2022-2023学年吉林省吉林市中考数学专项提升仿真模拟卷（一模二模）含解析

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2022-2023
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1A.a>b>c>dB.a>b>d>cC.b>a>c>dD.b>a>d>c7.᝞@ᙠZA=30°,5c=1,P஺EᑖO;ZTo8C,4cḄPᑣ஺EḄ"#A.1B.2C.qD.1+7348.᝞@tYABCDḄᕜ"#20cm,DEJ_AB,ᚖz#E,COSZ=1ᑣ5ᑡ78জDE=3cmkঝEB=lcmkঞSt8co=IS஺/.9:Ḅ]ᦪ#()CA.0]B.1]C.2]D.3]ஹ(ᐳ18ᑖ#$%⚪3ᑖ)9.=(+2)ஹ2+3%2;^_1ᦪᑣḄ-;.210.PA(-3,yi),B(-1,y2),C(2,yj)ᙠᱥy=]X?|yi,y3Ḅᜧᐵl2⚓/L52⚓

2b;(ᵨ“ீ”).411.Qᨴ8cNC=90°,tanA——,ᑣsinJ+cos4=___.312.᝞@\oYABCDPP;/TBDḄPPE,FᑖO;AB,CDḄPAD=BC,ZPEF=35°,ᑣNPFEḄᦪ;.13.᝞¡¢£ᚁi=43Ḅ¥ᚁ¦§50¨©ªᡠᙠḄ¬®¯ᩭḄ¬ᓣ²³¨.14.´ᙠAABCBC=6,AC=6µZA=30°,ᑣABḄ";______.Xஹ¶·⚪(ᐳ78ᑖ)15.¸¹(1)2cos60°-(2009-n)0+tan450.(2)2sin600-3tan300+2sin450-72.16.᝞@ᙠo"ᙳ#1Ḅ9»Y¼½¾aOABḄ⚔PO,A,Bᙳᙠ½PÀO;ZTᙶ᪗bḄ¯PPAᙠxF.(1)Ã஺#¬ÄÅaOABÆᜧÇÈÆᜧ©ḄQOAiBi,ÉAOAB/`ÊḄ®#21,ËÌQOAiBi,(ᡠËaOAiBiÉAOABᙠ¯PÍÎ)k(2)ZᑏÌPAiஹBiḄᙶ᪗(3)ZᑏÌtanNOAiBi.l3⚓/L52⚓

317.᝞@ÊÐÑḄi☢#ÓY/BCD,Ô᪷Ö@ᦪÖ×ÌᚁTØÙÑÚÛNO.(7Üᶇ᪷Þ)18.᝞@M;QZBCḄo8cḄPANᑖNBAC,BNLANஹN,à"8Ná4c0PD,48=10,8c=15,MN=3(1)×âBN=DN(2)×QABCḄᕜ".19.᝞@Zy=-x+2ãXFḄPA(2,0),ÀÉᱥä=å2á0B,CÍPPBᙶ᪗#(1,1).(I)×ᱥḄ1ᦪ⊤çèk(2)7OC,×Ì2MoeḄ☢ê.l4⚓/L52⚓

4320.᝞@ᙠëYABCDDE_LAC0E,cosZADE=-,AB=3.(1)×ADḄ-k21.᝞@ᙠ^ABCAD;BCoḄ²ta=cosZDAC.1
×âAC=BDk122
sinC=—BC=34,ZᑏÌADḄ";.22.ìíîᙠᦟîð¦ñò³ó“ìí”ôᛛ᝞@11জ.#³ö÷ôᛛḄ²øᙠ^ðùᑮPC,ᑭᵨXTüöÈôᛛ⚔ýAPḄþT#30஺ÚÿBḄ45஺ᙠᑮD,ᑭᵨAḄ60஺᝞10ঝ.CD10!"ᛛABḄ$%.&'ᑮ0.1(ὃᦪ+6=1.73
,5⚓//52⚓

