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1、例1：有一截面为圆环形的输暖管道，如图7—17内外管道半径分别为200mm、800mm，管道内水的半径为80℃，管外表层温度为10℃，求管道内的热应力分布(假设管道内充满水)。材料参数：弹性模量Z—120GPa泊松比v＝0.3线膨胀系数α＝1.3×10^-6m/m℃导热系数k=l.2w／m℃分析：该问题属于轴对称问题。在进行有限元计算时，沿管道横截面取宽度50mm的矩形截面(如图7—18为计算模型，首先采用间接法进行对其进行热应力分析，然后再采用直接法进行分析，最后对二者求解结果进行比较分析。间接法求解：Finish/clear/filname,thermalst
2、ressesinalongcylinder-indirectsolution/prep7Et,1,plane55,,,1!定义轴对称单元Mp,kxx,1,1.2Rectng,0.2,0.8,0,0.05Type,1Lsel,s,line,,1,3,2Lesize,all,,,10Lsel,s,line,,2,4,2Lesize,all,,,2Amesh,1Finish/solu!热传导求解Antype,staticLsel,s,line,,4Nsll,s,1D,all,temp,80Lsel,s,line,,2Nsll,s,1D,all,temp,10Allsel
3、Outpr,basic,allSolvefinish/post1Plnsol,tempFinish/prep7!重新进入前处理，进行热应力耦合分析Etchg,tts!转化单元类型热单元55为结构单元42Keyopt,1,3,1!定义单元关键字选项3为1（轴对称）Keyopt,1,6,1!定义单元关键字选项6为1（无表面输出）Mp,ex,1,120e9!输入材料结构性能参数Mp,alpx,,1.3e-6Mp,nuxy,1,0.3Lsel,s,line,,3Nsll,a,1Cp,7,uy,allallselCp,8,ux,1,14,24Cp,9,ux,2,12,13F
4、inish/solu!热应力求解Antype,staticD,1,uy,,,11!施加位移约束Ldread,temp,,,,,,rthSolveFinish/post1Plnsol,s,xPlnsol,s,yPlnsol,s,zFinish直接法求解：Finish/clear/filname,thermalstressesinalongcylinder-directsolution/prep7Et,1,plane13,,,1!定义热应力耦合单元Keyopt,1,1,4!定义单元关键字选项1=4（ux,uy,temp,az自由度）Keyopt,1,3,1!定义单元关
5、键字选项3=1（轴对称）Mp,ex,1,120e9！输入材料性能参数Mp,nuxy,1,0.3Mp,alpx,,1.3e-6Mp,kxx,1,1.2Rectng,0.2,0.8,0,0.05!创建几何模型Type,1!进行网格划分Lsel,s,line,,1,3,2Lesize,all,,,10Lsel,s,line,,2,4,2Lesize,all,,,2Amesh,1Lsel,s,line,,3Nsll,s,1Cp,7,uy,all!耦合节点AllselCp,8,ux,1,14,24Cp,9,ux,2,12,13Finish/soluAntype,static
6、!热应力耦合求解Lsel,s,line,,4Nsll,s,1D,all,temp,80!施加温度载荷Lsel,s,line,,2Nsll,s,1D,all,temp,10!施加温度载荷AllselD,1,uy,,,11!施加位移约束Outpr,basic,allsolveFinish/post1Plnsol,temp!输出温度场Plnsol,s,x!输出应力场Plnsol,s,yPlnsol,s,zfinish
