2022-2023学年天津市中考数学专项提升仿真模拟试题（一模二模）含解析

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8DVBD1AC,ZDBA=45°,AZBAD=45°,AZBAC=135°.ᦑ⌱DD.6.᝞Mᙠ(1Y,45Ḅᚖᑖ"'+4CJᚖ2JḄor4CDF=2¥,ᑣN2᜛c()DBA.100°B,104°C.105°D.110°ூ;<=ᫀ௃Bூ@௃BD,BF,D•'(ABCD(AD=CD,AZDAC=ZDCA.TEFᚖᑖAB,ACᚖᑖBD,AAF=BF,BF=DF,AAF=DF,]9⚓/`51⚓

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/XAFGூ-fKᫀ௃(1)©ª?᪆[(2)2ூᑖ᪆௃(1)᪷t-./Ḅឋ¬ᑮ/B=ND=90஺,᪷tᢚ®Ḅឋ¬r¯ZAFE=ZD=90°,°±ᑮNNFG=N8=90஺AB=AF,/G=4GᑮI³/ᐰµ[(2)᪷tᐰµᑮ8G=FG,BG=FG=x,ᑣCG=6—x,᪷tE=0ᑮCE=EF=£>E=3,ᑣEG=3+x,᪷t·¸¹ᳮExḄ".ூ௃(1)•••¼//8CQ#-./:.NB=ND=90஺,AD=AB,ᵫᢚ®Ḅឋ¬r½4>/¯ZAFE=ZD=90°,.ZAFG=90°,AB=AF,.NAFG=NB,4G=AG,.4ABGq/XAFG\(2)ஹV/\ABG^/\AFG,.BG=FG,BG=FG=x,ᑣGC=6-X,42⚓/51⚓

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஺8cḄE᝞ᡠ:.CE=16.ᙠN8E,45⚓/51⚓

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ST"PA$஺OḄᑗV2
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Tf"OCD,46⚓/51⚓

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஺஺^Q/3.ᙠRtAAFG,VAF=2,GF=1,...᪷n{|pᳮq"AG=y/AF2+GF2=V22+l2=75ᵫ(2)JAG«AB=12=—=AG5OBD,"AD$00Ḅ0Q/ABD=90஺.,,AB12V52V5ᙠRtZkABDVsinZADB=——AD=6,,45=.-.sinZADB=—.AD55VZACE=ZACB=ZADB,.".sinZACE=—.523./ᜧᐜᡃrᐵ"ᵫᢥᡂ¡¢£¤¥¦§ᡂ¨©ªḄ«ᵫ¬.®¯ᢥ᯿ᐵ£ḄM±²³“µ¶·ᐹ”.IJD±“µ¶·ᐹ”Ḅᡂ/ºA10ᐗ,/ºA12ᐗ,ºᨴ½y(A)¨ᓫx(ᐗ)©ªḄᐵÀÁÂ[XÃᦪ"y=—10x+500.47⚓/51⚓