5(1)12᝞জ456E7ᡠJ_ZE!BCஹF,45/9᧕;2#ADE/ECF(=ᨵ◤⌕;A)C(2)DE2᝞ঝ9ᙠFG28coḄH49I(9=ᨵJ4ஹ஺Lᔠ)459E,6ஹE'EF(PE,!BCஹF,45PF.;2APDENOPC(3)Qᵨ2᝞ঞ*EF!4B,F,EF(PE,ᐸTᩩV=ᨵWXAPEFḄ☢Z[6,ᑣ4PḄ]—.24.᝞ᙠ_HGABCD`AD//BC,NC=90°BC=4,DC=3,AD=6.aPbD!cdefDAḄgᔣᙠefDAIijk2lmᓫo]Ḅp%qaaQbC!cᙠfrCBIijk1mᓫo]Ḅp%ᔣBqaPஹQᑖtbD,Cuv!cwQqaᑮBvPxyz{qa.|qaḄv}t(k).(1)|48஺஺Ḅ☢Z5,~5ᑏ!sJfy}Ḅᦪᐵ[(=ᨵᑏ).(2)wB,P,Q⚔ḄG[ῪGv!vtḄ.(3)wfrPQJfrABO0,X20A=0Bv~5ᑏ!tan/8QP=.(4)[ᔲᙠv980ᙠ!fḄC=ᨵᙠAᳮᵫ.,6⚓//52⚓

62022-2023
ᔡ᪍ḕᔡ᪍ὃᦪ⚗ᓣᔁஹ⌱⌱2ᐳ24ᑖj⚪3ᑖ1.ᙠᵨA4BC`ZC=90°,Z5=40°,AB=5,ᑣBCḄ]5A.5tan40°B.5cos40°C.5sin40°D.---------7cos40ூᫀ௃Bூ௃••ᙠRtZkABC`,ZC=90°,BC.co=------ABVAB=5,ZB=40°,.*•BC=ABco=5cos40°.ᦑ⌱B.2.ᙠaABC`ZC=90°,sinA=—,ᑣcoḄ()2A.1B.—C.D.y222ூᫀ௃Bூᑖ᪆௃ᐜ᪷+sinA=XᑮNAḄ%ᦪᓽ§ᑮNBḄ%ᦪ¨᪷+Ḅ┦ᦪ2ᓽ§ᑮ&'.ூ௃2•••sinA=Xi2ZA=60°,/ZC=90°J.ZB=30°..co=----2ᦑ⌱B.,7⚓//52⚓

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1122ூ"#௃#(,1=4(-3,y\)>B(-1»y?)-C(2,Ñ)ᙠÊᱥÒX(-3)2228282=6,»2=]X(-1)2=—,]V]V6,•9•y2ᦪCHf=Ḅᙶ᪗ᱯÚ>ᦪCHf=Ḅᙶ᪗Û¬>ᦪ#᪆Ü#⚪Ḅᐵ¥.4d.*[8஺+NC=90°,tanJ=—,ᑣsiM+cos4=.37ூᫀ௃-4ூ"#௃••ᙠ*48C+ZC=90°,tan^=£3•kß8C=4àAC=3k,.••ᵫáâvᳮkl49=5%,..BC4k4AC3k3/.sin4=-----=—=—,cosA=------=—=—,AB5k5AB5k5437sin?l+cos/=—F—=—.555ᦑ2512.᝞CDABCD+=PJBDḄ+==E,FᑖIAB,CDḄ+=,AD=BC,ZPEF=35°,ᑣNPFEḄãᦪ_____.ூᫀ௃35஺x12⚓/{52⚓

