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1、第一章1.4指出下列物质在液氨中的酸碱行为（写出反应方程式）：CH3CO2H,NH2CONH2,CH3CH2OH,NaH1.4Pointedoutthatthefollowingsubstancesinacid-basebehaviorinliquidammonia(writereactionequation):CH3CO2H,NH2CONH2,CH3CH2OH,NaH参考答案：CH3CO2H为强酸CH3COOH+NH3→CH3COO--+NH4+NH2CONH2为弱酸NH2CONH2+NH3≈NH4++NH2
2、CONH-CH3CH2OH为弱酸CH3CH2OH+NH3≈NH4++CH3CH2O-NaH为强碱NaH+NH3→NH2-+H2↑1.4指出下列物质在液氨中的酸碱行为（写出反应方程式）：1.4Pointsoutthefollowingmaterialinthesodaacidliquidammoniabehavior(writearesponseequation)CH3COOH,H2NCONH2,CH3CH2OH,NaH解：CH3COOHstrongacidCH3COOH+NH3=CH3COOˉ+NH4＋H2NC
3、ONH2weakacidH2NCONH2+NH3=NH4＋+NH2CONHˉCH3CH2OHweakacidCH3CH2OH+NH3=NH4＋+CH3CH2OˉNaHstrongsodaHˉ+NH3=NH2ˉ+H21.5指出下列物质在100%H2SO4中的酸碱行为（写出反应方程式）：HNO3,CH3CO2H,HClO4,C2H5OH,H2NCONH2,SO31.5Pointedoutthatthefollowingsubstancesinacid-basebehaviorin100%H2SO4(writerea
4、ctionequation):HNO3,CH3CO2H,HClO4,C2H5OH,H2NCONH2,SO3参考答案：HNO3为碱HNO3+2H2SO4→2HSO4-+NO2++H3O+CH3CO2H为碱CH3COOH+H2SO4→HSO4-+CH3COOH2+HClO4为酸HClO4+H2SO4≈H3SO4++CH3COOH2+C2H5OH为碱C2H5OH+2H2SO4→CH3CH2HSO4+HSO4-+H3O+H2NCONH2为碱H2NCONH2+H2SO4→HSO4-+H2NCONH3+SO3为碱SO3+H
5、2SO4≈H2S2O7H2SO4+H2S2O7≈H3SO4++HS2O7-1.8Pleasewritedownthechemicalequationofthefollowingreactions.(1)Potassiumamideandanilinehavereactionsinliquidammonia.(2)InjecthydrochloricacidintoconcentratedsulfuricacidandconcentratednitricacidsolutiontogetNO2Cl.(3)Bori
6、cacidisdissolvedinsulfuricacid.1.9Inliquidammonia,whatistheconcentrationofammoniumion?1.9intheliquidammonia,whatistheconcentrationofammoniumion?Answer:2NH3=NH4++NH2-K=1.0*10-33[NH4+]=K1/2=3.16*10-7(MOl/L)1.12estimateroughthevalueofPKaabouteachoftheFollowinga
7、cids?Answer:1.phosphitepka1=2pka2=72.nitricacidpka1=-33.Percholoricacidpka=84.Periodatepka1=2pka2=71.12粗略估计下述各酸的pKa值1.12AroughestimatethefollowingthesourpKavalue解：(1)H3PO3m=1pK1=2pK2=pK1+5=7(2)HNO3m=2pK=-3(3)HClO4m=3pK=-8(4)H5IO6m=1pK1=2pK2=7第二章2.1Determinet
8、hefollowingmoleculesorobjectsbelongpointgroup(1)SiHDBr2TetrahedralCspointgroup(2)SiFClBrITetrahedralC1pointgroup(3)SiH2Br2TetrahedralC2vpointgroup(4)PCl3ThreesidesofvertebralC3vpointgroup(5)OPCl
