电力系统及其自动化毕业论文

《电力系统及其自动化毕业论文》由会员上传分享，免费在线阅读，更多相关内容在学术论文-天天文库。

1、220kV变电所电气部分一次系统设计设计计算书专业：电力系统及其自动化姓名：宋铁成学校：吉林电子信息职业技术学院东北电力学院毕业设计论文设计计算书短路电流计算1、计算电路图和等值电路图系统阻抗标幺值：设：SJ=100MVAX1=X2=X3=0.2X4=X5=X6=(Ud／100)*(Sj/Se)=(14.1/100)*(100/240)=0.59X7=X8=X9=X10=Xd*”*(Sj/Se)=0.167*(100/300/0.85)=0.0473X7=X8=X9=X10=(Ud%/100)*(Sj/Se)=(14.6/100)

2、*(100/360)=0.0406X15=X16=X*Sj/Up²=0.4*150*(100/230²)=0.1134X17=X18=X*Sj/Up²=0.4*100*(100/230²)=0.075655东北电力学院毕业设计论文根据主变的选择SFPSLO-型变压器，可查出：UdI-II%=14.6、UdI-III%=6.2、UdII-III%=9.84X19=X22=1/200*(UdI-II%+UdI-III%-UdII-III%)*(Sj/Se)=1/200*(14.6+6.2-9.84)*(100/240)=0.0228X

3、20=X23=1/200*(UdI-II%+UdII-III%-UdI-III%)*(Sj/Se)=1/200*(14.6+9.84-6.2)*(100/240)=0.0379X20=X23=1/200*(UdI-III%+UdII-III%-UdI-II%)*(Sj/Se)=1/200*(6.2+9.84-14.6)*(100/240)=0.003(1)、d1点短路电流的计算：X25=（X1+X4）/3=0.0863X26=（X7+X11）/4=0.02198X27=X15/2=0.0567X28=X17/2=0.0378X29

4、=X25+X27=0.143X30=X26+X28=0.05978用个别法求短路电流①水电厂S–1:Xjss–1=X29*(SN∑1/Sj)=0.143*(3*200/0.875/100)=0.9855东北电力学院毕业设计论文①水电厂H–1:XjsH–1=X30*(SN∑1/Sj)=0.0598*(4*300/0.85/100)=0.844查运算曲线：t=0”时I*S-1”=1.061I*H-1”=1.242IS-1”=(I*S-1”*SNS-1)／(√3*Uj)=1.061*(3*200/0.875)／(√3*230)=1.82

5、6KAIchS-1=IS-1”*√[1+2*(Kch-1)²]=1.826*√[1+2*(1.85-1)²]=2.855KAIH-1”=(I*H-1”*SNH-1)/(√3*Uj)=1.242*(4*300/0.85)/(√3*230)=4.402KAIchH-1=IH-1”*√[1+2*(Kch-1)²]=4.402*√[1+2*(1.85-1)²]=6.883KAI”=IS-1”+IH-1”=1.826+4.402=6.288KAIch1=IchS-1+IchH-1=2.855+6.833=9.738KAt=2”时I*t=2s

6、-1”=1.225I*t=2H-1”=1.36It=2s-1”=(I*t=2s-1”*SNS-1)/(√3*Uj)=1.225*(3*200/0.875)/(√3*230)=2.109KAIt=2H-1”=(I*t=2H-1”*SNH-1)/(√3*Uj)55东北电力学院毕业设计论文=1.36*(4*300/0.85)/(√3*230)=4.8198KAIt=2”=It=2s-1”+It=2H-1”=2.109+4.8198=6.928KAT=4”时I*t=4s-1”=1.225I*t=4H-1”=1.375It=4s-1”=(I

7、*t=4s-1”*SNS-1)/(√3*Uj)=1.225*(3*200/0.875)/(√3*230)=2.109KAIt=4H-1”=(I*t=4H-1”*SNH-1)/(√3*Uj)=1.375*(4*300/0.85)/(√3*230)=4.873KAIt=4”=It=4s-1”+It=4H-1”=2.109+4.873=6.982KA⑵、d2点短路电流的计算：X31=（X19+X20）/2=0.03035X32=X29+X31+X29*X31/X30=0.143+0.03035+0.143*0.03035/0.0598=

8、0.246X33=X30+X31+X30*X31/X29=0.0598+0.03035+0.0598*0.03035/0.143=0.103用个别法求短路电流55东北电力学院毕业设计论文①水电厂S–1:Xjss–1=X32*(SN∑1/Sj)=0.