模拟电子技术基础课后习题答案(吴友宇版)

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-«4°½:;÷ᨵᑁy&,nRúû5L5Ḅ÷ᵯvDᜧôᦪ|A2ý|A
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28ভ"AQ=ভ•ᜓT,U|=ᡷQRi=R//R//r=4kQ//6g//1.4kQ=0.88kQblb2beᓽAJ&=0.88ᦇ஺04ᜧᘤ:ᵯ78@4ᜧᘤᵯ78ḄE^(ᢥ`=1.4AQ)஺3.6.24ᜧᵯ"᝞⚪e3.6.2ᡠgVcc=12V,Rbi=15kQ,Rb2=45kC,&=RL=6k஺R=200/2R,=2.2஺ᨔijḄp=50%=300/2,V=0.6Vᔜᵯᢙpel2B£Uᶍrs஺(1)t☟᝱wxyA(/cQ=?WcEQ=(2)~ᐸᓄḄhᦪᦔᵯ"ᵯ4ᜧᦪᐭᵯᵯ(3):ᑁ&=11,:ᵯ=10/??V,ᵯ.A„sy_Re2%⚪e3.6.2zஹV”•12VX15(1)=--------=3y

29_j_VBQ-'BE_3-0.6_i…tI(ஹCi=Ipn===CQEQR+R0.2+2.2ele2VcEQ=^CC=1CQ(6+%+42)=12-1(6+0.2+2.2)=3.6V(2)ᓄhᦪᦔᵯ"᝞e362ᡠg஺_K__&_A='ᓃ%+(1+஺G=",+(1+£)IEQ=300+51x¡=1.626AQ1RJ=RIIR—6km6kQ=3ᦇ஺efBR150x3Ay=-&12.7r+(l+j3)R1.626+10.2beelRi=R//R//[r+(l+p)R]blb2bcel=15//45/7(1.626+10.2)»5.8k£lR«R=6kQocR,58ব4=A.=-12.7x--—+10.84+¢5.8+1|K|=|V|-K|=10x|-10.8|=108mVs3.6.3ᑖ!ᵯ"᝞⚪e3.6.3ᡠg=12V,Rm=15ᦇ0,%2=10540,R,=lk஺,Rc=5kd&=5kQ,ᨵ¦§¨©ᙠª«¬ᵨ®ᵯ⊤°±²᩽jᔜ´ᵯ᝞⚪⊤363ᡠgµᑖ᪆ᔜᵯ"Ḅwx¶᝱ᔲᔠ〉஺ºs〉ᔠµᑖ᪆p»¼½¾¿À⚪Á᝞ÂᐗÄÅ"ᡈÇ"஺⚪⊤3.6.3È123456VB(V)00.751.401.51.4V(V)000.7000.7EV(V)00.38.512124.3Cwx¶᝱ᦑÌᑖ᪆⚪e3.6.3

30A᪷Îᵯ"ᦪpUᵯ"Ḅᦪ@“ᓃw¡23,BQ&1+&215+105V=V-V=1.5-0.7=0.8V,£eBeB£jj%E1.5—0.7.4஺=/⚕=-----=-—=>—CEQ=%C-<:2(&+4)=12-0.8(5+1)=7.2V'Vvcjoz=VrCF/IK„+VFiiOj/=7.2+0.8=8V஺ᑣ+°ÕÖ×pUx᝞⊤3.6.3ᑖ᪆஺⊤3.6.3È123456V(V)00.751.401.51.4BV(V)000.7000.7EV(V)00.38.512124.3Cwx¶᝱ØÙ⛳ÛÜÝ4ᜧØÙØÙ4ᜧᦑÌᑖ᪆ᵯ:Å"ReÇ"Rb2Å"BJT'᩽Å"RbiÅ"3.7.1Âá᩽ᘤᵨE§ឤ:ᩭ!á᩽ᵯ᝞⚪e3.7.1ᡠgä(ᨔijḄ᜛=100,V=0.7V,r,=300/2,ᵯGஹQᙠçè"¬pé@Ç"஺BEbb1ê☟᝱0Ḅ/ëìíí஺2êá᩽ᘤḄᵯR“3%=8,êᐭᵯR,Û:ᵯ4ᜧᦪAஹ,ஹA4ºRL=110஺êᐭᵯÛ:ᵯ4ᜧᦪîgAឤ:ḄᱯyAçᵯ᩽ᜧð®ᵯ஺Ri*⚪e3.7.1

