2019高考化学真题分类汇编工艺流程题（解析版）

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⚪16⚪I.[2019
᪗I]⏚(H3BO3)⌕Ḅᓄᧇᵨᴻஹஹᧇ஺╅"(#Mg2B2O5H2஺ஹSiO2$%&Fe2O3ஹA1O)'ᧇ()⏚$*+,ᓄ╅Ḅ-.᝞0:23╅"2562—►H,BO38pH=6.59╅I-Mg(OH)ஹ•MgCO,*+,ᓄ╅NH4HCO334:;0ᑡ=⚪:(1)ᙠ95࠷“3B”╅"2)(ḄDEᙠ“ᔾᦈ”HIḄᓄJK.L'o(2)“6MI”ḄN⌕ᡂᑖᨵ஺'RS“561”TḄ64Hᔲ#ᨵFe3+VWX⌱ᵨḄᓄJZᑺ஺(3)᪷]H3BO3Ḅ^VI_HBO+HOH++B(OH)-4^=5.81xlO-10,XᑨaH3BO3332a⏚bᙠ“562”cd34pH8⁚f3.5,gḄ஺(4)ᙠ“9╅"H(ᡂMg(OH)2MgCO39iḄVWK.L',k4lmnTXo:___qrstᵨ஺ᵫvLw⏚╅ᑴᜓ*+,ᓄ╅ḄKzoூ;ᫀ௃(1)NH4HCO3+NH3=(NH)CO342(2)SiO,FeO>AIOKSCN22323(3)ᐗᓄ'H3BO3᪆(4)2Mg2++3CO,-+2HO=Mg(OH)-MgCOb+2HCOb2r23(ᡈ2Mg2++2COj+H2O^=Mg(OH)2-MgCC>31+CO2T)3Bᯏூ^᪆௃(1)᪷]-.╅"2Hmᐭ⏚╄34)(ḄDE'Dᵨw⏚34ᔾᦈIK.L'_NH+NHHCO3_^(NHQ2CO3஺34(2)6MI'⏚╄34IḄFez஺bஹAI2O3ஹSiObRSFe?_X⌱ᵨḄᓄJZᑺ'KSCN,2(3)ᵫ⏚ḄV^K.L⏚ᙠ34H5ᑖWḄᵨ)(VWWᨬ¡ᡂ¢£¤⏚¥ᐰ^Vᡠ⏚'ᐗ⏚bᙠ“562”cd34pH8⁚f3.5,gḄdB(OH)4ᓄ'HBO,¨H3BO3᪆33(4)9╅5.Hᵨw⏚╄34Mg?+I(ᡂMg(OH)2-MgCCh9╅5.ḄVWI'_2Mg2++2H2O+3CO32_^Mg(OH)2-MgCO31+2HCO3_k4mnᑖ^T(ᡂ⏚╆34Xo:“3B”

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᪗11]µ¶2ZnS-BaS04(¾¿À⚞Â)ÃᵨÂ⁐Åᧇ஺:;0ᑡ=⚪_(1)ᑭᵨᯚ⁐IḄᳮÉXᑴÊËÌÍḄ⁚ÎÏÐÑX¬ឋ␺ÔÕÖ×ØÙ஺Úµ¶2᪵ÜÝ╃Ḅᯚ⁐'(ß᪗à)஺A.â⁐B.ã⁐C.å⁐D.ç⁐(2)ᨔé(BaSO)'ᧇXᢥ᝞0()µ¶2_4ᨔéᙢ—jïᧇ_ðñ+òᓄḄ.óἘõ¾öᙢ÷mᯖù2Ẇûᗞý’ÿ”ߟBaSᡂ⊈1200࠷⏚জᙠ᮱ᨔ!"#$ᯖ&'()*ឋᓄ-./#0Ḅᓄ2304)஺᮱567ᨵᨵ96:.;<=*>#?@6AᣚCDEᐸᓄ)CO2IJKLMNO6:./CDḄᓄ2304)஺ঝᙠRST6UVWXḄ“'(ᧇ”.[⍎]^_`6ᕡḄ6:.b?ឋAc஺ᐸ(de“'(ᧇ”⊤☢;ᡂhij?Ḅ(lᓄ24)஺ঞopᘤCDḄrs304)o(3)ᡂvS?JḄ7$*xᵨ“Ớ${”|}஺~g᪵v,XjỚ$.25.00mL0.1000mollTḄL-KIjᐸ.ᐭ⏚..XᨩᜐCD5min,ᨵᓫ᪆]஺xp)ᢣᑺ.#$Ḅᵨ0.1000mol-LNa2s2O3¢£.CD4)I2+2SQ¦^=21+SQ¦஺|£©ªὑNa2s2O3:¬mL஺®¯°⁐Aᓄ).᪵vS?-Ḅ7$)(ᑏ]⊤³4)஺ூµᫀ௃(1)D(2)©BaSO+4C¦^BaS+4COfCO+HO^=CO+H2422ঝBaCCh@S2'+Ba2++Zn2++SO^----BaSO-ZnSJ,4(25.00--V)x0.1000x32(3)ÂÃ⁐ÄÅ⁐-----------2-------------------x100%mxlOOOூÆ᪆௃ூᑖ᪆௃(1)ᯚ⁐CDÉÊjᓄ2Aᓄ.ËᵨᩭÍÎÏÊᐗÑÒᙠ.ËÓÏÊᐗÑᯚ⁐:

