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1、ANSYS地震反应谱SRSS分析我在ANSYS中作地震分解反应谱分析，一次X方向，一次Y方向，他们要求是独立互不干扰的，可是采用直进行一次模态分析的话，他生成的*.mcom文件好像是包含了前面的计算结果，命令流如下：!进入PREP7并建模/PREP7B=15!基本尺寸A1=1000!第一个面积A2=1000!第二个面积A3=1000!第三个面积ET,1,beam4!二维杆单元R,1,0.25,0.0052,0.0052,0.5,0.5!以参数形式的实参MP,EX,1,2.0E11!杨氏模量mp,PRXY,1,,
2、0.3mp,dens,1,7.8e3N,1,-B,0,0!定义结点N,2,0,0,0N,3,-B,0,bN,4,0,0,bN,5,-B,0,2*bN,6,0,0,2*bN,7,-B,0,3*bN,8,0,0,3*bE,1,3!定义单元E,2,4E,3,5E,4,6E,3,4E,5,6e,5,7e,6,8e,7,8D,1,ALL,0,,2FINISH!!进入求解器，定义载荷和求解/SOLUD,1,ALL,0,,2!结点UX=UY=0sfbeam,1,1,PRES,100000,sfbeam,3,1,PRES,10
3、0000,sfbeam,7,1,PRES,100000,SOLVEFINISHallselNMODE=10/SOL!*ANTYPE,2!*MSAVE,0!*MODOPT,LANB,NMODEEQSLV,SPARMXPAND,NMODE,,,1LUMPM,0PSTRES,0!*MODOPT,LANB,NMODE,0,0,,OFFSOLVE*DIM,FRE,,NMODE*DO,I,1,NMODE*GET,FRE(I),MODE,I,FREQ!OBTAINMODEFREQENCYFORMODEI*ENDDOFINIS
4、H!地震影响系数grav=9.81tg=0.35amax=0.08c=0.05!*dim,a,,nmode*dim,t,,nmode*do,i,1,nmodet(i)=1.0/fre(i)*enddor=0.9+(0.05-c)/(0.5+5.0*c)p1=0.02+(0.05-c)/8p2=1+(0.05-c)/(0.06+1.7*c)*do,i,1,nmode*if,t(i),ge,0.0,and,t(i),lt,0.1,thena(i)=(0.45+(10.0*p2-4.5)*t(i))*amax*gra
5、v*elseif,t(i),ge,0.1,and,t(i),le,tga(i)=p2*amax*grav*elseif,t(i),gt,tg,and,t(i),le,5*tga(i)=(tg/t(i))**r*p2*amax*grav*elsea(i)=(p2*0.2**r-p1*(t(i)-5*tg))*amax*grav*endif*enddo!!X-方向谱分析SpectrumanalysisalongGlobalX-axisdirection/SOLUANTYPE,SPECTR!Spectrumanaly
6、sisSPOPT,SPRS!SinglepointspectrumSED,1,,!GlobalX-axisasspectrumdirectionSVTYP,2!Seismicaccelerationresponsespectrum!FrequencypointsandSpectrumvaluesforSVvs.freq.tableFREQ,fre(1),fre(2),fre(3),fre(4),fre(5),fre(6),fre(7),fre(8),fre(9)FREQ,fre(10)SV,,a(1),a(2)
7、,a(3),a(4),a(5),a(6),a(7),a(8),a(9)SV,,a(10)FINISH!/SOLU!ANTYPE,MODAL!Mode-frequencyanalysis!EXPASS,ON!MXPAND,nmode,,,YES,0.0!Expandnmodeshapes,calculateelementstresses!SOLVE!FINISH/SOLUANTYPE,SPECTRSRSS,0.0,DISP!SquareRootofSumofSquaresModecombination!withs
8、ignif=0.0anddisplacementsolutionrequestedSOLVEFINISH/POST1SET,LIST/INPUT,,mcom!***************EARTHQUAKEX******************ALLSEL,ALLFINISH!Y-方向谱分析SpectrumanalysisalongGlobalX-axisdirection!!***