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33BRcᐳ'ᵯ3Av1rbe+(l+P)ReA=-0.98V1(l+P)Reᐳlᵯ᩽ᵯ3AV2=0.99¦be+(1+B)ReবR=R//R//[r+(l+p)R]iblb2bee=15/30/7(2.626+101x3.3)»9.7kQ(4)R®R=3.3kQolcL+(A”//R”R02=R=0.12kn1+᜛3.7.3'᩽]ᘤ᝞⚪D373ᡠE
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35ᓽ=/'è=128஻AV-V24-07i?=ccBE-(D■ê(ë=———1+50x3=34.59h0.128BQ3.8.1.ᵯ3᝞⚪D3.8.1ᡠE஺ìrVcc=12V,R=300KH,R=3KH,R|=0.5KQ,bclCRe2=L5KC,ᨔIJḄᵯ,Rᜧᦪ=%=60,ᵯ3GḄᵯMMíOPᜧ஺{|ᵯ3Ḅ☟᝱VWXᦪî
]ïðᑖñlᵯ᩽]òn'᩽]ḄoóRᜧᵯ3ḄᵯYRᜧZᦪ஺12—0.7c6Rᜧᵯ3Ḅ☟᝱î{|631--------------=0.034mAR+(1+)R300+61X0.5BCII=BJBI=60x0.034mA=2.05mAC1Vcc5஺7=(IB2+1Cl)Rci+(1+஺2)12ô02'=Vcc-OfRa=12-5x3=0054mA,B2R+(l+p)R3+61x1.5C12e2I—஺2ὡ2=60x0.054mA=3.27mAC2VcEQl=VccTlB2+Ici)Rci-(l+Pl)lBlRel=464VVcEQ2=Vcc572ë(62_(l+02)1B2Re2=2.12VRᜧᵯ3ḄᵯYRᜧZᦪ{|:2626r=200+—=0.96kQr=200+—=0.68kDbelbe2ூBl1B2R=r+(l+P)R=92.2kQi2be2e2A=-PJ—R஺?——=-5.54,Vil÷ø1+(1+஺ù29óRᜧᵯ3lᵯ᩽]
4/2=-A--0.98rbe2+(1+22)2

36A=Avii•Avi2=(-5.54)x(-0.98)=5.41,Vj6óRᜧᵯ3n'᩽]
A.2=O+P)&2=0.99,ú2+d+ಘ&2A=Avjj•Avi2=(-5.54)x0.99=—5.5஺Vi3.9.1üRᜧᘤḄRᜧZᦪ4ஹ4ஹA,ᙳ0540,ýᑖñᵨᑖ7ᦪ⊤Eÿ஺20Zg|A|=54.6rfBv2()/g|A,|=54.6J510/g|Ap|=27.3d83.9.2ᵯḄᱯ᝞⚪3.29ᡠᑏ4,Ḅ⊤஺⚣ᵯᜧᦪ20!"43=30஺5ᡠ#4.=%106=%32('(⚣ᱯឋ*#+⚣,ᵯᜧᦪ(-180°)A=10Hz,/=105HOWZ.ᵯ/0ᐳ2ᜧᵯᡈ/0ᐳ4ᜧᵯ஺

37-3.2/ᡈ4»--------7------7-(1+5)(1+ᓃ)J1010ஹ3.9.3>ᵯḄ?⚣ᱯឋ᝞⚪3.9.3ᡠB(1)CᵯḄ὚ᔠFG(2)CᵯᵫIJᜧᵯKᡂG(3)M/=104Hz,▬T(-U<=M/=IO,,▬T(-YZU<=(1)[\▲^_⚣᳛0,ᡠ#ᵯab὚ᔠᵯG(2)[ᙠd⚣e?⚣ᱯឋ-60dB/ᓝ⚣ᡠ#ᵯkJᜧᵯ(3)M/=10"Hz,஺=%135°GM/=1()5HZ,Rp'^-270°஺3.9.4>ᓫJᐳ2ᜧᵯḄᵯᜧᦪ;200jf(1)4,”=?s=?/=?H(2)tᱯ஺\AVM\J,4TJLA„„=1000,/,=5Hz,f=10000HzH(1)uᣚᵯᜧᦪḄ⊤w4.ஹsஹs஺

