试验一--MATLAB-语言基础实验.doc

《试验一--MATLAB-语言基础实验.doc》由会员上传分享，免费在线阅读，更多相关内容在行业资料-天天文库。

1、试验一MATLAB语言基础实验（软件仿真）一、MATLAB的基本操作1、实验目的（1）学习了解MATLAB语言环境（2）练习MATLAB命令的基本操作（3）练习m文件的基本操作2、实验内容（练习MATLAB命令的基本操作中的内容）1）常规矩阵输入>>a=[123]a=123>>a=[1;2;3]a=123>>b=[125]b=125>>b=[125];>>aa=123>>a'ans=123>>bb=125>>b'ans=125>>c=a*bc=12524103615>>c=a*b'???Errorusing==>*

2、Innermatrixdimensionsmustagree.>>a=[123;456;780]a=123456780>>a^2ans=303615668142395469>>a^0.5ans=0.5977+0.7678i0.7519+0.0979i0.5200-0.4680i1.4102+0.1013i1.7741+0.6326i1.2271-0.7467i1.2757-1.0289i1.6049-1.0272i1.1100+1.6175i2）作循环命令程序>>makesum=0;fori=1:1:100make

3、sum=makesum+i;end>>makesummakesum=50503）分别执行下列命令>>a=[123;456;780]a=123456780>>poly(a)ans=1.0000-6.0000-72.0000-27.0000>>rank(a)ans=3>>det(a)ans=27>>trace(a)ans=6>>inv(a)ans=-1.77780.8889-0.11111.5556-0.77780.2222-0.11110.2222-0.1111>>eig(a)ans=12.1229-0.3884-5

4、.73454）练习m文件的基本操作>>penddemo倒立摆控制系统：二、MATLAB的数值运算1、实验目的（1）学习MATLAB语言的基本矩阵运算（2）学习MATLAB语言的点运算（3）学习复杂运算2、实验内容（1）基本矩阵运算1）创建数值矩阵>>a=[123;456;789];>>aa=123456789>>a(3,2)ans=8>>a(:,1)ans=147>>t=0:10t=Columns1through100123456789Column1110>>u=0:0.1:10u=Columns1through6

5、00.10000.20000.30000.40000.5000Columns7through120.60000.70000.80000.90001.00001.1000Columns13through181.20001.30001.40001.50001.60001.7000Columns19through241.80001.90002.00002.10002.20002.3000Columns25through302.40002.50002.60002.70002.80002.9000Columns31throu

6、gh363.00003.10003.20003.30003.40003.5000Columns37through423.60003.70003.80003.90004.00004.1000Columns43through484.20004.30004.40004.50004.60004.7000Columns49through544.80004.90005.00005.10005.20005.3000Columns55through605.40005.50005.60005.70005.80005.9000Colu

7、mns61through666.00006.10006.20006.30006.40006.5000Columns67through726.60006.70006.80006.90007.00007.1000Columns73through787.20007.30007.40007.50007.60007.7000Columns79through847.80007.90008.00008.10008.20008.3000Columns85through908.40008.50008.60008.70008.8000

8、8.9000Columns91through969.00009.10009.20009.30009.40009.5000Columns97through1019.60009.70009.80009.900010.0000>>a(:,3)=[2;3;4]a=122453784>>b=[11+2i;3+4i3]b=1.00001.0000+2.0000i3.00