12ூ"#௃(DABCD+=PJBDḄ+==E,FᑖIAB,CDḄ+=,/.PEAABDḄ+PF4BDCḄ+/.PE=yAD,PF=yBC,XVAD=BC,...PE=PF,/.ZPFE=ZPEF=35°.ᦑᫀ35°.13.᝞äåæçᚁãi=4(3Ḅéᚁêë50ìíîᡠᙠḄïðñᩭḄïᓣônì.ூᫀ௃30ூ"#௃#(᝞hCABõ⊤éᚁACõ⊤÷☢ᑣᵫ⚪ÅkÉ(AB=50,BC(AC=3(4,kßBC=3x,ᑣAC=4x,...ᙠRt^ABC+ᵫáâvᳮkl((3x)2+(4x)2=5()2,#l(%,=10,x=-10(úᨵᔠ⚪Åýþ)2.♦.BC=30.ᓽîᡠᙠḄïðñᩭᓣôn30ì.ᦑᫀ30.14.ÈÉᙠAABC+BC=6,AC=6JJ,ZA=30°,ᑣABḄ.ூᫀ௃12ᡈ6ூ
௃᪷⚪᝞ᡠᑣᵫ⚪AC=66CBCB2=6,NA=30஺,CCDJ_ABD,.,.ZCDA=ZCDB2=90°,VAC=6V3>ZA=30°,CBI=CB,2CD=35AD=J(6!_(3ᔣ2=9,DB=DB=/62-(3V3)2=3-12A$13⚓/'52⚓

13.•.AB=AD-DBi=9-3=6ᡈAB=AD+DB=9+3=12.2ᦑ6ᡈ12.9:⚪Ḅ⚪⌕=᪷⚪>◤@NABCC=DEFC=┦E,HI◤ᑖKLMNOᑖPQRSTU⚪>VᨵCXᶍZᐸ\]^MNO._ஹU⚪(ᐳ78ᑖ)15.de:(1)2cos60°-(2009-n)0+tan450.(2)2sin600-3tan300+2sin450-2.ூpqUᫀ௃(1)1;(2)0.ூ
௃t⚪ᑖ᪆(1)vwᑭᵨEḄ_Ezᦪ|}~ᢣᦪḄឋᓄUᫀ(2)vwᑭᵨEḄ_Ezᦪ|ᓄᐭUᫀ.t⚪᪆(1)=2X-1+1=12(2)=2X-3X+2XF-&=-V3+V2-72=0.23216.᝞ᙠᙳ1ḄpOABḄ⚔O,A,Bᙳᙠ¡஺=vEᙶ᪗¤ḄAᙠx¦¡.(1)}஺§¨©^OAB«ᜧ«ᜧ®ḄOAiBi¯AOAB°±²³Ḅ´21,OAiBi(ᡠAOAiBi¯AOABᙠLµ)(2)vwᑏAiஹBiḄᙶ᪗(3)vwᑏtanNOAiBi.$14⚓/'52⚓

14ூ
௃t⚪ᑖ᪆·1¸᪷§¨¹ᣚḄ»¼ᓽ;·2¸ᵫᓽḄᙶ᪗·3¸᪷pᑗzᦪḄ»¼.t⚪᪆·1¸᝞஺8|ᓽᡠÁ·2¸ᵫஹBiḄᙶ᪗·4,0¸Â·2,-4¸ᦑUᫀ·4,0¸Â·2,-4¸B.C4·3¸᝞tan/048i==2.4c29:⚪Ã⌕ὃÅ-§¨¹ᣚ⚪ḄᐵÇ=ÈÉÊ˧¨¹ᣚḄ»¼~ឋ.17.᝞^³ÌÍḄÎ☢ÐN8CDt᪷ᦪÁᚁEÒÂÍÓÔZC.·Ö×Øᶇ᪷Ú¸ூpqUᫀ௃AD=75+45$15⚓/'52⚓

15ூᑖ᪆௃ᙠR/ACE஺ÛÜvÝÞ}~ᚁÞ´ÁᚁEaஹḄ8BF,4஺F,ᙠRhZBb᪷ÜvÝÞÂᚁÁ2ᔆḄᓽÁ4஺=/!+8C+OE.ூ
௃8ᙠ4B=5,BF=CE=4.AF=3.ᙠtana=—=;=—.DE3.•./&=30°஺£=ᒹ=4etanaAD=AF+FE+ED=3+4.5+4>j3=1.5+4y/3■UᚁEaé30஺ÍÓÔZZ¸7.5+.I⚪ὃÅḄê=vE_EḄ±ᵨ^ᚁÞᚁEë⚪⚪ḄᐵÇ=“LÝ”᪀⌼vE_EÂð=ᨵᐵÐë⚪>ñḄòó².18.᝞M=NBCḄBCḄANᑖZBAC,8N_L4NN,öBN÷/CD,øZ8=10,8c=15,MN=3·2¸Á/3CḄᕜ.ூpqUᫀ௃·1¸ú᪆·2¸41ூᑖ᪆௃·1¸ûüNBNýᓽÖT.·2¸ᐜᑨMN80CḄCD,ᵫ14>/8=10,ᕜᓽ."16⚓/%52⚓

