mZyl?bl?Zxltan??1.7?2.35?tan(14.03?)?l.llm44挡土墙计算4.1抗滑动稳定性验算墙身体积计算：Vl?b(H?bltan?0)?1.74?(7.8?1.74?0.190)?13m3V2?0.5bltan?0?0.5?1.742?0.190?0.29m325V?Vl?V2?13?0.29?13.2

7、9m3墙身自重计算：Gl=V??13?22.5?292.5kN,G2=V??0.29?22.5?6.53kN,lk2kG?Gl?G2?235.62?5.28?299.03kN抗滑稳定性验算:?0.9G??QlEy??0.9Gtan?0?YE??0.9?299.03?0.5+1.4?161.7?0.5+0.9?299.03?0.19?1.4?210.29?4.47墙身自重力臂计算:ZGl?0.5[(H?bltan?0)?n?bl]?0.5???7.8?1.74?0.190??0.25?1.74??2.67l??ZG2?[l/2?l/3(l/2?tan?tan?

8、0)]b??0.5?(0.5?0.047)??1.7