上下盖概率法公差分析

《上下盖概率法公差分析》由会员上传分享，免费在线阅读，更多相关内容在行业资料-天天文库。

1、QuantaStorageInc.ENGStudyReportENGNo：新进人员学习心得Date：02/18/2008Page:4of4Description:學習報告Subject:底座上下蓋段差分析~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~NextSubject:　對模具知識學習~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~S

2、tudycontents:EH3US2底座公差分析，詳見如下：图1PE7500202R00QuantaStorageInc.ENGStudyReportENGNo：新进人员学习心得Date：02/18/2008Page:4of4图2如图2：设上下盖组立后间隙为组装后的封闭环A01，求A01已知，A1=114.8+0.2/0A2=114.80/-0.2A01=114.8-114.8=0T01=(0.22+0.22)1/2=0.282Δ01=0.1-(-0.1)=0.2ES01=0.2+0.282/2=0.341EI01=0.2-0.282/2=0.059A01=(0+0.341/+0.

3、059)/2=0+0.17/+0.03图3如图3所示，设上盖外边为封闭环A02.，建立尺寸链求A02.已知：A3=116.8+0.5/+0.3A2=114.80/-0.2A02=116.8-114.8=2T02=(0.22+0.22)1/2=0.282Δ02=0.4-(-0.1)=0.5ES02=0.5+0.282/2=0.641EI02=0.5-0.282/2=0.359A02=(2+0.641/+0.359)/2=1+0.32/+0.18PE7500202R00QuantaStorageInc.ENGStudyReportENGNo：新进人员学习心得Date：02/18/2008

4、Page:4of4图4图5如图4所示，设上下盖断差为A0且为装配后的封闭环，建立尺寸链如图5：已知：A4=1.0+0.3/+0.2A01=0+0.17/+0.03A02=1.0+0.32/+0.18A0=1+0-1=0T0=(0.12+0.142+0.142)1/2=0.22Δ0=0.25+0.10-0.25=0.10ES0=0.10+0.22/2=0.21EI0=0.10-0.22/2=-0.01侧A0=0+0.21/-0.01则分析可得其断差在0.21到-0.01之间。PE7500202R00QuantaStorageInc.ENGStudyReportENGNo：新进人员学习心

5、得Date：02/18/2008Page:4of4　PE7500202R00