山东省青岛胶州市2020-2021学年高二数学下学期期末考试试题(PDF)答案

山东省青岛胶州市2020-2021学年高二数学下学期期末考试试题(PDF)答案

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1、2020-2021学年度第二学期期末学业水平检测高二数学参考答案一、单项选择题:本大题共8小题,每小题5分,共40分。1-8:AACDACCB二、多项选择题:本大题共4小题,每小题5分,共20分。9.BC;10.AC;11.ABC;12.ACD三、填空题:本大题共4个小题,每小题5分,共20分。31913.;14.3;15.xsinx;16.(1);(2);2n124四、解答题:共70分。解答应写出文字说明,证明过程或演算步骤。17.(10分)解:(1)若选择①,由aa51与aaaa20294729a23a217解得:

2、或(由于an1an,舍去)············································2分a17a399a2a1d3a11设公差为d,则,解得·············································4分aa8d17d291所以数列{a}的通项公式为a2n1····························································5分nn若选择②,设公差为d,由S25a,得5a25a;a

3、ad3·································2分513121a12d5a1a11则,解得····································································4分ad3d21所以数列{a}的通项公式为a2n1····························································5分nn若选择③,S1,n1因为an·······················

4、······················································2分SS,n2nn11,n1解得an················································································4分2n1,n2所以数列{a}的通项公式为a2n1····························································5分nn1111(2)由题意得:b()·

5、·································6分n(2n1)(2n1)22n12n1所以Tbbbbn123n11111111(1)···································8分2335572n12n111n(1)·····································································10分22n12n118.(12分)13457解:(1)由已知可得:x4,y

6、4200··································1分5高二数学答案第1页(共5页)(用数学的眼光观察世界,用数学的思维分析世界,用数学的语言描述世界)55222222xiyi103000,xi13457100,···································3分i1i15xiyi5xy1030008400019000所以bˆi1950····································4分52221005420xi5xi1

7、所以aybˆx42009504400,所以yˆbˆxa950x400·················5分当y950x40010000时,x11所以估计第11轮联赛观看比赛的人数y超过10000人··········································6分(2)设甲被选中为事件A,乙被选中为事件B··················································7分2C1015由题意可知:P(A)·························

8、········································8分3C20261C414P(AB)····························

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