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时间:2018-03-15
《2013《电路与电子技术》(双语)试卷b》由会员上传分享,免费在线阅读,更多相关内容在工程资料-天天文库。
1、姓名学号学院专业座位号(密封线内不答题)……………………………………………………密………………………………………………封………………………………………线……………………………………线………………………………………_____________________…诚信应考,考试作弊将带来严重后果!不允许携带任何电子设备华南理工大学期末考试《电路与电子技术》(双语)试卷B考试时间:120minutes注意事项:1.考前请将密封线内填写清楚;2.所有答案请直接答在试卷纸上;3.考试形式:闭卷;4.本试卷共三大题,满分100分,考试
2、时间120分钟。题号IIIIII总分满分204040100得分评卷人I.Shortanswerquestions(20points)1、ExplainthefollowingabbreviationsmeaningKCL:Opamp:BJT:PFPMOS:S2、ForthecircuitinFig.1.2,ifv2=1000i2andi2=5mA,determinevS.Figure1.2(中文版15页)课后习题9看解答3、ReferringtoFig.1.3,Findixifiy=2Aandiz=0A.Fig.1.3
3、(中文版37页)课后习题6看解答4、WithsourcesiAandvBonandvC=0,ix=20AinthecircuitofFig.1.4,withallthreesourceson,ix=12A.FindixiftheonlysourceoperatingisvC.Fig.1.4(中文版101页)课后习题2看解答5、DeterminetheequivalentcapacitanceofthenetworkinFig.1.5ifallcapacitorsare6μF.Figure1.5(中文版134页)课后习题
4、20看解答II.Calculationandanalysisofproblems(40points)6.Whatisthepowerdissipatedinthe2-ΩresistorinFig.2.6.Figure2.67.Findthecurrenti(t)inthecircuitshowninFig.2.7.Figure2.7(a)AnRLCcircuitforwhichthesinusoidalforcedresponsei(t)isdesired.(b)Thefrequency-domainequivalen
5、tofthegivencircuitatω=3000rad/s.(中文版195页)有详解8.FindthenodevoltagesphasorV1andV2inthecircuitshowninFig.2.8.Figure2.8Afrequency-domaincircuitforwhichnodevoltagesV1andV2areidentified.9.ThesourceinFig.2.9isbalancedandexhibits(+)phasesequence.Find(a)IaA;(b)IbB;(c)IcC;
6、Figure2.9(中文版263页)课后习题12看习题解答III.Designandapplicationofquestion(thefollowingquestionsoptional4questions)10.Apower-supplycircuitisneededtodeliver0.1Aandanaverageof15Vtoaload.Theacsourceavailableis110Vrmswithafrequencyof60Hz.Assumethatthefull-wavecircuitofFigure3.
7、10istobeusedwithasmoothingcapacitorinparallelwiththeload.Thepeak-to-peakripplevoltageistobe0.4V.Allow0.7Vforforwarddiodedrop.Findtheturnsrationthatisneededandtheapproximatevalueofthesmoothingcapacitor(Hint:Toachieveanaverageloadvoltageof15Vwitharippleof0.4V,desi
8、gnforapeakloadvoltageof15.2V.).YoumustdrawthediagramofthevoltagewaveformonLoad.CFig3.1011.Designanamplifierforwhichtheoutputvoltageisv0(t)=5v1(t)—2v2(t).Assumethatide
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