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1、四、阅读下列程序，注释并填写指令执行后的结果（每题10分）1、ORG0LJMPSTART；跳转到（PC）＝0030H处ORG30HSTART：MOVR0,#20H；＃20H－>R0(R0)=20HMOVR1,#30H；#30H－>R1(R1)=30HMOVA,R0；(R0)－>A(A)=20HADDA,#36H；(A)+#36H－>A(A)=56HMOVP1,A；(A)－>P1(P1)=56HINCR0；(R0)+1－>R0(R0)=21HINCR1；(R1)+1－>R0(R1)=31HANLA,R1；(A)&(R
2、1)－>A(A)=10HSWAPA；累加器A的高低4位交换(A)=01HPUSHACC；累加器A内容压栈MOVP1,A；(A)－>P1(P1)=01HPOPB；堆栈内容出栈到B寄存器(B)=01HMOVR0,A；(A)－>R0(R0)=01HMOVDPTR，＃2200H；#2200H－>DPTR(DPTR)=2200HSETBC；1－>Cy(Cy)=1ADDCA,＃0；(A)+0+(Cy)－>A(A)=02HMOVX@DPTR,A；(A)－>(DPTR)(2200H)=02HEND(R0)=01H(R1)=31H(
3、P1)=01H(B)=01H(2200H)=02H2、ORG0LJMPSTART；跳转到(PC)=0030H处ORG30HSTART：MOVSP,#50H；#50H－>SP(SP)=50H第57页共57页MOVR2,#10H；#10H－>R2(R2)=10HMOVDPTR,#3000H；#3000H－>DPTR(DPTR)=3000HCRLA；0－>A(A)=0LOOP：MOVX@DPTR,A；(A)－>(DPTR)INCDPTR；(DPTR)+1－>DPTRDJNZR2,LOOP；(R2)-1－>R2若(R2)不
4、等于零则转移到LOOP处INCDPH；(DPH)+1－>DPH(DPH)=31H(R2)=00H(DPL)=10HINCDPH；(DPH)+1－>DPH(DPH)=32HMOV20H,#36H；#36H－>(20H)(20H)=36HSETB00H；位地址00H置120H.0=1(20H)=37HMOVA,20H；(20H)－>A(A)=37HMOVX@DPTR,A；(A)－>(DPTR)(DPTR)=3210H(3210H)=37HINCA；(A)+1－>A(A)=38HINCA；(A)+1－>A(A)=39HP
5、USHACC；累加器A内容压栈(SP)=51HXCHA,R2；累加器A的内容与R2内容互换(A)=00H(R2)=39HPOPDPH；堆栈内容弹到DPH(DPH)=39HADDA,#55H；(A)+#55H－>A(A)=55HPUSHACC；累加器A内容压栈END(A)=55H(R2)=39H(20H)=37H(DPTR)=3910H(SP)=51H3、ORG0LJMPSTART；跳转到(PC)=0030H处ORG30HSTART：MOVR0,#30H；#30H－>R0(R0)=30HMOVA,#12H；#12H－
6、>A(A)=12HSETBC；(Cy)=1ADDCA,R0；(A)+(R0)+Cy－>A(A)=43HMOV@R0,A；(A)－>(R0)(30H)=43H第57页共57页SWAPA；累加器A高低4位交换(A)=34HINCA；(A)+1－>A(A)=35HMOVDPTR,#2000H；#2000H－>DPTR(DPTR)=2000HINCDPH；(DPH)+1－>DPH(DPH)=21HMOVP1,A；(A)－>P1(P1)=35HINCA；(A)+1－>A(A)=36HMOVX@DPTR,A；(A)－>(DPT
7、R)(2100H)=36HXCHA,R0；(A)óR0(A)=30H(R0)=36HRLA；累加器A内容循环左移(A)=60HPUSHACC；累加器A的内容入栈RLA；累加器A内容循环左移(A)=0C0HPOPACC；堆栈内容弹出到累加器A(A)=60HEND(A)=60H(R0)=36H(DPTR)=2100H(P1)=35H(30H)=43H4、ORG0LJMPSTART；跳转到(PC)=0030H处ORG30HSTART：MOVSP,#50H；#50H－>SP(SP)=50HMOVDPTR,#3000H；#3
8、000H－>DPTR(DPTR)=3000HMOVR0,#20H；#20H－>R0(R0)=20HMOVA,#23H；#23H－>A(A)=23HMOVR2,#0FH；#0FH－>R2(R2)=0FHSETB01H；置位20H.1(20H.1)=1SETBC；置位Cy(Cy)=1ADDCA,@R0；(A)+((R0))+Cy－>A(A)=26HINCR0；(
