人教版2022-2023学年广东省佛山市数学升学分班真题专项练习（四则混合运算）含解析

《人教版2022-2023学年广东省佛山市数学升学分班真题专项练习（四则混合运算）含解析》由会员上传分享，免费在线阅读，更多相关内容在教育资源-天天文库。

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211.2022᧡•:᪥ᨴὃ"%!4☢ᔜ⚪஺O@!Ḅ⌕@!"_Lx+x3J-X34X17x2(&-1)X121981981717635/34\52X101-_5.(J-2"v4101582525S-12912.2022᧡•+,"O@!Ḅ⌕@!஺14x21U7dx(2)x12594157154613.2022᧡•+,"⌴¡I%!⌱£ᔠᳮḄ23%!"জᔁ41■§4ঝ7-7:17-]17ঞ%(0.25©)@y+0.22+y+l.8814.2022᧡•¯E+,"@!%!஺°Y8(1))158²52(2)25123V3⚓/Y22⚓

315.2022᧡•᫑´E+,"@!%!஺(1)64-A-Axl776(2)—X[l-=-(~#2)184316.2022᧡•¶ᩭ:+,"%!4ᑡᔜ⚪஺জ2x6x3ঝ¹º»{@ii94+f17.2022᧡•¯᧡+,"ᵨᔠ〉Ḅ23%!஺*3X3918.2022•½¾E"ᵨᔠᳮḄ23%!=¿ᑏ(1)630+2704-18X15(2)5.2----2+4.8(3)1313ÀP0.25)X(1.1X40)ভᵫÂÃম4X(Å)'7(6)137X135136136V4⚓/Y22⚓

419.2022•Ç">᪵@AB>᪵!஺7.6X35%+6.5X0.76—X21+13X—15415494920.2022•⍳PÉÊ"ῃI%!=ᵨËÌ/0Ḅ23%!஺23X0.75+27X~+50X75%—+3.+_L+O.125412812(A+A)X24XA(42X29+71X42)+35489V5⚓/Y22⚓

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6=Mx(±+?)799_47X799ফ76Ù4fD»=(75+1)xJ7!5=75X-L+1X-87575=8+—75=8૙75বÚx"=ÚÛÜ_-1--•---2-63I3.ÐÒ-^-X12-EÝ557=221X12--X755=Wx55=13ফ(2_xA)3439=(2--)-rA349=(A-.~)X.5.12128_59x128V7⚓/Y22⚓

7জ32=2x(Hl)+1544=2x315=24.ÐÒ(1)1.75X24^-X2-Q71444=_Lx(2+2-1)4714=—xo4=0(2)4.15-3.75X10%-^-4=4.15#~84=4.15-(ߟ+—)84=4.15-1.625=2.525(3)3-14-^^xA)773=3-14-(à+2)77=3-14-1=3-1=2V8⚓/Y22⚓

8(4)42567290=(A-A)+(A-A)+(A-A)+(A-J-)677889910,11^1UI1^116778899101.1=610=1151__£=2TT3=22(2)4.7-0.125-18=4.7-(0.125+Q)8=4.37-1=3.37(3)17XQ+Q99=(17+1)XQ9=18x29=14(4)[(3+1.8)xA]x_L616=[4.8Xà]X-L616=4*E16V9⚓/Y22⚓

9_5=I6.ÐÒ(1)a-2-s799,9(4+5)--------(ᓝ)799_9,--------172=7(2)2.54-^-X—84=4Xä4=17(3)(A+A-3)X24368=_LX24+—X24-~X24368=8+20-9=28-9=19(4)2P+[($-0.25)X$]967J6=37.ÐÒ(+Q-§)X246812V10⚓/Y22⚓

10=5x24+QP24--X246812=20+21-10=313.5XA5.5X80%+0.8+5=3.5X().8+5.5X0.8+0.8=0.8X(3.5+5.5+1)=0.8X10=88.ÐÒপ24ᓛ+0.89-0.85=24--0.8+0.895=24+0.89=24.89(2)(ߟ+—)X11+A.111616=_Lx11+J^X11+-5-111616=5+~+Q1616=5+1=6(3)2ç(1-25%)1536=2+[_L+5]15126#2115,10V11⚓/Y22⚓