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5(4)OP¹ÚÛÜÝÞᜐᳮᑮᑴᜓCaCChᡠ◤ḄCaCL஺ä6¹ÚÛḄOPᧇᑴCaCbḄfᫀoAç*pH=5/Fe(0H)30A1(OH)334ᐰ¯pH=8.5/A1(OH)3èée஺êëᵨḄíᑺoî⏚0Ca(0H)2ï஺ூñᫀ௃(1)1.6X104(2)HCO¯+NHHO^=NHo+COj+ô0(ᡈHCO¯+NHHO;^^NHo+COo+ô0)3232öDCO¯'Ḅ^[øÃCaSCUḄÍᓄ(3)®[\É(NH4)2CC>3ᑖeDúᤅÇû᳛(4)ᙠᤅǤᔣüýî⏚ᑖᢇDᐭOPÿ
ᑮᔣᑖᢇᐭCa(OH)ᵨpH!pH,#pH$%5~8.5*2)ூ,᪆௃ூᑖ᪆௃,,c(SO1-)(1)34CaSO(s)+C0,2'(aq)u1CaCCh(s)+SO2-(aq)Ḅ@⊝Bᦪ⊤EFGH-~IJᔠ44c(COj)CaSOLMCaCOḄK.pPQ஺3(2)STUNH4HCO334ᡂ(NH)2cO3;ᐭSTᢓᑴ(NH)2cO3ḄT,஺44(3)[\](NHQ2cChᑖ,_CaSO4`ᓄ᳛cd1eᢝ[\ஹ34*hஹ34ᱥM!ᑺḄk,l]CaSCU`ᓄ᳛ᓽl]34o᳛Jᔠ34Ḅᱯqrst34o᳛Ḅuvᑖ᪆஺(4)᪷xyz{|Ḅᡂᑖ}~ஹᡠ|CaCChஹSiO,AI2O3MFez஺.11TḄ2|GᧇᑴCaCb!᪷x⚪ᑺ✌ᐜ⌕ᐭ⏚CaCOaᐰ`ᓄGCaCb*AI2O3ஹFezCh`ᓄᡂAlCbஹFeCh◀SiChJᔠ⚪},ᑭᵨCa(OH)2¡⁚pH◀AMF£஺ூ¤,௃(1)34CaS04(s)+CO2-(aq)=-CaCC>3(s)+SO4”(¨)Eᑮ@⊝*!3c(SOj)c(Ca2+)rKsp(CaSO4)4©---------------------------------------------------------------------.......................................=______________=1r)XI(Icc(CO1)c(Ca2+XKsp(CaCO?)3xlQ-9'(2)NH4HCC>3ª%⏚FUST34ᡂ(NH4)2CC>3,34Ḅᓄ«¬FGNHHCO3+NHHO-(NH4)432

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9ᜧ0◤⌕Xᐸᓄ|@A0-ᑴpHᑮᓄ|O7ᐭ<=ᣚCd,ᨬ2X7ᵯEᑮ<0XE\஺Eq1ᵫ<Ḅ⌕ᡂᑖ)ZnS,ᯏs
⌕Ḅᓄ
5An,1ᐔZnS+-0,Zn0+S0,஺22.ᵫF⏚,601Ḅ⌕ᡂᑖ◀SiO2᜜ᨵPbS04⌕¡¢|@A0◤⌕f⁚67ḄpH,£,¤¥ᐭ¦ᩖK0ᡠ¨◤⌕ᑭᵨᓄᩖKFe2q367ḄCd?';ᵨ<=◀>0Ḅ@A
Zn+Cd?=Zn~Cd஺4ᵯEF⏚<67ᑴᜓᓫK

