资源描述：
《武汉理工大学线性代数网络作业满分》由会员上传分享，免费在线阅读，更多相关内容在工程资料-天天文库。
1、单选题1.设总体的概率密度为，其中，未知，为一样本，则的矩估计为（ ）(A)(B)(C)(D)难度：较易 分值：2.0 2.已知向量。当时，是的线性组合(A)(B)(C)(D)officiallyestablishedonJuly1,2013,Yibincity,formerlyknownasthebus,integratedoriginalrongzhoubuscompanyinYibincityandMetrobuscompany,formedonlyinYibincityofaState-ownedpu
2、blictransportenterprises,thecompanyconsistsofoneortwo,thirdDivision.Integrationofpublictransportservicesisnotyetestablished难度：较易 分值：2.0 3.与矩阵相似的矩阵为（）(A)(B)(C)(D)难度：较易 分值：2.0 4.使实二次型正定的参数应该是()(A)不存在(B)(C)(D)officiallyestablishedonJuly1,2013,Yibincity,former
3、lyknownasthebus,integratedoriginalrongzhoubuscompanyinYibincityandMetrobuscompany,formedonlyinYibincityofaState-ownedpublictransportenterprises,thecompanyconsistsofoneortwo,thirdDivision.Integrationofpublictransportservicesisnotyetestablished难度：较易 分值：2.0 5.对
4、矩阵，作乘法，必须满足（）(A)(B)(C)(D)难度：较易 分值：2.0 6.如果，则行列式(A)(B)(C)(D)难度：较易 分值：2.0 7.设是来自的一个样本,则（）officiallyestablishedonJuly1,2013,Yibincity,formerlyknownasthebus,integratedoriginalrongzhoubuscompanyinYibincityandMetrobuscompany,formedonlyinYibincityofaState-ownedpu
5、blictransportenterprises,thecompanyconsistsofoneortwo,thirdDivision.Integrationofpublictransportservicesisnotyetestablished(A)(B)(C)(D)难度：较易 分值：2.0 8.齐次线性方程组，则该方程（）(A)无解(B)只有零解(C)有无穷多解(D)无法确定难度：较易 分值：2.0 9.线性齐次方程组有非零解，则（）。(A)(B)(C)(D)难度：较易 分值：2.0 officia
6、llyestablishedonJuly1,2013,Yibincity,formerlyknownasthebus,integratedoriginalrongzhoubuscompanyinYibincityandMetrobuscompany,formedonlyinYibincityofaState-ownedpublictransportenterprises,thecompanyconsistsofoneortwo,thirdDivision.Integrationofpublictransportse
7、rvicesisnotyetestablished10.矩阵的伴随矩阵为（ ）(A)(B)(C)(D)难度：较易 分值：2.0 11.下列运算中正确的是（ ）。(A)(B)(C)(D)难度：较易 分值：2.0 12.设总体服从正态分布，其中为已知，从总体中取样本，则的置信度为的置信区间为（ ）officiallyestablishedonJuly1,2013,Yibincity,formerlyknownasthebus,integratedoriginalrongzhoubuscompanyinYi
8、bincityandMetrobuscompany,formedonlyinYibincityofaState-ownedpublictransportenterprises,thecompanyconsistsofoneortwo,thirdDivision.Integrationofpublictransportservicesisnotyetestab
