2022-2023学年中考数学模拟预测试卷解析版

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22200
Ḅᩩ22.᝞C~Qᨵ4ᕜ10~ᑁᨵᨩờᵫᔣᙠB5]Aᙠᓅ60஺ᔣ.12~ᑮC5]Aᙠᓅ30஺ᔣ.᝞ᦋᔣᔣᨵeᨵ¡ờḄᓻ◅¤¥¦§ᳮᵫ©ὃᦪ8Z1.73ூὃ5௃TB8o«j¬jAḄᵨ-ᔣj®⚪.ூF⚪௃318ᦪAᔠ>5548°Ὺ¬jAI«j¬jA>55E8o«j¬jA³ᐸᵨ>648µ¶«N>688·¸¹º>698ᵨ¼½.ூᑖ᪆௃¾¿AN,ᵫ⚪¼R]À4BE=60஺ZACD=30°,ÁÂ]UN4BC=N&1C=3O஺ÆÇÈC=BC=12,ᙠᙠRtA4NCQᑭᵨ«j¬jAḄÌjᐵÎÏU4VI10~nÐᓽR.ூop௃o8eᨵ¡ờḄᓻ◅>ᳮᵫ8᝞CÑ54¾ANLBCÓBCḄÔÕÖÆ5N,23/35

23ᵫ⚪¼]N4BE=60஺N/CD=30஺,1^ACN=60°,4BN=30஺.•/1n=ಘ4c=30஺,1BC=AC=12,ᙠRtZkANCQAN=ACcos60°=12xØ=6Â,2•⏀N=6Û10.38>10,.•eᨵᓻ◅.23.᝞CÜABCQN4CB=90஺B஺%ÜABCḄjÝᑖÖS5஺%ᙊi஺஺%Þß¾஺஺IÖàACÓÆ5D.(1)Ïá8%஺஺ḄᑗÖ>(2)ãtar%=^4D=2,ÏB஺ḄÕ.ூὃ5௃KF8jÝᑖÖḄឋå>M28ᚖßçᳮ>M58ᙊᕜjçᳮ;ME8ᑗÖḄᑨçIឋå>T78o«j¬jA.ூF⚪௃55A8IᙊᨵᐵḄéêᐵÎ>678ëᳮìí.ூᑖ᪆௃(1)Ñ஺¾஺Æð᪷jÝᑖÖḄឋå]ᑮOH24/35

24=oc,᪷ᑗÖḄᑨççᳮᓽR]ᑮñ>(2)ò஺஺ḄÞß%3x,óI]0H=0D=0C=3x,ᙠo«j¬jAᓽR]ᑮñ.ூop௃(1)á§8Ñ஺¾஺Æð•%CB=90஺1OC±BC,•.8஺%ḄjÝᑖÖ0H1AB,1OH=OC,ᓽ0H%஺஺ḄÞß'.DH.LAB,.2B%஺஺ḄᑗÖ>(2)o8ò஺஺ḄÞß%3x,ᑣ0H=0D=0C=3x,ᙠRQ49/7Qõ1114=ö4.23AH4•3x-AH1AH=4x,-AO=7OH2+AH2(3X)2+(4K)2=5x,5D=2,1AO=OD+AD^3x+2,.'3x+2=5x,.'x—1,1OA=3x+2=5,OH=OO=OC=3x=3,25/35

25.2C=OZ+OC=5+3=8,ᙠRtA4BCQ42114=¸AC."BC=AC»tanA=8x2=6,4>^^=A/0C2+BC2=A/32+62=3^'24.ùúû├ýþ"

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”Ḅᡂ16ᐗ├ᓫ20ᐗᜩ80.᪷!"#$%&'(├."#)*+᧜-├ᓫ(.0.5ᐗᑣᜩ1202├ᓫ3.4ᡂ567"