10Q¸x.(4)%஺2¼UE⏚Ḅᨵab½ᓄlCC>2ῃ◀&®-¿À!,ᑖ஺®ᢗᧇÃஹ®Å,Æ®ÇSḄᨵabῃ◀᳛᝞Èᡠ஺80࠷Êῃ◀᳛ËᓄḄÌÍx஺(5)ῃc&CaCChÏÐÑ&ᐙᑖÊÓᨵSOxÔᶇ&ÌÍÖ.×ᐭBaCC>3'"L#ÚÛcḄῃ◀᳛&ᐸݪ·Q¸Öo(6)ßagᡠ7ᑴE⏚&〉Ñâã§&(äå✏çᲩ;êᢣᑺ&ᵨbmoLL-NaOHòóôõö÷,ᡂNa2Hpe)4&úὑNaOHòemL஺7ᑴE⏚H3PO4ḄüÑᑖᦪÖ஺(ýwxH3Po4᥅ÿ
98g-mol')ூᫀ௃(I)Ẇஹ(2)জ<ঝ᪶ᵯ₹ᦪPVS,!"#$P>S,&ᵯ"'(PVS,)*+ឋPV6(3)2Ca(PO)F+10HSO|+5HO10CaSO•0.5HO+6HPO+2HF543224234(4)80°C>?@஺2ᑖCD᳛ᜧ?GHI℉KL(5)CaSOMNBaCO+SOP*+2HPO^=BaSO4+COt+HO+2HPO43342224
0.049bc(6)------aூC᪆௃(1)Ẇ'XᜧYZᱥḄ]^☢`?aYZD᳛??ᓣcdHaYZD᳛Pefg'aYZD᳛ḄhiᨵkẆஹ஺(2)জ᪷n“p⏚ᑴs⏚”ḄuᑖCYZvw?⏚ឋkHPOS,&ᵯ"'(P

11ᑁᨵῃ◀᳛XᜧP80࠷>dHᓣc?@஺2ᑖCD᳛ᜧ?H2O2GHI℉KL?YZD᳛᠒?ᩩ¢ᨵῃ◀᳛£஺(5)ῃ¤?CaCCh¦§
?ᐙᑖYZ>©ᨵSO42ªᶇ?!¬kCaSO4MN®஺ᐭBaCCh°±²³´c¤Ḅῃ◀᳛?¬BaSCU¶N®?ᐸgSO/BaCOsᡂ¹¶NḄBaSCUCO?,H3PO4Ḅ⏚ឋpH2co3?ᙠ¼⏚gCOj2¾ᓄᡂHOCO,YZḄ"f22BaCO+SO2+2HPO4=BaSO+COt+2HPO+HO«34342242(6)ÀÁÂÃᡂNa2HpO4?ᑣÇὑḄH3PO4NaOHᱥḄ
É1k2,n(H3PO4)=-n(NaOH)2bebe49bc—xbmol/Lxcx103L-----mol,m(H^PO)~-----molx98g/mol=-----g_0.049bcg,Ðᑴ⏚gH^PO442200020001000Ḅ
ᑖᦪ0.049bc஺aÃÑkÒ⚪ÔÐÕÖ×ᑴᜓ⏚ḄÙÚefÛÜ?ὃÞßàᓄYZD᳛Ḅ¬zஹ“p⏚ᑴs⏚”ḄuᑖCYZvwஹᐗzᕜ|wஹᢣÁâ᛻fḄäᑏஹᱥæ
Ḅçèé஺C⚪êëᑭᵨᡠîïðᔠefᑖ᪆?᝞ó(5)ôõöῃ¤ḄYZᙠ¼⏚g±÷Ḅ?BaCChᡈCaCChgᐗzᨬÂúCO2Pó(6)ôgH3PO4NaOHᱥḄ
ÉḄûÁé஺8.[2018ýþᔁ]
(⌕ᡂᑖAI2O3ஹFeO>SiO,FeS2⏚)"ᧇ$%232&'ᓄ)*+FeOḄ.ᑖ/012᝞453467ஹCaONaOH<=FeS2>=so2(1)ᯏAB2ᙳD&%SO,ᵨNaOH<=ᔾᦈBSOḄHIJ2K22(2)LMl%CaOPLMCaOḄQᯏA$ᐸS◀᳛VWXYᓄZ[᝞⚪16^ᡠ`஺8o%/6o魅4o小愎2O02004006008001000ᯏAWX/࠷⚪16^de5fᦪ⏚ḄᑖhWXij600࠷lmnopᯏAqQrᐗtuvஹsc஺,S◀᳛=(1-{|$$}p~2)X100%ᯏAᑠQrᐔtuv

