华科周纯杰版c语言问题详解.doc

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1、第三章程序和流程控制1.输入两个整数，输出较大者。#includevoidmain(){inta,b;intmax=0;printf("Pleaseinputtwonumbers:");scanf("%d%d",&a,&b);if(a<=b)max=b;elsemax=a;printf("Thelargernumberis%d",max);}2.有3个整数a，b，c，由键盘输入，输出其中最大的数。#includevoidmain(){inta,b,c,max;printf("Pleaseinputt

2、hreenumbers:");scanf("%d%d%d",&a,&b,&c);if(a>b){if(a>c)max=a;elsemax=c;}else{if(b>c)max=b;elsemax=c;}printf("Thelargestnumberis%d",temp);}3.从1累加到100，用while语句。#include#defineN100voidmain(){inti=1,sum=0;while(i<=N){sum+=i;i++;}printf("sum:%d",sum);}4.已知a1＝10，a2

3、＝－3，an＝3an-1＋an-2，求{a}的前十项。#include#defineN10voidmain(){inta[20]={10,-3};inti=0,m=0;for(i=2;ivoidmain(){inta,te

4、mp;printf("Pleaseinputanumbers:");scanf("%d",&a);temp=a%2;if(temp==0)printf("Thenumber%disaneven!",a);elseprintf("Thenumber%disanoddnumber!",a);}6.已知a1＝8，an＝an-1＋bn，b1＝1，bn＝bn-1＋3，求{a}前10项之和。#include#defineN10voidmain(){inta[N]={8},b[N]={1},i,sum=0;for(i=1;

5、ivoidmain(){floatx,y;printf("Pleaseinputafloatnumberx=:");scanf("%f",&x);printf("x=%f",x);if(x<1)y=x;elseif(x>=10)y=3*

6、x-11;elsey=2*x-1;printf("Thevalueofyis:%.3f",y);}8.给一个不多于5位的的正整数，要求：求出它是几位数，分别打印出每一位数字，最后按照逆序打印各位数字，例如原数为321，应输出为123。#include#defineN99999#defineM5voidmain(){inti,j,k,m,b[M];longinta,temp;printf("Pleaseinputanumber:");scanf("%ld",&a);if(a<0

7、

8、a>N)printf("Error

9、ininputdata!!!");else{temp=a;for(i=0;temp!=0;i++){temp=temp/10;}m=i;printf("Thenumbera=%ldhave%dsinglenumbers",a,m);temp=a;for(j=0;j

10、tteris:");for(j=m-1;j>=0;j--)printf("%dt",b[j]);printf("");printf("Theinvertednumbersare:")