第3章习题答案教学文案.doc

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1、__________________________________________________3-11.AX=0048H，AX=0702H2.AX=0059H，AX=0411H，AX=0107H，DL=04H3.AX=0011H，AX=0107H4．AX=005AH，AX=0900H，AX=0908H5.AL=62H6.AX=0248H3-2stacksegmentstack¢stack¢dw32dup(0)stackendsdatasegmentBVARDB99Hdataendscodesegmentbeginprocfara

2、ssumess:stack,cs:code,ds:datapushdssubax,axpushaxmovax,datamovds,axMOVAL,BVARMOVCL,4SHRAL,CLMOVAH,10MULAHANDBVAR,0FHADDBVAR,ALret____________________________________________________________________________________________________beginendpcodeendsendbegin先将2位压缩BCD数转换为非压缩

3、BCD数，再用AAD指令将非压缩BCD数转换为二进制数：MOVAL,BVARMOVAH,ALMOVCL,4SHRAH,CLANDAL,0FHAADMOVBVAR,AL3-3stacksegmentstack¢stack¢dw32dup(0)stackendsdatasegmentW1DW0807HW2DW0609HB3DB2DUP(0)dataendscodesegmentbeginprocfarassumess：stack，cs：code，ds：datapushdssubax，axpushaxmovax，datamovds，axM

4、OVAX,W1；AX=0807HSUBAL,BYTEPTRW2；AL=FEH,CF=1AAS；AL=08H,AH=07HMOVB3,ALMOVAL，AHSUBAL,W2+1MOVB3+1,ALretbeginendpcodeendsendbegin还可以用AAD指令将两个非压缩BCD数转换为二进制数，相减后再用AAM将差转换为非压缩BCD数：MOVAX,W2AADMOVDX,AXMOVAX,W1_______________________________________________________________________

5、_____________________________AADSUBAX,DXAAMMOVBYTEPTRB3,AX3-4stacksegmentstack¢stack¢dw32dup(0)stackendsdatasegmentD1DD06070809HD2DD04050607HOBFDB6DUP(0)dataendscodesegmentbeginprocfarassumess：stack，cs：code，ds：datapushdssubax，axpushaxmovax，datamovds，axMOVSI，0MOVDI,OFFSE

6、TOBF+5MOVBYTEPTR[DI],¢$¢MOVCX,4XORAH,AHAGAIN:MOVAL,BYTEPTRD1[SI]ADDAL,BYTEPTRD2[SI]ADDAL,AHMOVAH，0AAAADDAL,30HDECDIMOV[DI],ALINCSILOOPAGAINANDAH,AHJZN5DECDIMOVBYTEPTR[DI],¢1¢N5:MOVDX,DIMOVAH,9INT21Hretbeginendpcodeendsendbegin3-5stacksegmentstack¢stack¢dw32dup(0)_______

7、_____________________________________________________________________________________________stackendsdatasegmentW1DW8931HW2DW5678HOBFDB6DUP(0)dataendscodesegmentbeginprocfarassumess：stack，cs：code，ds：datapushdssubax，axpushaxmovax，datamovds，axMOVDI,0MOVAL,BYTEPTRW1；AL=31

8、HADDAL,BYTEPTRW2；AL=A9H,CF=0,AF=0DAA；AL=09H,CF=1MOVAH,ALMOVAL,BYTEPTRW1+1；AL=89HADCAL,BYTEPTRW2+1；AL=E0H,CF=0,