12জPLMCaOḄQᙠj500࠷ᯏA$S◀Ḅᐗt⌕ᩭj஺ঝ700CᯏA$LMl%CaOḄQS◀᳛PLMCaOḄQS◀᳛$ᐸ⌕"(3)ᔣ“B>”+ᑮḄ>=rᐭBCO2,ᐗtᙠḄKᵫ_______________(ᓄK)ᓄ_______________(ᓄK)஺(4)“B>”+ᑮḄ>rᜧḄFeO»FezCh¤FeS2¥ᔠqᙠ§'ᩩ©4ᯏA%ᡂFe3O4SO?$23ᳮ¬®ᐰ°{±ὑḄn(FeS)5n(FeO)=஺223ூµᫀ௃(1)SO+OH_^=HSO-23(2)জFeS2ঝᐗtᓄCaSO¸ᶇᙠQr4(3)NaAlOA1(OH)32(4)1516ூh᪆௃(1)BSO2¤NaOH°{%ᡂNaHSOsHO,°{ḄᓄJ2KSGh+NaO+NaHSCh$H2IJ2KSO+OH=HSO,23(2)জ᪷¾⚪¿Àe$fᦪ⏚ḄᑖhWXj600࠷,PLMCaOḄQj500࠷ᯏA$S◀Ḅᐗt⌕ᩭjFeSz஺ঝLMCaO,CaOÁÂÃᵨ$LMCaOÄ%Ḅ°{2CaO+2so2+O2=2CaSC)4$᪷¾S◀᳛ḄÆ$700࠷ᯏA$LMÇCaOḄQS◀᳛PLMCaOḄQS◀᳛Ḅ"5ᐗtᓄCaSO4ᶇᙠQr஺(3)“ÈÉ”AI2O3ஹSiChᓄ”+ᑮḄ>=rᐭBCO2,23CO¤NaAlC>2°{%ᡂNaHCChA1(OH),°{ḄHIJ2KCO2+AIO2+20=~1(OH%I+HCO,233ᓽAlᐗtᙠḄKᵫNaAK)2ᓄAl(OH)3஺(4)FeO¤FeS¥ᔠqᙠ§'ᩩ©4ᯏA%ᡂFeOSO?,°{ḄᓄJ2K23234FeS+16FeO35SLllFe3O+2SO2t,ᳮ¬®ᐰ°{±ὑḄn(FeS)5n(FeO)=1:16஺224223ÐÑ5Ò⚪
"ᧇ%&'ᓄFe.QḄ12ÕÖ$ὃØ12Ḅᑖ᪆$FeஹAlஹSᐗtnᐸ4ᓄᔠᱥḄឋv$^ÛḄᑖ᪆$*ÜÝÞßḄàá$ᢣãä᛻4J2KḄæᑏ஺᝞NaOH<=ᔾᦈBSO?ᑣ&ᱥHSO-,FezQ,¤FeSz¥ᔠqᙠ§'ᩩ©4ᯏAᑣéᨵ'7Ã'ᓄᑺì◤îï°{ᱥnᵨḄP3ð஺9.[2018ôõᔁ]
CLஹNaOHஹ(NEhMCKùt)SO?"ᧇúᑴᜓᵨý-þ஺(Êᔠÿ0
Na2so3,