38IOOO-A-__________LL_________________5_A_f(l+j^)(l+jJL4“=1000A=5Hz»104Hz(2)ᱯ᝞3.9.3ᡠ஺3.9.5xJRC὚ᔠᜧᘤ|%J}|~Jᦪ?⚣ᱯឋAy"}42(46)᝞⚪3.9.5ᡠtCᜧᘤᦪ?⚣ᱯឋAv(dB),Cᜧᘤ⚣ḄAஹ,_L?U<=ᙠ⚣᳛\CᜧᘤḄᵯᜧᦪ\4Ḅ5"⚪ᑖ᪆0⚪Ḅtᦪ?⚣ᱯឋḄFᑭᵨxJᜧᘤᑖᦪᓫJᜧᘤᑖᦪ(Tᳮ஺ᙠḄ?⚣ᱯឋ¡⌕£Iᱯ¤¥(¦/=1(/"zᡈ/'=1()6"~)¨b©Iᱯ¤¥ᓽ*஺ᵫ⚪3.9.5*ᙠ⚣eA=40dBA=20dBv}fV2••⚣eᜧᘤ

39A=A1+Ay240+20=6043ᓽ4=1000ᜧᘤᦪ?⚣ᱯឋ᝞3.9.5ᡠ᪗Ḅ஺ᵫ*M/=1()4a,-ᜧᘤᵯᜧᦪ\AzḄ஺3.9.6ᵫx®ᐰ(°ḄᓫJᡠKᡂḄRCᜧᘤᐸ²▲^_⚣᳛f=20kHz\▲^H_⚣᳛f=20HzwᔜJḄ²▲^_⚣᳛/,}\▲^_⚣᳛W஺LHf2fᙠd⚣eᑣ[1-(ߟ)2]2+(——)2=2,µ3=0.644%1¶13kHzGᙠ·⚣e¸1-(¹)2]2+(º1)2=2,µ»=f“/0.644*31Hz஺3.9.7ᙠ⚪3.9.7ᡠᵯ>ᨔ½¾Ḅ¿,=I஺஺஺be=lk஺☟᝱ᵯÂEQ=2mA,~~800pF7?=2,R[)=500kC,Rc=3.3kQ,C=10p.FosᑖÃwᵯḄ/Hஹstᱯ஺(1)ws--------«5.3Hz’2ᐔ(Rs+%)2TC(R+r)Sbe(2)wÅ}⚣ᵯᜧᦪrb'e=Æbe-Wb=09kOH=--------------------------------------«-----------------------------«316kHzrr27t[r.//(r.+Rb஻Rs)]C”2ᐔḺ஻(*%+R)lCnbebbs

40g«^-«77mA/VmmUTAusm=.
-gmRL«-76pRs+Ri%R+rsbc201g|A|»37.6dBusm(⚣ᱯឋ}?⚣ᱯឋᱯ᝞3.9.7ᡠ஺⚪4ÈÉÊË⚪ஹ⚪i.Ìᦔξᑭᵨ᜜TᵯÐÑḄᵯÒᩭÔᑴÖ᩽ᵯÂḄᜧØ[ÙÚᵯÔᑴᘤÛ஺2.ÜÝÞßÌᦔξàáâ᪕4äxPNÞåæTçᔣᵯᩭᦋuêᵯë⍝ḄíîÚḄïᐭᵯñòMOS¾ḄïᐭᵯñØ஺ÞßÌᦔξ᜜TḄ᪕-4ᵯÎÝ᪕4äḄὑôõö÷çᔣᵯøùúûᐸRGSᜧḄᱯ¥஺3.ÌᦔξÖ᩽ᵯÂᵫUᦪüÂýḄþ-ÿ
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ᨵI஺d6.P⍝-."MOSḄ89ᵯ:%ᐸ<஺N⍝-."MOSḄ89ᵯ:%'<஺7.ᦔ>ᨔ@ABCᐸDᐭᵯFGHIJKLMNOPQឋSH⛳U:VᜧMXᜧYCZH⚣᳛ᱯឋC^_`⚣᳛aMDbc᳛Cd஺8.ᦔeᵯ:fᑴᘤi,kl᩽eᵯfᑴᘤi஺9.ᦔXᜧᘤmᵨopᵯqrsᨵto:ᵯqUᑖ:ᘤvto:ᵯqwxy"஺10.ᵫᨔ@l᩽zᵯஹ{|wx}5~>ᵯᡠ$%᩽"Ḅᵫᦔ0ᨵᦪ~>ᵯᡠ$ᐸ%ᓫ᩽"Ḅ஺11.g,“᧜ᦔ᪕ᵯ:᩽ᵯfᑴYᐸᓫ%ms

