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1、一、用钢筋混凝土简支梁的数值模拟为实例，对ANSYS的使用方法进行说明钢筋混凝土简支梁，尺寸为长2000mm，宽150mm，高300mm。混凝土采用C30，钢筋全部采用HRB335，跨中集中荷载P作用于一刚性垫板上，垫板尺寸为长150mm，宽100mm。建立分离式有限元模型，混凝土采用SOLID65单元，钢筋采用LINK8单元，不考虑钢筋和混凝土之间的粘结滑移。创建分离式模型时，将几何实体以钢筋位置切开，划分网格时将实体的边线定义为钢筋即可。加载点以均布荷载近似代替钢垫板，支座处则采用线约束和点约束相结合。单元尺寸以50mm左右为宜。二、命令流!钢
2、筋混凝土简支梁数值分析!分离式模型FINISH/CLEAR/PREP7!1.定义单元与材料属性ET,1,SOLID65,,,,,,,1ET,2,LINK8MP,EX,1,13585!混凝土材料的初始弹模以及泊松比MP,PRXY,1,0.2FC=14.3!混凝土单轴抗压强度和单轴抗拉强度FT=1.43TB,CONCR,1TBDATA,,0.5,0.95,FT,-1!定义混凝土材料及相关参数，关闭压碎TB,MISO,1,,11!定义混凝土应力应变曲线，用MISO模型TBPT,,0.0002,FC*0.19TBPT,,0.0004,FC*0.36TBPT
3、,,0.0006,FC*0.51TBPT,,0.0008,FC*0.64TBPT,,0.0010,FC*0.75TBPT,,0.0012,FC*0.84TBPT,,0.0014,FC*0.91TBPT,,0.0016,FC*0.96TBPT,,0.0018,FC*0.99TBPT,,0.002,FCTBPT,,0.0033,FC*0.85MP,EX,2,2.0E5!钢筋材料的初始弹模以及泊松比MP,PRXY,2,0.3TB,BISO,2TBDATA,,300,0!钢筋的应力应变关系，用BISO模型PI=ACOS(-1)R,1R,2,0.25*PI*
4、22*22R,3,0.25*PI*10*10TBPLOT,MISO,1!混凝土材料的数据表绘图TBPLOT,BISO,2!钢筋材料的数据表绘图!2.创建几何模型BLC4,,,150,300,2000*DO,I,1,19!切出箍筋位置WPOFF,,,100VSBW,ALL*ENDDOWPCSYS,-1WPOFF,,,950!切出拟加载面VSBW,ALLWPOFF,,,100VSBW,ALLWPCSYS,-1WPROTA,,-90WPOFF,,,30VSBW,ALLWPOFF,,,240VSBW,ALLWPCSYS,-1WPOFF,30WPROTA,,
5、,90VSBW,ALLWPOFF,,,45VSBW,ALLWPOFF,,,45VSBW,ALLWPCSYS,-1!3.划分钢筋网格ELEMSIZ=50!网格尺寸变量，设置为50mmLSEL,S,LOC,X,30LSEL,R,LOC,Y,30LATT,2,2,2LESIZE,ALL,ELEMSIZLMESH,ALLLSEL,S,LOC,X,75LSEL,R,LOC,Y,30LATT,2,2,2LESIZE,ALL,ELEMSIZLMESH,ALLLSEL,S,LOC,X,120LSEL,R,LOC,Y,30LATT,2,2,2LESIZE,ALL,E
6、LEMSIZLMESH,ALLLSEL,S,LOC,X,30LSEL,R,LOC,Y,270LATT,2,3,2LESIZE,ALL,ELEMSIZLMESH,ALLLSEL,S,LOC,X,120LSEL,R,LOC,Y,270LATT,2,3,2LESIZE,ALL,ELEMSIZLMESH,ALLLSEL,S,TAN1,ZLSEL,R,LOC,Y,30,270LSEL,R,LOC,X,30,120LSEL,U,LOC,X,75LSEL,U,LOC,Z,0LSEL,U,LOC,Z,2000LSEL,U,LOC,Z,950LSEL,U,LOC,Z
7、,1050LATT,2,3,2LESIZE,ALL,ELEMSIZLMESH,ALLLSEL,ALL!4.划分混凝土网格VATT,1,1,1MSHKEY,1ESIZE,ELEMSIZVMESH,ALLALLSEL,ALL!5.施加荷载和约束LSEL,S,LOC,Y,0LSEL,R,LOC,Z,100DL,ALL,,UYLSEL,S,LOC,Y,0LSEL,R,LOC,Z,1900DL,ALL,,UYDK,KP(0,0,100),UX,,,,UZDK,KP(0,0,1900),UXP0=180000Q0=P0/150/100ASEL,S,LOC,Z,
8、950,1050ASEL,R,LOC,Y,300SFA,ALL,1,PRES,Q0ALLSEL,ALLFINISH!6.求