13ᐸ⌕᝞:NaOHso--►NajCOjߟ►IV——►Na2sChᔠজC12+2Oir^=Cl(y+C#+H2O%&'()஺ঝN2Hr,஺-./118"C,ᐹᨵ234ឋ678NaClOᒓ:();ᡂN2஺(1)IᑴᜓNaClO?6@ABCD40࠷,028NaOH();ᡂNaCICh
NaCl,ᐸFGHIJKLMᑴAB◀ᵨPQ᜜63◤TUḄWX%஺(2)IIᔠᡂNHHOḄYZ᝞⚪19\Tᡠ_஺NaClO`ឋ8ᙠ40࠷b()242cd?ef6ghiᓣAk110࠷lm()஺LnDopᧅorḄ%KsᵨtuvḄwḄ%.(3)IVᵨᵫzᑮḄ|}~Na2cᑴᜓNa2s(LH2so3ஹHSOKஹSOpHḄᑖ᝞⚪19\-2ᡠ_6Na2sChḄB᝞⚪19\-3ᡠ_)஺5040302010⚪19\-2⚪19\-3জᤅᔣNaCOLnᐭSOᑴᜓNaHSO஺L?nS0Ḅ23232Jo

14ঝ⊡ᐙ᦮ᵫNaHSChᑴᜓNa2sChḄHᫀ6ᵨ⏣¡¢6£¤6¥¦ᒹY஺ூ©ᫀ௃(1)3C1+6OH=5C1+C1O+3HO°᠒nᐭCb232(2)NaC10`ឋ³ᔠ὏Ḅᢵ¶(3)জ·ḄpH,@pH/J4,nS02ঝᤅᔣNaHSChLorNaOH6·pH,pH/J10?6orNaOH6r'º»kᨵᜧᨔ¾᪆À6ᙠÁÂ34࠷ᩩÄÅ'DÆூ᪆௃ᑖ᪆ILCk8NaOH()ᑴᜓNaClOKJILḄ()JNaClO`ឋ8()ᑴᜓᔠῙ,KIllᑖFÀᔠḄKIVᵫSO?8Na2co3()ᑴᜓNa2so3஺Ï(1)ABCD40࠷,Cl8NaOH¶;Ðᓄ();ᡂNaClO,.NaCl
HO,()ḄᓄÒHI22J3cl2+6NaOHÓ5NaCl+NaClCh+3H2O,FGHIJ3C1+6OH=5C1+C1O+3H0eᵫÂCl8NaOH2322Ḅ()J&'()6JÕ³NaCOjḄ;ᡂ6)MᑴAB×CD400Cஹ³᠒()i᳛KLMᑴAB◀ᵨPQ᜜63◤TUḄWX%°᠒nᐭC&(2)nLḄ()JNaClO`ឋ8()ᑴᜓᔠ▢6ᵫÂᔠᨴÝᐹᨵ234ឋஹ78NaClOᒓ:();ᡂN2,JÕ■ᔠßàᓄ6)⌲oorNaClO`ឋ6ᡠbnDopᧅorḄ%NaClO`ឋ஺NaClO`ឋ8ᙠ110"Clm()6N2H4•ä0-./118æ6sᵨtuvḄwḄ³ᔠçḄᢵ¶஺(3)জᔣNa2co3LnᐭSO?ᑴᜓNaHSCh6᪷é\_pH/J4?6HSOKḄ᥅ëᑖᦪᨬᜧ6ᑣḄpH/J4?nᐭS02KL?nᐭSO2ḄJ·ḄpH,@pH/J4,nSO”ঝᵫNaHSChᑴᜓNa2so36✌ᐜ⌕rᐭNaOHòNaHSChóᓄJNa2so36᪷éôõö÷8pHḄᐵù6rᐭNaOH)ú⁚ḄpH/J10K᪷éNa2so3ḄB6ABÁÂ34࠷᪆ÀNa2soüÂ34࠷᪆ÀNaSO•7H2O,ᡠbþNa2s஺3Lÿ
NazSChᑴ34C஺ᵫNaHSCh23ᑴᜓ
Na2sChḄᫀ!ᤅ#!ᔣNaHSCh%&'NaOH)*+pH,pH/102)34&'NaOH)'5678ᨵᜧ+ᨔ<᪆>)ᙠ34࠷ᩩBCD5EF)ᵨH+
I⏣KL)MN)OPᒹR஺STU⚪WᑴᜓᔠYZ
NaaSChḄ[\]<)ὃ_ᩩBḄᑴஹ'ᧇḄbஹcᳮḄᳮeZᫀḄfgஹhi⊤klmḄnoZᜐᳮᵨqr஺sStᫀḄfg)ᙠfgᫀ2⌕vwhE\ZcᳮḄᳮe)xᔠi⊤klmyzᑖ᪆|⚪⌕S஺