”Ḅ├ᓫx2ᐗ5ᜩḄ├:y25.215<ᜩḄ├:y25=├ᓫx2ᐗ5>?Ḅ@ᦪᐵCDE225├ᓫ1Fᐗ├"

”ᜩḄ├ᑭHᨬᜧᨬᜧᑭH1FᐗKூὃN௃HE-RS@ᦪḄTᵨ.ூV⚪௃124-├Y⚪E533-[S@ᦪ\ᐸTᵨE535-RS@ᦪ^_\ᐸឋaE536-RS@ᦪḄTᵨE66-bcdeE69-Tᵨgh.ூᑖ᪆௃215├ᓫx2ᐗ5├ᓫ(.0.5ᐗᑣᜩ26/35

26120(├ᓫ3.4ᡂ)ᑣst(.u1Fv0.50.5ᐗwxy20ᓽ1Ḅᦪᯠ|}l80ᓽ~ᜩḄ├:y(2)7ᜩḄ├ᑭHwᐗ᪷!ᑭH4ᜩḄ├:xyḄᑭHᑡwᐵ4xḄ@ᦪᐵCDᐸᑏᡂ⚔NDᢥ᯿RS@ᦪḄឋa~ᫀ.ூ௃-(1)ᵫ⚪g~-y=80+20x20^,0.5.y=-40x+880E(2)7ᜩḄ├ᑭHwᐗᑣᨵ-w=(-40x+880)(x-16)=-40(x-19)2+360,\a=-40<0,.•RS@ᦪ^_ᔣ.•x=19wᨵᨬᜧᨬᜧ360ᐗ.-├ᓫ19ᐗ├"

”ᜩḄ├ᑭHᨬᜧᨬᜧᑭH880ᐗ.25.᝞^ᙠ4BCD4஺=8(k>0),NE£¤¥¦§¤lḄ[v¨N©ª4E,«N4¬®¤DC4NF.জ᝞^1,5k=l,ᑣ±=4E>?Ḅᦪ:ᐵC£”=AEEঝ᝞^2,6´1,µᑨ·/F=4E>?Ḅᦪ:ᐵCᑏ¹º»¼½E(ᵨ¾kḄD¿⊤Á)஺640=248=4,©ªBD4F4NG,©ªEG,CF=127/35

27

281^EAB=ZE40,1AEAB^\FAD(A4S),1AF=AEᦑᫀ-AF^AE.(2)AF=kAE.¼½-••±àABCD£.•ಘ0=஻BC=4DF=90஺1^FAD+ZFAB=90°,'AFLAE,."4F=90஺.•ಘB+ZE4B=90஺1^EAB=ZFAD,•.”BE+4BC=180°,.•aBE=180஺-yBC=180஺-90°=90°,1^ABE=ZADF.1AABE^ADF,•ABAE•■»-=--,ADAFMD=kAB,ëì*XD-k.AE1*AFV1AF=kAE.(3)-জ᝞^1,NFᙠ4l,29/35

29•.±àABCD£1AB^CD,AB/CD,•⏀O=2AB=4,1AB=2,.8=2,6=1,1DF=CD-CF^2-1=1.ᙠRt^AOrZADF=90°,'AF=7AD2+DF2=A/42+12=,.DF/AB,4DF=4BA,4FD=4AB,:AGDFsGBA,.GFDF1,GA-25F=GF+/G,1AG=^=^Jn-•.ÎABESA40R,AEAB2_1'AF-AD7[ó1AE=^=^x.Jn=^-.ᙠRtZkE4GNE4G=90஺,30/35

