语言上机部分试题.doc

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1、二级考试（C语言）上机部分试题1．三个数比较大小。（2）#includevoidswap(______1______)//intpa,intpb{/交换两个数的位置/inttemp;temp=pa;pa=pb;pb=temp;}voidmain(){inta,b,c,temp;scanf("%d%d%d",&a,&b,&c);if(a>b)swap(&a,&b);if(b>c)swap(&b,&c);if(______2______)//a>cswap(&a,&c);printf("%d,%d,%d",a,b,c)

2、;}2．表达式求和。#include#includevoidmain(){FILEfp;floatn=1,t=1,pi=0;inti;//从以下开始答题i=1;while(fabs(t)>=1e-6){pi=pi+t;i=-i;n=n+2;t=i/n;}fp=fopen("Design1.dat","w");fprintf(fp,"%.6f",4pi);fclose(fp);}运行结果：3.3．字母后移循环输出。（14）#includevoidmain(){charc;c=getc

3、har();if(______1______)//c>='a'&&c<'v'c=c+5;elseif(c>='v'&&c<='z')______2______//c=c-21;putchar(c);}4．求满足条件的数。#include#includevoidmain(){floaty=1.05;intn=1;FILEp;//以下开始做答while(!(pow(y,n)<1e6&&pow(y,n+1)>1e6))n++;p=fopen("Design2.dat","w");fprintf(p,"%d

4、,%.0f",n,pow(1.05,n));fclose(p);}运行结果：283,5．求满足条件的数。#includevoidmain(){intm=0,t=1,n;while(_____1________);//(scanf("%d",&n),n<=0)while(!(t<=n&&t2>=n)){_____2_____//t=t2;m++;}printf("%d",m);}6．求平面点间的最短距离。#include#include#definelen(x1,y1,x2,y2

5、)sqrt((x1-x2)(x1-x2)+(y1-y2)(y1-y2))voidmain(){FILEp;inti,j;floatc,minc;floatx[]={1.1,3.2,-2.5,5.67,3.42,-4.5,2.54,5.6,0.97,4.65};floaty[]={-6,4.3,4.5,3.67,2.42,2.54,5.6,-0.97,4.65,-3.33};minc=len(x[0],y[0],x[1],y[1]);p=fopen("Design1.dat","w");for(i=0;i<9;i++)for(j=i+

6、1;j<10;j++)if((c=len(x[i],y[i],x[j],y[j]))_______1______//longf(intn);voidmain(){printf("%ld",f(30));}longf(intn){if(______2______)//n==1n==2return1;elsereturnf(n-1)+f(n-2);}运行结

7、果：8．多项式求和问题。#include#includevoidmain(){FILEp;inti;floatx=1.279,t=1,y=0;floata[10]={1.1,3.2,-2.5,5.67,3.42,-4.5,2.54,5.6,0.97,4.65};p=fopen("Design2.dat","w");y=a[0];for(i=1;i<10;i++){t=tx;y=y+ta[i];}fprintf(p,"%f",y);fclose(p);}运行结果：98.9．整数转换为字符串。#incl

8、udevoiditoa(longi,chars){if(i==0)return;/1/s='1'+i%10;//s='0'+i%10itoa(i/10,s-1);}voidmain(){longn;charstr[7