1510J2017᪗1w⏚tw⌕Ḅᓄcᧇ)ᵫᑴᜓ)Ḅ⌕ᡂᑖFeOCnCh)ᨵấஹkᩖ஺ᑴᜓ[\᝞iᡠ:1|জᰚஹ!ᓄঝ$%1_____'2NaCO,NaNO----&'ঞ*pH=7233'(1&+ᜓ'(3KzCr2஺?§|Cᑡ©⚪:ª1«¬জḄ⌕¯FeOC^Ch+Na2co3+NaNC«3´-->NaCrO+FeO+CO+NaNO242322¶·¯¸¹ºFeOCrzCh»NaN03Ḅ¼ᦪ¾஺¿¬ÀqÁᵨ◌ÃÄᘤ)cÆtª2«FÇ1%+ᨬÉḄÊËᐗÍt
FÇ2Ḅ⌕ᡂᑖtÎấᩖ஺ª3«¬টÐF2ḄpHÁÑÒªÓ“ᜧ”ᡈ“×”«)cÆtªᵨØÙ\b⊤«஺ª4«ᨵᐵᱥḄe᝞iᡠ஺ᔣ“F3”%'ᐭ〉+KCLßà67)áᓾxᨔ)EFᑮKzCrzO?ä<஺áᓾᑮªÓ᪗å«ᑮḄæ252஺7ä<èéᨬÉ஺(0.3自举幅友解a.80࠷b.60࠷c.40࠷d.10࠷¬ঠḄ¯ðñt____________________ª5«òᔆᵨwikgøªCr2C>340%«ᑴᜓKzCrzO,ᨬúᑮèémkg,è᳛2ூ|ᫀ௃ª1«27◌ÃᙠCþ»Na2cCh¯ফAI(OH)3(3)2CrOj+2H+=^C"O+H2஺(4)dᑖ190zn(5)2xlOO%147/#L

16ூ᪆௃+I,FeOCnCh012ᑺ45ᓄ7ᱥ9Na2CrC,42~ஹSiCh"CrOZ4⁚i{pHlmnmq29A1+OH,3rấᩖ஺+3,m{2⁚pHḄḄ0Vi{Ḅ⏚ឋ4pH9i{hᙠ2஺<,42-+24=5072-+Q0,ᜧi{hH+4Lo⊝ᔣ@4Vi{hḄ஺+4,ᵫLM,ᙠ10࠷¢£`,ᑮKzCgChḄ§¨ᨬu2KCl+Na2Cr2C»7=K2Cr2O71+2NaClḄª«9ᑖ஺+5,᪵hCr2+,3Ḅs9gx40%kg,ᑣ¯ᡂK25O7Ḅᳮ²s9gx40%kgx³4ᑣᡠ7Ḅ7794190”#᳛9in,kg-?+x40%kgx—,x]00%=-----x100%஺W|152147gூ»¼½¾௃ὃÀÁÂᑴᜓḄÅÆÇÈ4É5ᓄ12ஹÊEËÈÌÍஹΪkḄᵨÏᔠᱥḄᑖÊZÑÒ4⚪`⌕ÕÖ᦮ØÇÈoÙÚÛᑖ᪆4ÖÇÈh=ÜØḄ2ᳮ<ÝÞḄḄ⌕ᳮßà஺11.[2017ãä᪗I]æ4ç5஺|2?1@2Ḅ-4᳛A70%E1ᡠFᵨḄ./ᩩIAo