41—஺12.ὑ!"N⍝MOSḄ/sᜧ,ᐸDᐭᵯFJd஺13.r"ᦔḄᱯឋ᝞⚪4.1ᡠ¡ᑣz⍝ḄᦔḄᜳ¤ᵯ:Vz4.5V,⛳UᵯIDSSz5.4mA஺p¥¦§¨⚪4.2.1©ª«"ᦔḄDss=2mA,V=-4V,¬bḄᱯឋUDbᱯឋp2®¯b⚜ᜳ¤±²஺³H᪷µ¶·H/=Z
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43³H⚪461ᡠ¡Ḅᔜᵯqaᡠ¡ᵯq#_`ᙠXᜧÌbᡠ¡ᵯq##_`ᙠXᜧÌcᡠ¡ᵯq##_`ᙠXᜧÌdᡠ¡ᵯq##_`ᙠXᜧÌ஺4.6.2¬ᑖ᪆⚪462ᡠ¡ḄᔜᵯqzᔲôXᜧ'õö÷øùúᳮᵫ஺üᡠᨵᵯ³H⚪462ᡠ¡Ḅᔜᵯqaᡠ¡ᵯq#Xᜧö÷ø஺ý%Vgs=OὑN⍝MOSᙠឤᜧ஺bᡠḄᵯᜧ!"#$%ᦔ'Ḅ☟᝱*+,-.Rs1.Ḅᵯ23435678஺9:G-S=ᵯ6>?@A஺cᡠḄᵯCᜧ!"D஺9:EF%ᦔ'C234356G᪵MOSᜐ@JKL᝱஺4.6.3%ᦔ'ᜧᘤ᝞⚪4.6.3ᡠUᓃ”=20V,⌕]☟᝱*:I=2mA,DQV=-2V,V=10V,^]Rs_RD஺GSQDse`Dᵫ⚪b+cDᓃso=ᓃ—ᓃ=&-2=-0.002x&R=1000/2=IkAs⚪4.6.3%S2=%i(%+&)=l°V10=20-0.002x(%+&)R+R=5000/2=5k஺ns+fDRD=4k£24.6.4EFMOSᔲᓫkᵨ4m5nḄopᩭrn☟᝱*s:tus^vwᵨP

44⍝EFMOS᪀ᡂḄᐳ|ᵯ}~ᔜᐗᵨ஺`D@EFMOSCᵨ4m5nḄopᩭrn☟᝱*஺9:456Ḅ᪕᩽|᩽=Ḅᵯ6ᓃ᫴=10%⊤+,w45623Ḅᩩᐜᨵ/DEFMOSḄᵯ6ᜧ@0,ᨵ᪕᩽|᩽=Ḅᵯ6ᑮᵯ6ᱏᨵ᩽ᵯ9¡G¢£Cᵨ4m5nḄopᩭrn☟᝱*஺EFMOS᪀ᡂᜧᵯ¤ᵨᑖ6456ᵯ᝞464ᡠ&ஹR2_¦23᪕᩽5nᵯ6R3Ḅᜧ?ᜧᘤḄ☟᝱*§¨©ᡠ,+,ªᜧ&«,¬ᜧᘤ®ᐭᵯ°஺±_²ᑖ³|᩽ᵯ°_᩽ᵯ°஺4.6.5⚪4.6.5(a)%ᦔ'ᜧᵯ(b)£Ḅ¸¹ᱯឋ¼½஺rᵯ°RG=IMC,RD=a=18[ᵯ¾Gஹ஺2ஹÀÁᜧ஺^ÂD(2)ÃஹR$ஹ஺3ḄᵨtusU⌕]Äs=—2VᑣH,'⌱Èᜧs`D(1)⚪4.6.5(b)ᡠḄᵯ6¸¹ᱯឋ+c⚪465(a)ᡠḄᵯÊᡠᵨḄ£Ë@NJFET($%ᦔ')஺£ḄI=5mA,ᜳÑᵯ6ᓃ,=-4V஺DSS(2)A஺Ḅᵨ>᪕᩽ÓÔAᵯÕÖ±|᩽ᵯ°ᐳ×234m᪕6ÄSQR,s

