Ch06 Discrete Probability Distributions(商务统计导论-英文版)课件.ppt

Ch06 Discrete Probability Distributions(商务统计导论-英文版)课件.ppt

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1、CHAPTER6 DiscreteProbabilityDistributionstoaccompanyIntroductiontoBusinessStatisticsfourthedition,byRonaldM.WeiersPresentationbyPriscillaChaffe-StengelDonaldN.Stengel©2002TheWadsworthGroupChapter6-LearningObjectivesDistinguishbetweendiscreteandcontinuousran

2、domvariables.DifferentiatebetweenthebinomialandthePoissondiscreteprobabilitydistributionsandtheirapplications.Constructaprobabilitydistributionforadiscreterandomvariable,determineitsmeanandvariance,andspecifytheprobabilitythatadiscreterandomvariablewillhave

3、agivenvalueorvalueinagivenrange.©2002TheWadsworthGroupChapter6-KeyTermsRandomvariablesDiscreteContinuousBernoulliprocessProbabilitydistributionsBinomialdistributionPoissondistribution©2002TheWadsworthGroupDiscretevsContinuousVariablesDiscreteVariables:Canta

4、keononlycertainvaluesalonganintervalthenumberofsalesmadeinaweekthevolumeofmilkboughtatastorethenumberofdefectivepartsContinuousVariables:Cantakeonanyvalueatanypointalonganintervalthedepthatwhichadrillingteamstrikesoilthevolumeofmilkproducedbyacowtheproporti

5、onofdefectiveparts©2002TheWadsworthGroupDescribingtheDistributionforaDiscreteRandomVariableTheprobabilitydistributionforadiscreterandomvariabledefinestheprobabilityofadiscretevaluex.Mean:µ=E(x)=Variance:s2=E[(x–µ)2]=©2002TheWadsworthGroupTheBernoulliProcess

6、, CharacteristicsTherearetwoormoreconsecutivetrials.Ineachtrial,therearejusttwopossibleoutcomes.Thetrialsarestatisticallyindependent.Theprobabilityofsuccessremainsconstanttrial-to-trial.©2002TheWadsworthGroupTheBinomialDistributionThebinomialprobabilitydist

7、ributiondefinestheprobabilityofexactlyxsuccessesinntrialsoftheBernoulliprocess.foreachvalueofx.Mean:µ=E(x)=npVariance:s2=E[(x–µ)2]=np(1–p)©2002TheWadsworthGroupTheBinomialDistribution, AnExampleWorkedbyEquationProblem6.23:AstudybytheInternationalCoffeeAssoc

8、iationfoundthat52%oftheU.S.populationaged10andoverdrinkcoffee.Forarandomlyselectedgroupof4individuals,whatistheprobabilitythat3ofthemarecoffeedrinkers?NumberProportionCoffeedrinkers(x)3.52Noncoffeedrin

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