11=Ï39.ÐÒপᔁ+9ᜓÜ7v15Vl=1xQ9=Q©ফ᧡X2.5X-1-X0.4OI=(QX@)X(2.5X4)87=3x104u~2ব4-1XᵫD=—^-[—x—]51511515=X24628=_§.X24+ëX24-3x24628=20+12-9=23V12⚓/Y22⚓

1210.ÐÒ^-4—+—732—_18,~r-1-4-.-t~2142424232_21=+424253427__2_26+?13913"97+92""ᗎ+ñ=1-213_5_=731.2J_"+3510=§-_£+&"310105_7=3Io50_21=303029=30II.Ð:1
_Lx6+òx3198198=_Lx+W"19881_5_=192
—X34X17X-L1717V13⚓/Y22⚓

13=(*4)X2)=2X217=4(3)(ߟ-—)X1263=§X12-lxi263=10-4=65ভô{ᝅ74Xö+ᵴ4_5175x4308=2+জ242432==ᓛ3(5)2x101-2525=2x(101-1)25=2xioo25=85Q+2"(6)8129øùúV14⚓/Y22⚓

145_.11=836=45.22727223=7212.(1)-1^x2594_1.2-----ᓝ-----53=15.4=A1.X—+—x1577"15*xQ7=1x171=7(3)(2)X1246=2xi2--X1246=9-2=713Ð஺(T)-^—+-^------k--Ḻ12^51512+121215=1+15=115V15⚓/Y22⚓

15ঝ7-7+17-ü17,71071717_7,10X7(1717=7-1=6ঞ%+(0.25ø)=(r°-25)þ3-1----20J7=20@y+0.22+y+l.88=+(0.22+1.88)=1+2.1=3.114.ÐÒ(1)1A-?15515151529=T8K5Q2(2)25123153=QV16⚓/Y22⚓

1615.ÐÒ1"6
2-~KQ776=7-17=607(2)§X[1+(M)]8=Sx[i+_L]812,512X85=~216.ÐÒজ2x6X~94=2x&X694=960=1ঝu+1+-LxZ122127=_Lx2+-Z-x2127127=2x(ߟ+—)712122=7X12=7ঞ++AL25625_8,17,525256V17⚓/Y22⚓

17=1+#6617.ÐÒপ^X*39=&X39xW134=18x3427=2ফ♦-ÿV)_92-1o105=2-25=0(3)£x3X4=i.X(3+4)7=2x77=6=12()=12-1=1118.প630+2708X15=630+15X1518⚓/#22⚓

18=630+225=855(2)5.2-J-^-+4.81313(52+4.8)-(-Z-+&)1313=10-1=9(3)(J-X0.25)X(1.1X40)11=(J_X1.1)X(0.25X40)11=0.7X10=7(4)154-($+%)612=15+$4=12(5)4X(A+A)X747=4X&X7+4X&X747=7+4=111351(6)137X-135X13613619⚓/#22⚓

19135135=137X136136=(137-1)x135136135=136X136=13519.:4(11)xl15154=12115*415(2)7.6X35%+6.5X0.76=0.76X3.5+6.5X0.76=0.76X(3.5+6.5)=0.76X10=7.6(3)—X21+13X.2S.4949=J3.X21+13X-23.4949=JJ.X(21+28)49=13.X4949=1320.(1)23X0.75+27X2+50X75%4=23X2Xy+50x4+27444=(23+27+50)X—420⚓/#22⚓

20=100X04=75(2)+0.125128125.+3+&+&128128+1)=2=1i(3)(A+A)X24XA489_124124-4vXT+?yXT,63=1(4)(42X29+71X42)+35=42X(29+71)4-35=42X1004-35=4200+35=12021⚓/#22⚓

2122⚓/#22⚓