17100(2)“⏚-”N1OP⌕RTiOCTUVWᙠ1ᑏ4Z[\[Ḅ]^_`V__________________(3)TiCh-HhOdஹf\[40minᡠi./67᝞%⊤ᡠ;)k/࠷3035404550TiOxHOoᓄ᳛q929597938822ᑖ᪆40࠷ETiC^HkOoᓄ᳛ᨬḄyz__________________஺(4){2P5஺|50TiḄᓄᔠ~A+4,ᐸ0ḄᦪA஺(5)“ঝ”0c(Mg2+)=0.02mol-LJi,ᐭ⏚(1)1Fe1+ាᐰᓽ0c(Fe3+)=1.0x10-5mol.1EᔲᨵMg3(PC)4)2¡ᡂ£(ᑡV¤¥)•FePO§ஹMg3(PO4)2ḄKspᑖ«A1.3x10-22ஹi.0xl()-24஺যᑏ4“ᰀঝ"0ᵫFePOᑴᜓLiFePC>4Ḅᓄ±_`V஺4ூ$ᫀ௃(1)100࠷ஹ2h,90࠷,5h(2)FeTiO+4H++4C1=Fe2++TiOCl)+2HO32(3)µ¶40࠷,TiOxHOoᓄ\[·᳛¸kᓣº»¼40࠷,ᑖ½df¾⍎4ÀÁ22TiOxHOoᓄ\[·᳛%Â22(4)41a1n-22x(5)Fe3+ាᐰE1c(PO»Ã--------molL-l=1.3x1017mol-L-1,c3(Mg2+)x2(PO))=c1.0x10-(0.01)3x(1.3x10l7)2=1.7xlO4°4)2஺4(6)2FePO+Li2c0.3+HCOI-^-2LiFePO+HOT+3co2T42242ூ½᪆௃(I)ᵫ9;>?1“⏚-”E2ḄÌ4᳛A70%E1ᑣ[⌱Ïᙠ1()0࠷ஹ2h,90࠷,5h%ÐÑ»(2)“⏚-”EᵨÒ⏚½FeTiCh¡ᡂTiOCrE1Ô¡\[Ḅ]^_`VAFeTiO+4H++4Cr=Fe2++3

18TiOClj+2H2O»(3)kÕÖ·᳛ḄP⌕z×1ØH2O2ᙠ%᧕ᑖ½ஹf᧕ᢵÔ1ᓽyzµ¶40C,TiO.rHO22oᓄ\[·᳛¸kᓣº»¼40C,ᑖ½df¾⍎4ÀÁTiCh-xH?஺oᓄ\[·᳛%»(4)LiTiO+LiA+1~10A-2~1TiA+4~1᪷(O))0ᐗ×Ý-1~1ḄᦪAx,25l5᪷Þßàᓄᔠ~áᦪA0,>?(+l)x2+(+4)x5+(-2)x(15-2r)+(-l)x2x=0,½i)x=4K(5)Ksp[FePCUl=c(Fe")xc(PO))=1.3xl0'1ᑣc(PO^")—=1.3x1017mol/L,QJMg3(PC)4)2]=c-3(Mg2+)xc2(PO))=(0.01)3x(1.3x1017)2=i.69x10^Cl.OxlO24,ᑣâ஺(6)%FePO&dLi2cChH2c2஺4ãᔠä>iLiFePO§1᪷Þᵯ^æឤy^æឤ>i\[Ḅᓄ±_`VA2FePO+Li2co3+HCO4=^i=2LiFePO+H0t+3co2b42242ூèéêë௃ìíî`⚪1ïðᓄì¡ñ`0ḄP⌕¡ñ▤óᓽ¡ñî`ᵨ᪾9UV⊤;4ᩭ1ö᪷Þ¡ñî`0ᨵᐵḄᓄ±?øùù'1Uᡂdᓄì¡ñúûὶýḄᓄììíþ⚪஺ᑴᜓÿ
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19HNCÍ3Îf§ᓄAg,+ÈnÉᱥḄ-.ᑖ᪆HNOÏÐNaClOḄÑ23Ò3ÇÓÔAgḄlᦈ᳛◤“©H”Ḅ©¬ÁÂÖ×Ø஺Ò4Ùḕᶍ“©I”ÛÜᔣÞᓾZḄÈnàᘤâÅ10%¤¥ᑣ◤⌕äŤ¥Ḅᵨ◀æNaClO$NHyHoOÈn᜜ÒÌᩩ|NaC10$NHHOeÈnÍbæÇ஺332Ò5Íç%è+“©n”ZḄ©¢éêᓫìAgḄCEᫀuÒCíîᵨḄmᑺᨵu2moi[T¥ᔠῙ¡¢1moLL-H2so4Í஺ூKᫀ௃Ò1Í¥óű24Ag+4NaClO+2HO^=4AgCl+4NaOH+Ofôõ"ö÷§ᓄᱥÒᡈNOஹNO,⌼ᡂ9᛻úû222Ò3ÍüÖ×ZḄ©¢ᔠØᐭ©IIḄ©¢Ò4ý©ᣵḄ¡¢ôÿ
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