全国中考数压轴题精选精析.doc

全国中考数压轴题精选精析.doc

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1、2008年全国中考数学压轴题精选精析25.(08江西南昌)24.如图,抛物线相交于两点.(1)求值;(2)设与轴分别交于两点(点在点的左边),与轴分别交于两点(点在点的左边),观察四点的坐标,写出一条正确的结论,并通过计算说明;(3)设两点的横坐标分别记为,若在轴上有一动点,且,过作一条垂直于轴的直线,与两条抛物线分别交于C,D两点,试问当为何值时,线段CD有最大值?其最大值为多少?(08江西南昌24题解析)24.解:(1)点在抛物线上,,·································

2、··························································2分解得.···········································································································3分(2)由(1)知,抛物线,.·······5分当时,解得,.点在点的左边,,.············6分当时,解得,.点在点的左边,,.··············

3、··········································7分,,点与点对称,点与点对称.·······························································8分(3).抛物线开口向下,抛物线开口向上.················9分根据题意,得.···············································11分,当时,有最大值.····························

4、···················12分说明:第(2)问中,结论写成“,四点横坐标的代数和为0”或“”均得1分.26.(08江西南昌)25.如图1,正方形和正三角形的边长都为1,点分别在线段上滑动,设点到的距离为,到的距离为,记为(当点分别与重合时,记).(1)当时(如图2所示),求的值(结果保留根号);(2)当为何值时,点落在对角形上?请说出你的理由,并求出此时的值(结果保留根号);(3)请你补充完成下表(精确到0.01):0.0300.290.290.130.03(4)若将“点分别在线段上滑动”改

5、为“点分别在正方形边上滑动”.当滑动一周时,请使用(3)的结果,在图4中描出部分点后,勾画出点运动所形成的大致图形.(参考数据:.)(08江西南昌25题解析)25.解:(1)过作于交于,于.,,,.······················································································2分,.··································································

6、·······················3分(2)当时,点在对角线上,其理由是:··········································4分过作交于,过作交于.平分,,.,,.,.,.即时,点落在对角线上.································································6分(以下给出两种求的解法)方法一:,.在中,,.··············································

7、····························7分.························································································8分方法二:当点在对角线上时,有,···························································································7分解得.·······················

8、·································································8分(4)由点所得到的大致图形如图所示:12分说明:1.第(2)问回答正确的得1分,证明正确的得2分,求出的值各得1分;2.第(3)问表格数据,每填对其中4空得1分;3.第(4)问图形画得大致正确的得2分,只画出图形一部分的得1分.27.(08山东滨州)23、(1)探究新知:如图1,已知△ABC与△

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