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时间:2018-10-16
《氧化还原标准电位表.pdf》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、氧化还原标准电位表0半反应E(伏)+F2(气)+2H+2e=2HF3.06+O3+2H+2e=O2+2H2O2.072–2–S2O8+2e=2SO42.01+H2O2+2H+2e=2H2O1.77–+MnO4+4H+3e=MnO2(固)+2H2O1.6952–+PbO2(固)+SO4+4H+2e=PbSO4(固)+2H2O1.685+HClO2+H+e=HClO+H2O1.64+HClO+H+e=1/2Cl2+H2O1.634+3+Ce+e=Ce1.61+–H5IO6+H+2e=IO3+3H2O1.60+HBrO+H+e=1/2Br2+H2O1.59–+BrO3+6H+5e=1/2B
2、r2+3H2O1.52–+2+MnO4+8H+5e=Mn+4H2O1.51Au(III)+3e=Au1.50+–HClO+H+2e=Cl+H2O1.49–+ClO3+6H+5e=1/2Cl2+3H2O1.47+2+PbO2(固)+4H+2e=Pb+2H2O1.455+HIO+H+e=1/2I2+H2O1.45–+–ClO3+6H+6e=Cl+3H2O1.45–+–BrO3+6H+6e=Br+3H2O1.44Au(III)+2e=Au(I)1.41Cl2(气)+2e=2Cl1.3595–+ClO4+8H+7e=1/2Cl2+4H2O1.342–+3+Cr2O7+14H+6e=2Cr+7
3、H2O1.33+2+MnO2(固)+4H+2e=Mn+2H2O1.23+O2(气)+4H+4e=2H2O1.229–+IO3+6H+5e=1/2I2+3H2O1.20–+–ClO4+2H+2e=ClO3+H2O1.19–Br2(水)+2e=2Br1.087+NO2+H+e=HNO21.07––Br3+2e=3Br1.05+HNO2+H+e=NO(气)+H2O1.00++2+VO2+2H+e=VO+H2O1.00+–HIO+H+2e=I+H2O0.99–+NO3+3H+2e=HNO2+H2O0.94–––ClO+H2O+2e=Cl+2OH0.89–H2O2+2e=2OH0.882+–C
4、u+I+e=CuI(固)0.862+Hg+2e=Hg0.845–+NO3+2H+e=NO2+H2O0.80+Ag+e=Ag0.79952+Hg2+2e=2Hg0.7933+2+Fe+e=Fe0.771–––BrO+H2O+2e=Br+2OH0.76+O2(气)+2H+2e=H2O20.682––AsO8+2H2O+3e=As+4OH0.68–2HgCl2+2e=Hg2Cl2(固)+2Cl0.632–Hg2SO4(固)+2e=2Hg+SO40.6151––MnO4+2H2O+3e=MnO2+4OH0.588–2–MnO4+e=MnO40.564+H3AsO4+2H+2e=HAsO2+2
5、H2O0.559––I3+2e=3I0.545–I2(固)+2e=2I0.5345Mo(VI)+e=Mo(V)0.53+Cu+e=Cu0.52+2–4SO2(水)+4H+6e=S4O6+2H2O0.512––HgCI4+2e=Hg+4Cl0.48+2–2SO2(水)+2H+4e=S2O3+H2O0.403–4–Fe(CN)6+e=Fe(CN)60.362+Cu+2e=Cu0.3372++3+VO+2H+2e=V+H2O0.337++BiO+2H+3e=Bi+H2O0.32–Hg2CI2(固)+2e=2Hg+2Cl0.2676+HAsO2+3H+3e=As+2H2O0.248–AgCI
6、(固)+e=Ag+Cl0.2223++SbO+2H+3e=Sb+H2O0.2122–+SO4+4H+2e=SO2(水)+H2O0.172+–Cu+e=Cu0.5194+2+Sn+2e=Sn0.154+S+2H+2e=H2S(气)0.141–Hg2Br2+2e=2Hg+2Br0.13952++3+TiO+2H+e=Ti+H2O0.12–2–S4O6+2e=2S2O30.08–AgBr(固)+e=Ag+Br0.071+2H+2e=H20.000––O2+H2O+2e=HO2+OH-0.067++––TiOCl+2H+3Cl+e=TiCl4+H2O-0.092+Pb+2e=Pb-0.126
7、2+Sn+2e=Sn-0.136–AgI(固)+e=Ag+I-0.1522+Ni+2e=Ni-0.246+H3PO4+2H+2e=H3PO3+H2O-0.2762+Co+2e=Co-0.277+Tl+e=Tl-0.33603+In+3e=In-0.3452–PbSO4(固)+2e=Pb+SO40.35532––SeO3+3H2O+4e=Se+6OH-0.366+As+3H+3e=AsH3-0.38+Se+2H+2e=H2Se-0.402+Cd+2e=Cd-
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