最新数值分析作业(C语言编程实现).doc

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1、__________________________________________________#include#includedoublef(doublex){doubleans;ans=exp(x);returnans;}voidmain(){doublea=1,b=3,error=0.0001,t[20][20],h,c;inti,j,k,m,n;h=b-a;t[0][0]=h*(f(a)+f(b))/2;k=1;while(1){t[0][k]=0;m=1;for(j=0;j

2、i=1;i<=m;i++)t[0][k]=t[0][k]+h*f(a+(i-0.5)*h);t[0][k]=(t[0][k]+t[0][k-1])/2;for(j=1;j<=k;j++){c=1;for(n=0;n

3、____________________________________________#include#includedoublef(doublet){doubleans;ans=pow(cos(t),1.0/3);returnans;}voidmain(){doublex=0,eslong=0.000001,x0;intN=20,i;printf("近似初值x0=%lf",x);for(i=0;i

4、#includedoublea=0,b=1,x,y=0,h=0.1,k1,k2,k3,k4;inti,N;doublef(doublet,doubles){doubleans;ans=1+t*t;re

5、turnans;}voidmain(){N=(b-a)/h;x=a;printf("初值为(x0,y0)=(%.8f,%.8f)",x,y);for(i=0;i

6、________________________________________#includevoidmain(){doubledatax[4]={1.2,2.9,4.6,5.8},datay[10]={14.84,33.71,58.36,79.24},l[3],x=1.5,y;inti,j;y=0;for(i=0;i<=3;i++){l[i]=1;for(j=0;j

7、(datax[i]-datax[j])*l[i];y=y+datay[i]*l[i];}printf("f(x)在x=%f处的近似值为:y=%f",x,y);}收集于网络，如有侵权请联系管理员删除__________________________________________________#includevoidmain(){doubledatay[9]={11.7,14.87,21.44,31.39,44.73,61.46,81.57,105.11,131.91};intm=2,i,j,k;doublep,data[9][4

8、],a[3][4],datax[9]={1.2,2.