45ØᨵÙÚ☟᝱*Ḅᵨ஺C3ḄᵨÛᵯ¾ᙠÜ-ʲÝᙠᵨᩭ4Þ23᪕|ßᔣ5623ᔠ〉Ḅ☟᝱*#ᙠ-Ê&ãC3ÛäCÝᙠᨵᑭ@¬ᵯ6ᜧæᦪ஺èᓃ■sU-ZVᵫéêᱯឋ¼½+cD=2mA,ᡠ,½=ߟì=íîI2mAD4.6.6%ᦔ'ᜧᵯ᝞⚪4.6.6ᡠᵯïᦪᓃᑘ=24V,R“=56ᦇQ,R=,R=4kA%ᦔ'ḄV=-W,I=\mA#U⌕]᩽ᵯÕó=10V,c2PDSS^]RiḄ«஺⚪4.6.6`Dᓃ2==10,24-1014…I=------=—=0.25mAnDR56DôᨵD12ᓃ2,õ=%=-0.5
÷VGS=ᓃᓃ=%ᓃ=/Fø+V2=Tú=-0.25mAx&

46ø=-û=2(ü4.7.1ýc⚪4.7.1(a)ᡠᵯÊ%ᦔ'Ḅ¸¹ᱯឋ_®wᱯឋᑖ³᝞(b)(c)ᡠ஺(1)ᑭᵨ`p]`Q*#(2)ᑭᵨþᦔᵯp]`Zyஹ&_஺`D(1)ᙠ¸¹ᱯឋÊܽVGS=-4,Ö¸¹ᱯឋḄ*ᓽ஺ᙶ᪗/DQ=1mA,VGSQ——2V»᝞4.7.1(a)ᡠ஺ᙠᱯឋVDS=V-z(RD+RS)VQ=-2VḄDDDGSᩩᱯឋḄ஺VDSQ«3V„᝞4.7.1(b)ᡠ(2)✌ᐜ#$ᦔᵯ'(ᶍ)ᯠ+,-.᝱ᑖ᪆஺4=~gRo=~5mRஹ=Rg=1MX2R஺=RD=5W4.7.1(b)

474.7.2ᵯ'᝞⚪4.7.2ᡠ89:ᦔ;<Ḅ=⚣?@gmCᑏAzஹR,HAu=_gm
Rp஻Rl,IJ4ஹR,HR஺Ḅ⊤NOᑖPRi=R3+4஻R2RO=RD4.7.3R⚪4.7.3ᵯ':ᦔ;

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504.7.6ᐳ§Xᙠᵯ'¨:ᦔ;<Ḅᱯឋ᝞⚪4.7.6(a)ஹ(b)ᡠᵯ'SᦪRD=25k஺,R,=\.5kQ,R=5M^,V=15VCᵨI¯H°±¯W☟᝱\Q஺GDDI(1)I¯WI☟᝱\Ḅ²᝞4.7.6ᡠ஺³z:(a)᪷v=ᓃ>஺—%(/?"+A’)ᙠᱯឋºMN(b)½¾ᱯឋ᪷v%s=-%Á’§᩽0A½¾ᱯឋḄQᓽ☟᝱\஺ᙠ½¾ᱯឋHᱯឋºmÄᑮ☟᝱\ḄᦪVGSQA-0.35V

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