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时间:2018-10-03
《混凝土配料监控系统设计》由会员上传分享,免费在线阅读,更多相关内容在行业资料-天天文库。
1、课程设计说明书(2011/2012学年第1学期)课程名称:《监控组态设计基础》课程设计题目:混凝土配料监控系统设计专业班级:学生姓名:学号:指导教师:设计周数:设计成绩:2011年12月23日13目录1、课程设计目的··································12、课程设计正文··································32.1 工程的简介················································32.2 下位机PLC设
2、计···········································32.3 创建组态界面··············································52.4 制作动画连接···············································52.4.1罐向导动画连接···········································52.4.2搅拌器动画连接13·························
3、··················62.4.3传感器动画连接···········································62.4.4启动按钮动画连接··········································72.5 脚本动作····················································73、课程设计总结或结论·····························114、参考文献1、课程设计目的1、了解混凝土
4、配料的控制方法和控制要求。2、确定上位机监控系统的控制方案。3、利用软件编制上位机监控系统界面,建立实时数据库。4、利用仿真程序对上位机监控系统进行模拟试验。2、课程设计正文2.1 工程的简介13首先沥青入喷射舱,各热骨料仓装料,粉料仓装料;热骨料,粉料,沥青入搅拌锅;最后搅拌结束,由小车将料运走。通过PLC控制水泥,沙子,石头,水等各种材料的给定量来设定配方,自行确定上料的次序和搅拌时间。2.2 下位机PLC设计LDSM0.1RM0.0,32LDI0.4OM0.0ANT37=M0.0TONT37,20L
5、DI0.5LDNI0.4AM1.1OLD=M1.1LDT37OQ0.0LDM1.0ANM1.1OLDANM0.2=Q0.0LDI0.2SM0.2,1LDM0.2ANM0.3=Q0.1LDI0.113SM0.3,1LDM0.3ANM0.4=Q0.2LDI0.0SM0.4,1LDM0.4TONT38,600ANT38=Q0.4LDT38OM0.0=Q0.3LDNQ0.0ANQ0.2AI0.3EDSM0.5,1LDM0.5TONT39,200LDT39RM0.0,6=M1.02.3 创建组态界面132.4 制作
6、动画连接罐向导动画连接搅拌器动画连接13传感器动画连接启动按钮动画连接132.5 脚本动作1313主程序IFzl==1THENdj1=1;dj2=1;dj3=1;dj4=1;dj5=1;fw=0;ENDIFIFdj1==1THENg1=g1+20ENDIFIFdj2==1&&dj3==1THENg2=g2+20;jb1=1;ENDIFIFdj4==1THENg3=g3+20ENDIFIFdj5==1THENg4=g4+20ENDIFIFg1>=100&&g2>=100&&g3>=100&&g4>=100T
7、HENdj1=0;dj2=0;dj3=0;dj4=0;dj5=0;ENDIFIFjb3==1THENg1=g1-20;g2=g2-20;g3=g3-20;g4=g4-20;jb1=0;jb2=1;dj6=1;g5=g5+10;ENDIFIFys==1THENjb2=0;jb3=0;g5=g5-10;x=x+10;ENDIFIFx>=100THEN13xc=xc+20;dj6=0;ENDIFIFxc>=100THENxc=0;x=0;ENDIFIFtz==1THENzl=0;jb3=0;ys=0;dj1=0
8、;dj2=0;dj3=0;dj4=0;dj5=0;dj6=0;g1=g1;g2=g2;g3=g3;g4=g4;g5=g5;jb1=0;jb2=0;xc=xc;ENDIFIFfw==1THENzl=0;jb3=0;ys=0;dj1=0;dj2=0;dj3=0;dj4=0;dj5=0;dj6=0;jb1=0;jb2=0;g1=0;g2=0;g3=0;g4=0;g5=0;xc=0;tz=0;133、课程设计总结或结论我所在组课设的题
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