c语言cfree题目

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1、2417Description输入某年某月某日，判断这一天是这一年的第几天？Input输入为一行输入格式为YYYY-MM-DDOutput输出这天是这一年的第几天SampleInput2007-01-01SampleOutput1SourceYhr#includeintmain(){inta,b,c,d,f;scanf("%d-%d-%d",&a,&b,&c);if(a%400==0)f=1;elseif(a%4==0&&a%100!=0)f=1;elsef=0;switch(b){case1:d=0;break;case2:d=31;break;ca

2、se3:d=31+28;break;case4:d=31+28+31;break;case5:d=31+28+31+30;break;case6:d=31+28+31+30+31;break;case7:d=31+28+31+30+31+30;break;case8:d=31+28+31+30+31+30+31;break;case9:d=31+28+31+30+31+30+31+31;break;case10:d=31+28+31+30+31+30+31+31+30;break;case11:d=31+28+31+30+31+30+31+31+30+31;break;

3、case12:d=31+28+31+30+31+30+31+31+30+31+30;break;default:printf("inputerror!");break;}d=d+c;if(b>2)d=d+f*1;printf("%d",d);return0;}Description输入数字1-7，打印出对应的英文（Monday-Sunday）.Input输入数字1-73502Output输出该数字对应的英文单词SampleInput7SampleOutputSundaySourcejsj_5_3#includeintmain(){intn;scan

4、f("%d",&n);switch(n){case1:printf("Monday");break;case2:printf("Tuesday");break;case3:printf("Wednesday");break;case4:printf("Thursday");break;case5:printf("Friday");break;case6:printf("Saturday");break;case7:printf("Sunday");break;default:printf("inputerror!");break;}retur

5、n0;}3503Description输入一个百分制成绩，转换为五级记分制成绩并输出。Input输入一个score（0<=score<=100）。Output按照以下规则进行转换并输出转换后的成绩。score:90-100---->goodscore:80-89---->nicerscore:70-79---->mediumscore:60-69---->passscore:0-59---->failSampleInput67SampleOutputpassSourcemgc1008#includeintmain(){ints;scanf("%d",&

6、s);if(s>=90&&s<=100)printf("good");elseif(s>=80&&s<=89)printf("nicer");elseif(s>=70&&s<=79)printf("medium");elseif(s>=60&&s<=69)printf("pass");elseprintf("fail");return0;}3504要求根据以下函数关系，对输入的任意整数x，计算出相应的y值。要求用switch语句实现。x的值y的值x<0y=00<=x<10y=x10<=x<20y=10x>=20y=30Input输入的任意整数xOut

7、put计算出相应的y值SampleInput39SampleOutputy=30.000000Sourcejsj_4_4#includeintmain(){intx,y,t;scanf("%d",&x);if(x<0)t=1;elseif(x<10&&x>=0)t=2;elseif(x<20&&x>=10)t=3;elset=4;switch(t){case1:printf("y=0");break;case2:printf("y=%d",x);break;case3:printf("y=10");break