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1、第2章正弦交流电路习题参考答案（Thesecondchapter,sinusoidalACcircuitexercises,referenceanswers）Thisarticleiscontributedbyxjgcn1234DOCdocumentsmayexperiencepoorbrowsingontheWAPside.ItisrecommendedthatyoufirstselectTXT,ordownloadthesourcefiletothelocalview.Thesecondchapter,sinusoidalACcircuitexercises,referenceans
2、wers2.1thefollowingsinusoidalquantitiesarerepresentedbyphasorquantities:(1)u=10,2,sin314tVolts(2)i=-5sin(314t-60)AnnSolution:(1)U=10/0(V)(2)Im,=-5/-60,=5/180-60=5/120(A);Themaximumvalueof2.2knownfrequencysinusoidalvoltageUABis311V,theinitialphaseof-60degrees,theeffectivevalueishowmuch?Writetheins
3、tantaneousexpression;whent=0.0025S,Uabvalueofsolution:UABM=dreams?2Uab11x311=220(V)UABM=22TheeffectivevalueofAB=U*TheinstantaneousvalueexpressionisuAB=311sin(314T60degrees)(V),whent=0.0025SisU,ab=311*sin,100pi*0.0025PI=311sin()=80.5(V)312PI2.3indicatethevoltage,current,whicharecorrectandwhicharew
4、rongintheseriesRCcircuit(1)I=uZ(2)I=UR+XC(3)I=TheCofU.U,R,J,Omega,C(4)I=,U,Z(5)U=UR+UC(6)U,=U,R,+U,C(7)I=-jU(8)I=JOmegaCSolution:inR,Cseriescircuits,thetotalimpedanceisZ=R,J,X,C=R,J,andZ=22R+XCOmega1cUI=ZUR=IRU=IXCU=U,R+UC222U=U,R,+U,CSo(1)(2)(3)(5)(7)(8)iswrong,,,,(4)(6)ofthe2.4.InFigure2.1,U1=4
5、0V,U2=30V,i=10sin314t,A,U?Andwritetheinstantaneoussolutionbyexpression.ThecircuitdiagramshowsthevoltageandcurrentofU1Iwiththesamedirection,whilethevoltageU2aheadofcurrentI90,so2U=U12+U2=302+402=50(V)DreamsaheadofcurrentIelectricvoltageUangle=arctanu=502*sin(31.4t+36.9)(V)3U1=arctan=36.9DEGU242.5,
6、showninFigure2.2,thecircuitisknownasu=100sin(314t+30)voltsandi=22.36sin(314t+19.7),TwelveI2=10sin(314t+83.13)Ann,try:I1,Z1,Z2,andexplainthenatureofZ1,Z2,drawphasorSolution:byquestion,IM=22.36/19.7degrees(A),soI1m=I,m,I2,M=20/6.87degrees(A)I1=20sin(314T6.87)(Z1=A)dreamsI2m=10/83.13degrees(A)UM=100
7、/30degrees(V)Um100/30DEG==50/38.67degrees(omega)I1m2/8.67degrees100/30degreesU=10/53.13degrees(omega)Z2=M=I2M10/83.13degreesHenceZ1inductiveload,capacitiveload.2.6Z2asshowninFigure2.3,XR=XL=R,A1andknowncurrentmeterread
