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1、电路理论基础习题答案第一章1-1.(a),(b)吸收1()W；(c)、(d)发出10W.l-2.-lA;-10V;-lA;-4mW.1-3.-0.5A;-6V;_15JV;1.75cos2/A;3G;1.8cos'2rW,1-4.h=104/;w=15mA10-104z;z/=2000/;h=-104mWAp1001-6.0.1A.1-704msz；A24ms2500.4
2、丁.75.251.251■-0.4
3、—(d)",100uN8020Ams(f)10010f,ms(e)8.2//F;4//C;0;4“J.9.9・
4、6V,0・192W,1.152mJ;16V,0,3.2mJ.6f10.1—G°A,r>o取s.11.3H,6(l-r)2J;3mH,6(1-1000t)2mJ;12.0.4F,0.13.供12W;吸40W;吸2W;(2V)供26W,(5A)吸10W.14.-40V,-1mA;-50V,-1mA;50V,1mA.15.0.5A,1W;2A,4W;-1A,-2W;1A,2W.16.10V,50W;50V,250W;—3V,—15W;2V,1OW.17.(a)2V;R耗4/3W;〃s:-2/3W,Is:2W;(b)-3V;
5、R耗3W;Us:-2W,/s:5W;(c)2V,-3V;R耗4W;3WQs:2W,/s:5W;1-18.24V,发72W;3A,吸15W;24V6电压源;3AI电流源或5/3Q电阻.1-19.OQs/RlQs;Us/R,Us/R,-Us心/川•1-20.6A,4A,2A,1A,4A;8V,-10V,18V.1-21.K打开：(a)0,0,0;(b)10V,0,10V;(c)10V,10V,0;K闭合:(a)10V,4V,6V;(b)4V,4V,0;(c)4V,0,4V;1-22.2V;7V;3-25V;2V.1-
6、23.100・A*i10Idt123JP(W)()2"s)1-24.14V.1-25.-2.333V,l・333A;0・4V,0・8A.1-26.80V.1-26(习题册)(G：12V;2A;-48W.(b):-6V;3A;-54W第二章2-1.2.50;1.6/?;8/3Q;0.5/?;4O;1.4480;./?/8;1.5Q;1.269Q;40Q;14Q.2-2.P低=484W,P,=484x4W.2-3.1.6180.2-4.400V;363.6V;/a=5A,电流表及滑线电阻损坏.2-6.5kQ.2-7.0.
7、750.2-8.R1=38K£l,R2=10/3KQ2-9.10/3A,1.20;一5V,如；8V,4O;0.5A,30/l1Q.2-10.1A,2Q;5V,2Q;2A;2A;2A,6d2-11.-75mA;-0.5A.2-12.60;7.50;0;2.10.2-13.4Q;1.5Q;2kQ.2-14.1.6V,-24V2・15.(习题册)2.5W2-15.(a)2A;(b)-2Al,吸20W.2-16.2-17.3A.2-18.7.33V.2-19.85.76W.2-20.IV,4W.2-21.64W.2・22.电
8、压源发50W,电流源发1050W2-232-24.7V,3A;8V,1A.2-25.4V,2.5V,2V.2-26.202-27.60V.2-28.4.5V.2-29.-18V.2-29(习题册)：4W;48W2・30.原构成无解的矛盾方程纟R;(改麻)4V,10V.2-312-32.2.5A2-33.3.33kq,50kq.2-34加法运算w0=-(wn+uj2+%3)2-35.R3(7?i+/?2)isIR•2・36.可证明/l=~^s/&.2-37.-2;4.2-3811/2探第三章3-1.44V;-1+9=
9、8V;6+9=15V;sinr+0・2「V.3-2.155V.3-3.190mA.3-4.1.8倍.3-5.左供52W,右供78W.3-6.lg;1A;0.75A.3-7.3A;1.33mA;1.5mA;2/3A;2A.3-8.20V,-75.38V.3・8（习题册）：0.2Q3・9（习题册）：2W3-9.-1A;2A;1A.3-10.5V,20;;—2V,4q.3-12.4.6（；.3-13.2V;0.5A.3-14.10V,5kg.3-15.3-16.22.5V3-17.4/3（；,75W;4/3q,4.69W.
10、3-18.3q,529/12W.;lq,2.25W.3-193-20.50（；.3-21.0.2A.3-22.1A.3-23.1.6V.3-24.4A;3-25.23.6V;5A,10V.3-26.3-274V3-28.探第四章4-1.141.1V,100V,50Hz,0.02s,0°,-120°;120°.4-2.7.07/0°A,1/-45
