过欠电压提示保护电路课程设计

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1、山西大学课程设计报告课程名称：系部：专业班级：学生姓名：指导教师：完成时间：报告成绩：评阅意见：评阅教师日期16目录1.概述···················································31.1过欠压电路课程设计背景······························31.2过欠压电路课程设计目的······························31.3设计任务与要求······································32.设计内容·····

2、········································42.1分模块电路设计思路··································42.2电源模块的设计······································42.3比较模块的设计······································52.4报警模块的设计16······································61.总电路图·····················

3、·························83.1图像·················································83.2元件清单·············································83.3部分重要原件介绍·····································82.仿真与调试···········································114.1仿真························

4、·························114.2调试·················································124.3结论·················································143.心得体会··············································144.16参考文献··············································151.概述1.1过欠压电路课程设

5、计背景生活中，我们不可避免的要用到要用到各种各样的电气设备。由于电网电压的波动，在较高的电压下很有可能使电气设备受到损坏，而在低压时电气设备不能正常工作。那么，在这样的情况下就需要有一个电压报警指示设备，它可以及时准确地对电网电压进行分段指示并且对过、欠压进行指示报警，从而实现保护电器设备的目的。1.2过欠压电路课程设计目的1.设计一过/欠电压保护提示电路。2.对给定的电路原理框图进行原理图设计，分单元进行设计。对电路参数进行必要的计算，选择元器件参数。3.画出完整的电路原理图。4.对设计的电路进行仿真验证。要求打印出仿真

6、结果。161.3设计任务与要求1.设计一个过欠电压保护电路，当电网交流电压大于250V或小于180V时，经3～4s本装置将切断用电设备的交流供电，并用LED发光警示。2.在电网交流电压恢复正常后，经本装置延时3～5分钟后恢复用电设备的交流供电。3.每一位学生对设计内容都应根据自己所学知识、水平及能力独立完成，不得有雷同。4.写出完整的设计报告。1.设计内容2.1分模块电路设计思路a.电源模块的设计；b.比较模块的设计；c.报警延时模块的设计；2.2电源模块的设计电源设计图：16电源模块采用10TO1的变压器降压，1A／50

7、V桥式整流电路进行整流，RCπ型滤波器进行滤波。当通以220V的交流电压时，经过变压器降压后，电压测量值为21.978V；通过由4个相同型号的二极管组成的桥式整流电路后，得到14.725V直流电压；再通过RCπ型滤波器的滤波、稳压功能，并通过电阻分压,采集到电压比较器变化端,最终得到9.692V的直流电压。2.3比较模块的设计过压比较器同相输入端与欠压比较器反相输入端端接电源部分采集到的电压，过压比较器的反相输入端与欠压比较器的同相输入端则可以端接两种电路，这个部分经过查阅资料与讨论，制定出两套方案：方案一：可以通过电源部

8、分分别将250v与180v所对应的电压测试出来，分别为11.158v与7.89v。然后分别在过压与欠压比较器的相应输入端接入相同电压值的直流电源。方案二：从电源部分的输入端接并联个单相桥式整流电容滤波电路，对其输出电压进行稳压，使其电压值高于或等于250v所对应的电压，这个电压值为基准电压，经过测试后为