47(1)®¯ᙠÅÆḄEᨴ(ᓫp/20ᐗÉÊDEᨴ/ˬḄ«/ÌÍᐗÎ(2)®¯ÏqḄᑭÐ/W(ᐗ)Òᓫp/ÌÍᐗÓºᨴ6ÏqᑭÐÎ(3)ᱥÖ×ØpD±“µ¶·ᐹ'’ḄᓫÛq28ᐗ.᝞Ü®¯Ý⌕ºᨴÏqḄᑭÐÛß3000ᐗÉÊ/ˬḄ«ᨬÍ/ÌÍᐗÎூbc!ᫀ௃(1)DEᨴ/ˬḄ«/600ᐗV(2)Òᓫp/30ᐗÓºᨴ6ÏqᑭÐ4000ᐗV(3)ᓫp/28ᐗÓºEᨴ/ˬḄ«ᨬÍ/440ᐗ.ூᑖ᪆௃(1)Sr½᪷nºA⊡ä2ᐗᓽ6ᜐᳮᡂ,.(2)ᑭᵨåÃᦪḄឋçᓽ6h!ᡂ,.(3)᪷nᩩAcprè½Ḅé`ëSryḄᨬí`ᓽ6ᜐᳮᡂ,.ூkh௃(1)Òx=20Ó,y=-10x+500=-10X20+500=300,300X(12-10)=300X2=600ᐗ,ᓽDEᨴ/ˬḄ«/600ᐗV(2)ᵫ⚪òq"%(x-10)(-10x+500)=-10X2+600X-5000=-10(x-30)2+4000.'a=-10<0,...Òx=30Óõᨵ`4000ᐗ.ᓽÒᓫp/30ᐗÓºᨴ6ÏqᑭÐ4000ᐗV(3)ᵫ⚪òq"-10x2+600x-5000=3000,hq:ø=20,x=40.2'a=-10<0,ùᱥÅúᔣ],.•.Ò204W40Ó,3000^x^4000.YXW28,...Ò204W28Ów3000,ᨴḄpᐗ.p=(12-10)X(-lOx+500)=-20x+1000.$-20<0..p&xḄ'ᜧ)*+,-28/pᨵᨬ+2440ᐗ.ᓽᓫ628ᐗ/ᨴḄᨬ7440ᐗ.8⚪ὃ;<=>?ᦪḄAᵨC⚪ḄᐵEFᳮC⚪HIJ᪀L=>?ᦪᜐᳮᨬ2ᡂOIJᑭᵨ?ᦪḄ'*ឋᜐᳮRSᡂOTḄᨬ2ᡂOUVTὃWὃ⚪X.24.᝞Z[\AB_x`VaB(2,0),_y`VaA(0,2),[\DMLx`fg`VaM,_\hABVaC,DM=3,jkDA,ZDAC=90°.(1)o[\ABḄC᪆q.(2)oDaᙶ᪗tu0ஹDஹBwaḄxᱥ\C᪆q.(3)zaPF\hOB|Ḅ}auaP~x`Ḅᚖ\_ABVF,_(2)Txᱥ\VE,jCE,ᔲᙠPABPFAFCEzᙠoPaᙶ᪗zᙠ▊ᳮᵫ.48⚓/51⚓

48ூfᫀ௃1[\ABḄC᪆qy=-x+22Daᙶ᪗F1,3,xᱥ\ḄC᪆qy=-3xx-23P-,03-^,஺ᡈ,0.333ூC௃⚪ᑖ᪆¡1᪷£¤6¥ᦪ¦§¨?ᦪC᪆q;2᪷£ªῪ[¬w¬Ḅᑨ6ឋ¯§¨Zaᙶ᪗᪷£¤6¥ᦪ¦§¨?ᦪC᪆q;3᪷£w¬Ḅᑨ6ឋ¯§¨Eaᙶ᪗᪷£aḄᙶ᪗°±?ᦪC᪆q§¨Eaᙶ᪗§¨Paᙶ᪗.⚪C᪆¡1[\Z8ḄC᪆q²A.2aᙶ᪗³ᐭ?ᦪC᪆q¨h=2k=-107LAC¨2¶+b=0,b=2,[\ABḄC᪆q=-ᵪ2•OA=OB=2,49⚓/51⚓

49...¹048FªῪ[¬w¬.'AD^AB,ZDAG=900-N0AB=45°,ᓽ¹/1OGFªῪ[¬w¬.DG=AG=OG-OA=DM-OA=2>-2=\,=஺aᙶ᪗F(1,3)xᱥ\ḄC᪆qy=«x(x-2),²஺aᙶ᪗³ᐭ¨ᡝ”([-2)=3,C¨஺=-3,xᱥ\ḄC᪆q¿-3x(x-2)(3)ᵫ(2)¨NP8E=45°,ᑣNCFE=N8EP=45°,-(x,0),MP=x-1,PB=2-x,জ,NECF=NBPF=90°Z,[BPFsAFCE,uC~CHLEF,CH=LEF,ᓽEF=2CH=MP,2PE=PF+EF=BP+2MP=2-x+2(jc-l)=x,ᓽE(xÃ.²Eaᙶ᪗³ᐭxᱥ\¨x=-3x(x-2)»x,=",ᓽP20)C¨ᑁ=0(Æᔠ⚪HÈ)33ঝ᝞Z2,\Dojp,MX^2,NCEE=N8PE=90°/[CEFஹ¹8PFªῪ[¬w¬PE=MC=\,²Eaᙶ᪗³ᐭ?ᦪC᪆q¨-3x(x-2)=l,C¨Ì=Í5,஽=Í50⚓/51⚓

50Ð/Pwᓛ,0ᡈÒÓ,0,Ô|ᡠÖ¡-g,0=FoᡈØÓ,0,51⚓/51⚓