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时间:2020-03-26
《nBA与HEA的共聚合及其竞聚率测定.pdf》由会员上传分享,免费在线阅读,更多相关内容在行业资料-天天文库。
1、92第41卷,第9期工程塑料应用Vo1.41.NO.92013年9月ENGINEERINGPLASTICSAPPLICATIONSep.2013doi:lO.3969/].issn.1001-3539.2013.09.020nBA与HEA的共聚合及其竞聚率测定邓双辉,叶沪平,姜丹凤,范传杰,林群芳,赵婧婧,周晓东(1.华东理工大学化学工程联合国家重点实验室,上海200237;2.上海通用识别技术研究所,上海201112;3.华东理工大学材料科学与工程学院,上海200237)摘要:采用原子转移自由基聚合一步加料的方法,以。c.溴代异丁酸乙酯为引
2、发荆,溴化亚铜/N,N,N,N,N五甲基二亚乙基三胺为催化体系,环己酮为溶剂,于70qC下进行了丙烯酸正丁酯(nBA)与丙烯酸羟乙酯(HEA)的共聚合反应。采用傅立叶变换红外光谱、核磁共振氢谱、凝胶渗透色谱和动态力学分析等对共聚物进行了表征和测试,证实了无规共聚物PnBA—co.PHEA的成功合成,且其分子量分布较窄(<2.0),只具有一个玻璃化转变温度,其值为一27.35℃。通过改变单体投料比来分析共聚物组成,然后由拓展的Kelen—Tfidos法计算了两种单体的竞聚率分别为rHE^=l。505和‘lB^=0。894,表明PnBA-coPH
3、EA确为无规共聚物。关键词:丙烯酸正丁酯;丙烯酸羟乙酯;原子转移自由基聚合法;竞聚率中图分类号:O631.5文献标识码:A文章编号:1001.3539(2013)09—0092-04CopolymerizationandReactivityRatioMeasurementofn—ButylacrylateandHydroxyethylAcrylateDengShuanghui,5reHuping,JiangDanfeng,FanChuanjie,LinQunfang,ZhaoJingjing,ZhouXiaodongf1.StateKeyLa
4、boratoryofChemicalEngineering,EastChinaUniversityofScienceandTechnology,Shanghai200237,China;2.ShanghaiGeneralRecognitionTechnologyInstitute,Shanghai201112,China;3.SchoolofMaterialScienceandEngineering,EastChinaUniversityofScienceandTechnology,Shanghai200237,China)Abstract:
5、Atomtransferradicalpolymerization(ATRP1wasemployedtopreparethecopolymerofn·butylacrylate(nBA)andhydroxyethylacrylatefHEA).Thecopolymerizationreactionswerecarriedoutat70℃withethyl2-bromoisobutyrateastheinitiator,copperbromide/N,N,N,N,N"-pentamethyldi—ethylenetriamineasthecat
6、alystsystem,andthecyclohexanoneasthesolvent.Thecopolymerproductswerecharacterizedbyfouriertransforminfraredspectroscopy,hydrogen-nuclearmagneticresonance,gelpermeationchromatographyanddynamicmechanicalanalysis.TheresultsshowthattherandomcopolymerPnBA—co—PGMAissuccessfullysy
7、nthesizedviaATRP,itsmolecularweightdistributionisverynarrowandithasonlyaglasstransitiontemperaturewhichis-27.35qC.ThroughchangingthemonomerfeedingratioofHEAandnBA,thecompositionofthecopolymerwasanalyzed.Finally,usingtheextendedKelen—Tfidosmethodfromthecopolymercompositionda
8、tum,themonomerreactivityratioswerecalculatedtobeEA=1.505andrnBA=0.894respectively,
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