16ூ*+௃1
-./01N,/.ZANB=ZAND,ᙠZB344£W-Z1=Z2V-AN=AN,ZANB=ZAND:AABNq/\ADN(ASA)./.BN=DN.(2),:#ABN/4ADN,/.AD=AB=IO,DN=.5/1MBC1AMN8OCḄ./.CD=2MN=6./.AABCḄᕜ=Z8+8C+C0+/D=10+15+6+10=41.19.᝞78y=-x+29X:;Ḅ1A(2,0),<=>ᱥy=a¥@0B,CA11Bᙶ᪗D(1,1)(1)F>ᱥḄGᦪ⊤JKL(2)MNOC,FAJOCḄ☢P.ூ*+௃Q⚪ᑖ᪆/(1)V1BḄᙶ᪗Wᐭy=ax2+஺ḄZᓽᑮ>ᱥḄ+᪆KL(2)ᵫ(1)ᡠ>ᱥḄ+᪆K48Ḅ+᪆K]ᔠ᪀ᡂab]+ab]ᓽF1CḄᙶ᪗1AḄᙶ᪗ᓽFaAOCḄ☢P.Q⚪+᪆/"17⚓/%52⚓

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F-/AC=BDL122
¶sinC=·BC=34,8ᑏADḄ_ூ¸¹ᫀ௃1
-.º+᪆L2
——.ூ*+௃Q⚪ᑖ᪆/1᪷┦¦§¦GᦪḄ»ᓽFᫀ.CD12(2)¼ᵫ0J=—,ᑡabᓽFX.AC13ADAD.Q⚪+᪆/+/1
ᵫ⚪¾ª/ta=cosND4C,L---------BD—ACLBDAC12CD1234-x12”(2)¼/C=8D=x,JCD=BC-BD=34-x.VsinC=—----------=-r+:13JC~13x13442x=----.25442ᦑᫀD----.2522.ÀÁ±ᙠᦟ±ÃÄÅÆ¢·Ç“ÀÁ”Êᛛ᝞711জ.D¢ÍÎÊᛛḄµÏÐ.ᙠsÃÑᑮ·1C,ᑭᵨ§¦ÒÍÊᛛ⚔ÔA1ḄÕ¦D30஺Ö×B1ḄئD45஺ÐÙᙠÚÃÑᑮ·1D,ᑭᵨ§¦ÒÍA1ḄئD60஺᝞710ঝ.¶ÜªCDD10ÝÞFÊᛛABḄµÏ.Nßᑮ0.1Ýàὃᦪ6=1.73
"19⚓/%52⚓

19ூ¸¹ᫀ௃ÊᛛABḄµÏáD6.8Ýூᑖ᪆௃91CâCELAB0E,᪷⚪ãäªᩩæçFAC=5,ᑭᵨ+8¦§¦}çFAE4CEḄÏè·éFBE,ᓽFAB=AE+BE.ூ*+௃+/᝞791CâCE_LAB0E.VZD=90o-60o=30°,ZACD=90°-30°=60°,sZCAD=90°.VCD=10,/.AC=yCD=5.ᙠRtZkACE5AE=ACsinNACE=5sin300=·,2CE=AC*cosZACE=5*cos30°=-----.2ᙠRtABCEVZBCE=45°,BE=CEtan450=-2/.AB=AE+BE=-+^-=-6+1=6.8Ý.ᡠçÊᛛABḄµÏáD6.8Ý.222"20⚓/%52⚓

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3ᵨ᝞ঞ*EF!AB,IF,EF1PE,ᐸᩩᨵAPEFḄ☢6,ᑣ/Ḅ—.ூ"#$ᫀ௃1()᪆
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24
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