30•ộ=|/J
õ2+ö2=ঝ᝞^2,NFᙠ஺CḄ¦§¤lDF=CD+CF=2+1=3,EᙠRSAOÞZADF=90°,•^=VAD2+DF2=V42+32=5•,.DF/AB,,14AB=4FD,4BA=4DF,:AGBs&GD,•AGAB__2•ẑßT\GF+AG=AF=5,1AG=2,•.Î/BES/X/DF,.AEAB21'XF-AD-4-2•NE="iẆᔁx59ᙠRtAE4GNE4G=90஺>'EG=VAE2+AG2=^(y)2+22=^-.±὚,•]!ᡈ.26.ᙠ#☢%&ᙶ᪗)*ᱥ,y=QX2+bx-312/(-3,0),B(1,0),4y5672C,⚔2!2D.31/35

31(1)B*ᱥ,ḄD᪆FG(2)2P!%,CD=ḄIJK2LMBCজ᝞P1,QᔲSᙠ2P,/PBC=NBCO?TSᙠBUᡠᨵXYᩩ[Ḅ2PḄᙶ᪗GT\Sᙠ]^_ᳮᵫGঝ᝞P2,2Pᙠx5=cLMP46*ᱥ,72MNP4B=ZBC஺,2Mᙠghi▲*ᱥ,=LMMN,kl4NM=45஺m]%Mூὃ2௃HFstuvᦪᔠ⚪.ூz⚪௃16s|5⚪G65sᦪ}ᑖ᪆.ூᑖ᪆௃(1)y=ax2+bx-3=a(x+3)(xT),ᓽBDG(2)জᑖ2P(P)ᙠ2CḄஹ2Pᙠ2CḄ,ᑖBDᓽGঝ_(44S),ᑣ2M(m+n,n-m-3),ᑭᵨ2Mᙠ*ᱥ,=4R=NR,ᑡUFᓽBD.ூD௃Dপy=ax2+bx-3=a(x+3)(x-1),DsQ=l,32/35

32ᦑ*ᱥ,Ḅ⊤F!sy=x2+2x-3@G(2)ᵫ*ᱥ,Ḅ⊤F2CஹDḄᙶ᪗ᑖ!(0,-3)ஹ(-1,-4),ᵫ2Cஹ஺Ḅᙶ᪗%,CDḄ⊤F!sy=x-3Gtan/¢஺=£¤ijcosN8CO=_G3A/10জk2P(P')ᙠ2஺Ḅm■:ZPAB=ZBCO,ᦑP'B®5,ᑣ2P'(1,-2)Gk2Pᙠ2CḄm¯%,PB6y572H,12“±HNLBC>ஹN,,14AB=ZBCO,1ABCH!Ὺh&³¤IµBC=2CHcosB0=2xCHxᢣ=^32+12,DsᑣOH=3-C”=Uᦑ2”(0,-·ᵫ2BஹᨴḄᙶ᪗%,Ḅ⊤F!s_/=⊤-¹ঝ)33/35

33ὶ»জঝ¼Ds½“5,[y=-8ᦑ2PḄᙶ᪗!¾1,-2ᡈ¾-5,-8G@'1ZPAB=ZBCO,¿tanZBCO=£3ᦑ¯%,APḄ⊤F!sy=lx+s,À2AḄᙶ᪗Áᐭ=F¼D3sS=l,ᦑ%,5PḄ⊤F!sy^lx+1,ὶ»জঞ¼Dsᦑ2N
1,9;¯ZMMNḄ᜜Mᙊ!ᙊR,P2k4NM=45஺mᑣ4RM=90஺¯ᙊÆRḄᙶ᪗!¾m,n,•.2DM+ZMRH=90஺ZMRH+4MH=9U°,4MH=4AR,&R=MR,zAGR=ZRHM=90஺,1AAGR^\RHM(A4S),1AG^m+3=RH,RG=-n=MH,.•2MCm+n,n-m-3),34/35

34À2MḄᙶ᪗Áᐭ*ᱥ,⊤Fsn-m-3=(m+n)2+2(m+n)-3ঞᵫ⚪ÇsAR—NR,ᓽ(m+3)2=(m-A)2+(È)2ট39f2in=—ὶ»ঞট¼DsG0I9ᦑ2M(I±-35).3935/35