锅炉原理课程设计计算.doc

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1、锅炉原理课程设计一、热力计算（一）燃料燃烧计算1.锅炉参数（1）锅炉蒸发量D30t/h（2）蒸汽压力P0.13MPa（3）蒸汽温度tgr350℃（4）给水温度tgs105℃（5）冷空气温度tlk30℃（6）锅炉排污率P5%2．设计燃料与特性：收到基成分CarHarOarNarSarAarMar（%）56.592.692.930.940.7529.66.5挥发分26.76%收到基低位发热量（热值）21280kj/kg3.锅炉各受热面的漏风系数和过量空气系数锅炉各受热面漏风系数和过量空气系数序号锅炉受热面漏风系数入口处过量空气系数出口处过量空

2、气系数△aaa''1炉膛0.11.31.42凝渣管01.41.43蒸汽过热器0.031.41.434锅炉管束0.051.431.485省煤器0.11.481.586空气预热器0.031.581.614.理论空气量、理论烟气容积的计算理论空气量、理论烟气容积序号名称单位计算公式结果1理论空气量m3/kg0.0889*（Car+0.375*Sar）+0.265*Har-0.0333*Oar5.672三原子气体容积m3/kg0.01866*（Car+0.375*Sar)1.0653理论氮气容积m3/kg0.79Vk0+0.8*Nar/1004.

3、48684理论水蒸气容积m3/kg0.111Har+0.0124*Mar+0.0111*Vk00.2765.各受热面烟道中烟气特性表各受热面烟道中烟气特性表序号名称符号单位炉膛与防渣管过热器锅炉管束省煤器空预器1平均过量空气系数apj1.41.4151.4551.531.5952实际水蒸气容积Vh20m3/kg0.31251480.3138840.3175360.3243820.3303163烟气总容积Vym3/kg8.09588.180858.407658.83299.201454RO2容积份额rR020.1315496920.1301

4、820.126670.1205720.1157435H2O容积份额rH200.0340917510.0337370.0328270.0312470.0299956三原子气体总容积份额rq0.1656414440.1639190.1594980.1518190.145738（三）炉膛的热力计算1.炉膛结构特性（1）标高计算结构名称计算公式标高（mm）A1400+1085tg9°1572B1400+4370tg9°2092C/F2092+1305tg55°3956D7300+1900tg15°7809E7300G3956-920tg20°36

5、21H1600+320tg60°2154I前联箱中心标高1600炉膛结构个点标高示意图（2）炉膛包覆面积1）侧墙A=[(7.300-3.956)+(7.809-3.956)]*0.5*1.900=6.84㎡B=[1.305*(3.956-2.092)]*0.5=1.22㎡C=[(1.572-1.100)+(2.092-1.100)]*0.5*3.285=2.4㎡D=0.595*(3.956-1.100)=1.70㎡E=[(3.956-1.100)+(3.621-1.100)]*0.5*0.920=2.47㎡F=[(2.154-1.100)

6、+(1.600-1.100)]*0.5*0.32=0.25㎡Fcq=6.84+1.22+2.4+1.70+2.47+0.25=14.882）后墙1.572-1.100=0.472mAB=(2.092-1.572)/sin9°=3.32mBC=1.305/sin35°=2.28mCD=7.809-3.956=3.85mFhq=(0.47+3.32+2.28+3.85)*2.72=26.98㎡1）前、顶墙1.600-1.100=0.50mHI=0.32/cos60°=0.64mFG=0.92/cos20°=0.98mGH=3.621-2.15

7、4=1.47mEF=7.30-3.956=3.34mED=1.90/cos15°=1.97mFqq=(0.50+0.64+0.98+1.47+3.34+1.97)*2.72=24.21㎡2）炉壁总面积Fbz=2*14.88+26.98+24.21=80.95㎡(3)炉排有效面积（2.092-1.572）/tg9°=3.28m0.595+0.92+0.32=1.84mR=(3.28+1.84)*2.3=11.78㎡(4)炉膛容积Fcq*2.72=14.88*2.72=40.47㎡(5)炉膛有效辐射受热面1）前顶后水冷壁示意图DE+EF-(4

8、.40-3.956)=1.97+3.34-0.44=4.87m(曝光)（0.64+0.98+1.47+3.34+1.97）-4.87=3.53m（覆盖耐火涂料层）S=170,d=51,e=25